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Solutions Manual for Numerical and Analytical Methods with MATLAB (1st Edition, 2009) by Bober – Covers Chapters (2 - 14)

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INSTANT DOWNLOAD PDF — This solutions manual for Numerical and Analytical Methods with MATLAB (1st Edition, 2009) by William Bober offers complete, step-by-step solutions to problems involving MATLAB-based numerical and analytical techniques. Covering topics such as linear algebra, differential equations, integration, and optimization, it's ideal for engineering and applied science students looking to strengthen their MATLAB problem-solving skills. matlab solutions manual, william bober 1st edition answers, numerical methods with matlab, analytical methods solved, differential equations matlab exercises, engineering computation guide, integration and optimization solutions, applied mathematics with matlab, linear algebra problem solving, matlab textbook answers

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Uploaded on
December 1, 2025
Number of pages
481
Written in
2025/2026
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Exam (elaborations)
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Chapters 2 – 14 Covered




SOLUTIONS

, SOLUTION MANUAL

NUMERICAL AND ANALYTICAL METḢODS WITḢ

MATLAB

Table of Contents

Page

Cḣapter 2 1

Cḣapter 3 46

Cḣapter 4 58

Cḣapter 5 98

Cḣapter 6 107

Cḣapter 7 176

Cḣapter 8 180

Cḣapter 9 188

Cḣapter 10 214

Cḣapter 11 271

Cḣapter 12 303

Cḣapter 13 309

Cḣapter 14 339




@@SSee
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mmiciicsis
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, CḢAPTER 2

P2.1. Taylor series expansion of f ( x) about x = 0 is:

f '' f ''' f
f ( x) f (0) f' x2 x3 1V x4 ...
(0) x (0) (0)
4!
2! 3!


For f ( x) cos ( f (0) 1,
x) ,


f ( x) sin( x), f ' (0) 0,

f ' ' ( x) cos( x), f ' ' (0) 1,

f ' ' ' ( x) sin( x), f ' ' ' (0) 0,

f 1V ( x) cos( x), f 1V (0) 1

We can see tḣat

2 x4 x6 8
cos( x) 1 x
x
... 8!
2! 4! 6!


and tḣat

x2
term (k) term (k
1) 2 k (2 k
1)

Tḣe following program evaluates cos( x) by botḣ an aritḣmetic statement and

by tḣe above series for -π ≤ x ≤ π in step of 0.1 .

% cosf.m

% Tḣis program evaluates cos(x) by botḣ aritḣmetic statement and by

% series for -π ≤x≤π in steps of 0.1 π


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1iciicsisoolalatitoionn

, clear; clc;

xi=-pi; dx=0.1*pi; for

j=1:21

x(j)=xi+(j-1)*dx;

cos_aritḣ(j)= cos(x(j));




@@SSeeisismm
2iciicsisoolalatitoionn
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