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CHEM 210 Module 2 Exam (Portage Learning 2025/2026) — 30 High-Level Practice Questions with 100% Correct Answers

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CHEM 210 Module 2 Exam (Portage Learning 2025/2026) — 30 High-Level Practice Questions with 100% Correct Answers

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Institution
CHEM 210 Module 2
Course
CHEM 210 Module 2

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Uploaded on
November 30, 2025
Number of pages
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Written in
2025/2026
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CHEM 210 Module 2 Exam (Portage Learning
2025/2026) — 30 High-Level Practice Questions with
100% Correct Answers

1.​ How many protons, neutrons, and electrons are in a neutral atom of ⁶⁵₂₉Cu?


A. 29 p⁺, 34 n°, 29 e⁻


B. 34 p⁺, 29 n°, 34 e⁻


C. 29 p⁺, 35 n°, 29 e⁻


D. 30 p⁺, 35 n°, 30 e⁻


Correct Answer: A


Explanation: Atomic number (29) = protons = electrons in a neutral atom. Mass number
(65) – atomic number = 65 – 29 = 34 neutrons.


2.​ Which quantum-number set is valid for the last electron added to a neutral
phosphorus atom (Z = 15)?


A. n = 3, l = 2, m = 0, mₛ = +½


B. n = 3, l = 1, m = –1, mₛ = +½

,C. n = 2, l = 1, m = 0, mₛ = –½


D. n = 4, l = 0, m = 0, mₛ = +½


Correct Answer: B


Explanation: Phosphorus ends with 3p³; the third 3p electron enters one of the degenerate
3p orbitals with m = –1, 0, or +1 and parallel spin (Hund’s rule). All values are within
allowed ranges.


3.​ Arrange the following species in order of increasing first-ionization energy: Mg,
Al, Na, Si.


A. Na < Mg < Al < Si


B. Mg < Na < Al < Si


C. Na < Al < Mg < Si


D. Si < Al < Mg < Na


Correct Answer: A


Explanation: Ionization energy increases left-to-right across a period; Na (period 3, group
1) is lowest, followed by Mg, Al, and Si highest.


4.​ Which element has the largest atomic radius among S, Cl, Se, and Br?

, A. S


B. Cl


C. Se


D. Br


Correct Answer: D


Explanation: Atomic radius increases down a group and left-to-right across a period. Br is
below Cl in group 17 and below Se in period 4, giving it the largest radius.


5.​ How many unpaired electrons are present in a ground-state sulfur atom (Z = 16)?


A. 0


B. 1


C. 2


D. 3


Correct Answer: C


Explanation: Sulfur’s configuration is 1s² 2s² 2p⁶ 3s² 3p⁴; the 3p subshell contains two
unpaired electrons (Hund’s rule).

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