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Exam (elaborations)

CPSC110 Psets Solution

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This is the correct solution for the pset that you are going to be given as a student who is/will be taking cpsc110.

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;​; DO NOT PUT ANYTHING PERSONALLY IDENTIFYING BEYOND YOUR CWL IN THIS​
​FILE.​
​;; YOUR CWLs WILL BE SUFFICIENT TO IDENTIFY YOU.​
​;;​
​(require spd/tags)​
​(require 2htdp/image)​

​(@assignment psets/pset-01);Do not edit or remove this tag​


(​ @problem 1)​
​;;​
​;; Write the BSL expression that most clearly represents the following​
​;; arithmetic expression:​
​;;​
​;; 3^2 + 6 * (6 - 10) / 3​
​;;​
​;; which equals 1​
​;;​
​;; There is a single BSL expression that both produces the correct result,​
​;; and most closely matches the structure of the equation given above.​
​;; Although 1 is an expression that evaluates to 1, that is not the​
​;; correct answer, because it doesn't show the structure of the expression​
​;; above.​
​;;​

​(+ (sqr 3) (/ (* 6 (- 6 10)) 3))​




(​ @problem 2)​
​;;​
​;; Given the definitions below (LOWER, UPPER and foo),​
​;; write the step-by-step evaluation of the following expression:​
​;;​
​;; (foo (* 3 4) (+ 0 2))​
​;;​
​;; Be sure to show every intermediate evaluation step, including the original​
​;; expression and the final result. The steps should NOT be in comments.​
​;;​
​;; Stepping questions like this one have only one correct answer. The goal​
​;; of this problem is to assess whether you have learned the exact BSL step​
​;; by step evaluation rules; not whether you can figure out the final​
​;; result of an expression.​
​;;​

​(define LOWER 10)​

, ​(define UPPER 20)​

​(define (foo x y)​
​(if (and (> x LOWER) (< x UPPER))​
​(- x (* y 2))​
​(+ x (* y 3))))​

​(foo (* 3 4) (+ 0 2))​

​(foo 12 (+ 0 2))​

​(foo 12 2)​

​(if (and (> 12 LOWER) (< 12 UPPER))​
​(- 12 (* 2 2))​
​(+ 12 (* 2 3)))​

​(if (and (> 12 10) (< 12 UPPER))​
​(- 12 (* 2 2))​
​(+ 12 (* 2 3)))​

​(if (and true (< 12 UPPER))​
​(- 12 (* 2 2))​
​(+ 12 (* 2 3)))​

​(if (and true (< 12 20))​
​(- 12 (* 2 2))​
​(+ 12 (* 2 3)))​

​(if (and true true)​
​(- 12 (* 2 2))​
​(+ 12 (* 2 3)))​

​(if true​
​(- 12 (* 2 2))​
​(+ 12 (* 2 3)))​

​(- 12 (* 2 2))​

​(- 12 4)​

​8​




(​ @problem 3)​
​;;​
​;; Skye has written the following expression, and expects it to produce​

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