,
,Chapter 1: Arithmetic Needed For Dosage
MULTIPLE CHOICE
1. A Patient/Client Was Instructed To Drink 25 Oz Of Water Within 2 Hours But Was Only
Able To Drink 15 Oz. What Portion Of The Water Remained?
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A
Feedback: Subtract The Quantity Of Water The Client Drank (15 Oz) From The Total
Available Quantity (25 Oz): 10 Oz Remain. To Determine The Portion Of The Water That
Remains, Create A Fraction By Dividing 10 Oz (Remaining Portion) By 25 Oz (Total Portion).
Therefore, 10 Divided By 25 = 10/25. To Reduce Fractions, Find The Largest Number That
Can Be Divided Evenly Into The Numerator And The Denominator
(5). Ten Divided By 5 (10/5) = 2; 25/5 = 5. The Fraction 10/25 Can Be Reduced To Its Lowest
Terms Of 2/5.
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care And
Comfort Cognitive Level: Apply
Difficulty: Moderate
Page And Header: 2, Dividing Whole Numbers; 3, Fractions
Integrated Process: Teaching/Learning
Objective: 1, 2
2. A Patient/Client Was Prescribed 240 w
mwlwo.F Etnbsusremb.Ywmsouth As A Supplement But
Consumed Only 100 Ml. What Portion Of The Ensure Remained?
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B
Feedback: Subtract The Quantity Of Ensure The Client Consumed (100 Ml) From The Total
Available Quantity (240 Ml): 140 Ml Remain. To Determine The Portion Of The Ensure That
Remains, Create A Fraction By Dividing 140 Ml (Remaining Portion) By 240 Ml (Total
Portion). Therefore, 140 Divided By 240 = 7/12. To Reduce Fractions, Find The Largest
Number That Can Be Divided Evenly Into The Numerator And The Denominator (20); 140
Divided By 20 (140/20) = 7; 240/20 = 12. The Fraction 140/240 Can Be Reduced To Its
Lowest Terms Of 7/12.
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care And
Comfort Cognitive Level: Apply
Difficulty: Moderate
Page And Header: 2, Dividing Whole Numbers; 3, Fractions
Integrated Process: Teaching/Learning
Objective: 1, 2
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, 3. A Patient/Client Consumed Oz. Of Coffee, 2/3 Oz. Of Ice Cream, And Oz. Of Beef
Broth. What Is The Total Number Of Ounces Consumed That Should Be Documented For
The Patient/Client?
a. 3 3/4
b. 4 5/12
c. 4 2/3
d. 4 4/9
ANS: B
Feedback: Add The Amount Of Ounces Consumed. First, Change Any Mixed Number To A
Fraction By Multiplying The Whole Number By The Denominator And Then Adding That
Total To The Numerator. For The Coffee, 4 2 = 8 + 1 = 9/4; For The Beef Broth, 2 1
= 2 + 1 = 3/2. Then Add: 9/4 + 2/3 (Ice Cream) + 3/2. When Fractions Have Different
Denominators, Find The Least Common Denominator (LCD). For 2, 3, And 4, The LCD =
12. Rewrite Each Fraction Using The LCD; Divide The LCD By The Denominator Of Each
Fraction And Then Multiply That Result By The Numerator Of The Fraction. The New
Fractions To Be Added Are 27/12 (Coffee), 8/12 (Ice Cream), And 18/12 (Beef Broth). After
Conversion Of The Fractions, The Numerators Are Added Together And The Fraction Is
Reduced To The Lowest Terms.
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care And
Comfort Cognitive Level: Analyze
Difficulty: Difficult
Page And Header: 2, Multiplying Whole Numbers; 3,
Fractions Integrated Process: Communication And
Documentation Objective: 1, 2
4. A Coffee Cup Holds 180 Ml. The Patient/Client Drank 2? Cups Of Coffee. How Many
Milliliters Would
The Nurse Document As
Consumed?
a. 360
b. 420
c. 510
d. 600
ANS: B
Feedback: The Coffee Cup Holds 180 Ml. The Client Drank 2? Cups. To Estimate The Total
Number Of Milliliters Consumed, Multiply 180 7/3 ( ). When A Mixed Number Is
Present, Change It To An Improper Fraction By Multiplying The Whole Number By The
Denominator And Then Adding That Total To
The Numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 Ml × 7/3 = 420 Ml (180 ÷ 3 = 60 × 7 =
420).
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care And
Comfort Cognitive Level: Analyze
Difficulty: Difficult
Page And Header: 2, Multiplying Whole Numbers; 3,
Fractions Integrated Process: Communication And
Documentation Objective: 1, 2
5. A Patient/Client Weighed 48.52 Kg On Admission And Now Weighs 50.4 Kg. How Many
Kilograms Were Gained Since Admission?
a. 0.78
2|Pag e
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,Chapter 1: Arithmetic Needed For Dosage
MULTIPLE CHOICE
1. A Patient/Client Was Instructed To Drink 25 Oz Of Water Within 2 Hours But Was Only
Able To Drink 15 Oz. What Portion Of The Water Remained?
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A
Feedback: Subtract The Quantity Of Water The Client Drank (15 Oz) From The Total
Available Quantity (25 Oz): 10 Oz Remain. To Determine The Portion Of The Water That
Remains, Create A Fraction By Dividing 10 Oz (Remaining Portion) By 25 Oz (Total Portion).
Therefore, 10 Divided By 25 = 10/25. To Reduce Fractions, Find The Largest Number That
Can Be Divided Evenly Into The Numerator And The Denominator
(5). Ten Divided By 5 (10/5) = 2; 25/5 = 5. The Fraction 10/25 Can Be Reduced To Its Lowest
Terms Of 2/5.
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care And
Comfort Cognitive Level: Apply
Difficulty: Moderate
Page And Header: 2, Dividing Whole Numbers; 3, Fractions
Integrated Process: Teaching/Learning
Objective: 1, 2
2. A Patient/Client Was Prescribed 240 w
mwlwo.F Etnbsusremb.Ywmsouth As A Supplement But
Consumed Only 100 Ml. What Portion Of The Ensure Remained?
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B
Feedback: Subtract The Quantity Of Ensure The Client Consumed (100 Ml) From The Total
Available Quantity (240 Ml): 140 Ml Remain. To Determine The Portion Of The Ensure That
Remains, Create A Fraction By Dividing 140 Ml (Remaining Portion) By 240 Ml (Total
Portion). Therefore, 140 Divided By 240 = 7/12. To Reduce Fractions, Find The Largest
Number That Can Be Divided Evenly Into The Numerator And The Denominator (20); 140
Divided By 20 (140/20) = 7; 240/20 = 12. The Fraction 140/240 Can Be Reduced To Its
Lowest Terms Of 7/12.
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care And
Comfort Cognitive Level: Apply
Difficulty: Moderate
Page And Header: 2, Dividing Whole Numbers; 3, Fractions
Integrated Process: Teaching/Learning
Objective: 1, 2
1|Pag e
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, 3. A Patient/Client Consumed Oz. Of Coffee, 2/3 Oz. Of Ice Cream, And Oz. Of Beef
Broth. What Is The Total Number Of Ounces Consumed That Should Be Documented For
The Patient/Client?
a. 3 3/4
b. 4 5/12
c. 4 2/3
d. 4 4/9
ANS: B
Feedback: Add The Amount Of Ounces Consumed. First, Change Any Mixed Number To A
Fraction By Multiplying The Whole Number By The Denominator And Then Adding That
Total To The Numerator. For The Coffee, 4 2 = 8 + 1 = 9/4; For The Beef Broth, 2 1
= 2 + 1 = 3/2. Then Add: 9/4 + 2/3 (Ice Cream) + 3/2. When Fractions Have Different
Denominators, Find The Least Common Denominator (LCD). For 2, 3, And 4, The LCD =
12. Rewrite Each Fraction Using The LCD; Divide The LCD By The Denominator Of Each
Fraction And Then Multiply That Result By The Numerator Of The Fraction. The New
Fractions To Be Added Are 27/12 (Coffee), 8/12 (Ice Cream), And 18/12 (Beef Broth). After
Conversion Of The Fractions, The Numerators Are Added Together And The Fraction Is
Reduced To The Lowest Terms.
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care And
Comfort Cognitive Level: Analyze
Difficulty: Difficult
Page And Header: 2, Multiplying Whole Numbers; 3,
Fractions Integrated Process: Communication And
Documentation Objective: 1, 2
4. A Coffee Cup Holds 180 Ml. The Patient/Client Drank 2? Cups Of Coffee. How Many
Milliliters Would
The Nurse Document As
Consumed?
a. 360
b. 420
c. 510
d. 600
ANS: B
Feedback: The Coffee Cup Holds 180 Ml. The Client Drank 2? Cups. To Estimate The Total
Number Of Milliliters Consumed, Multiply 180 7/3 ( ). When A Mixed Number Is
Present, Change It To An Improper Fraction By Multiplying The Whole Number By The
Denominator And Then Adding That Total To
The Numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 Ml × 7/3 = 420 Ml (180 ÷ 3 = 60 × 7 =
420).
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care And
Comfort Cognitive Level: Analyze
Difficulty: Difficult
Page And Header: 2, Multiplying Whole Numbers; 3,
Fractions Integrated Process: Communication And
Documentation Objective: 1, 2
5. A Patient/Client Weighed 48.52 Kg On Admission And Now Weighs 50.4 Kg. How Many
Kilograms Were Gained Since Admission?
a. 0.78
2|Pag e
www.PlusBay.Plus
