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Answers and Solutions Manual for Student Exercises for Spectrometric Identification of Organic Compounds (8th Edition) by Robert M. Silverstein, Francis X. Webster, David J. Kiemle, and David L. Bryce – Complete Step-by-Step Spectroscopy Problem Solutions

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This Answers and Solutions Manual corresponds to the Student Exercises for Spectrometric Identification of Organic Compounds (8th Edition) by Robert M. Silverstein, Francis X. Webster, David J. Kiemle, and David L. Bryce. It provides complete, detailed solutions to all textbook exercises, including spectral interpretation, compound identification, and structure elucidation problems. Each solution walks students through the reasoning process behind interpreting IR, NMR (¹H and ¹³C), mass spectrometry (MS), and UV-Vis spectra. Step-by-step explanations guide readers through identifying key peaks, chemical shifts, splitting patterns, molecular ion fragments, and functional groups to arrive at the correct molecular structures. The manual covers all chapters and exercise sets included in the 8th edition, aligning directly with the examples and learning objectives of Silverstein’s text. It reinforces the essential analytical skills needed to interpret spectroscopic data with accuracy and confidence — critical for courses in Organic Chemistry, Analytical Chemistry, and Spectroscopic Methods. Each answer includes annotated spectra, chemical reasoning, and brief reviews of underlying theory to strengthen conceptual understanding. Ideal for undergraduate and graduate students, this guide bridges the gap between textbook theory and real-world spectral analysis, helping learners develop the intuition and precision required in organic structure determination. It is also an invaluable tool for laboratory coursework, self-study, or exam preparation in advanced organic and instrumental analysis. Comprehensive, methodical, and clear, this manual supports mastery of one of the most essential skills in modern organic chemistry.

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Institution
Introduction To Continuum Mechanics
Course
Introduction to continuum mechanics

















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Robert M. Silverstein, Francis X. Webster, David J. Kiemle, David L. Bryce Spectrometric Identification of Organic Compounds
  • 2014
  • 9780470616376
  • Unknown

Written for

Institution
Introduction to continuum mechanics
Course
Introduction to continuum mechanics

Document information

Uploaded on
October 30, 2025
Number of pages
107
Written in
2025/2026
Type
Exam (elaborations)
Contains
Questions & answers

Subjects

  • spectroscopic identification organic structure det
  • robert silverstein solution manual
  • nmr spectroscopy ir spectroscopy
  • mass spectrometry uv vis spectroscopy
  • organic chemistry exercises spectral analys

Content preview

All 8 Chapters Covered




PDF
Spectrometric
ldentification of
Organic Compounds

,
,Answers for Student Exercises 1 .1 to 1 .5 1

Atom Type # of Atoms Mass Total Mass
Hydrogen 22 1.00783 22.17226
a
Carbon 10 12.00000 120.00000
Nitrogen 0 14.0031 0.00000
3-ethyloctane Oxygen 0 15.9949 0.00000
C10H22 Sulfur 0 31.9721 0.00000
CnHmXxNyOz IHD Bromine 0 78.9183 0.00000
Index = (n) - (m/2) - (x/2) + (y/2) + 1 = 0 Exact Mass 142.17226

- (C2Hs•) +


[ r Rule 3
..
[ r - (CH2=CH2) +
+



Rule 9

b Atom Type # of Atoms Mass Total Mass
Hydrogen 18 1.00783 18.14094
Carbon 10 12.00000 120.00000
Nitrogen 0 14.0031 0.00000
3-butylcyclohex-1-ene Oxygen 0 15.9949 0.00000
C10H18 Sulfur 0 31.9721 0.00000
CnHmXxNyOz IHD Bromine 0 78.9183 0.00000
Index = (n) - (m/2) - (x/2) + (y/2) + 1 = 2 Exact Mass 138.14094




[
[
rr or



- (C4H9 )
•
Rule 5 and 6 .. 0

Rule 6
.-.
r r .. r
- (CH)=CH
- 7 )


[
r r - (C3H7•) \_)/ ..

, @SOLUTIONSSTUDY


+
• \ /
+
Rule 3

,Answers for Student Exercises 1 .1 to 1 .5 3

0 Atom Type # of Atoms Mass Total Mass
Hydrogen 18 1.00783 18.14094
Carbon 13 12.00000 156.00000
c
Nitrogen 0 14.0031 0.00000
2-methyl-1-phenylhexan- l-one Oxygen 1 15.9949 15.99490
C13H1sO Sulfur 0 31.9721 0.00000
CnHmXxNyOz IHD Bromine 0 78.9183 0.00000
Index = (n) - (m/2) - (x/2) + (y/2) + 1 = 5 Exact Mass 190.13584




o+
Rule 8

+ +


Rule 9 \=I rH
. ---
\=I
H
/


- (CO)

O
+
I
Rule 8+9

Atom Type # of Atoms Mass Total Mass
d Hydrogen 22 1.00783 22.17226
Carbon 11 12.00000 132.00000
(E)-undec-3-ene
C11H22 Nitrogen 0 14.0031 0.00000
Oxygen 0 15.9949 0.00000
Sulfur 0 31.9721 0.00000
CnHmXxNyOz IHD Bromine 0 78.9183 0.00000
Index = (n) - (m/2) - (x/2) + (y/2) + 1 = 1 Exact Mass 154.17226




+
+



[ (;
.
•
3
..
r -Rule
(CH 5)


•
+




0
r. -(
C5H13)

Rule 5
.. +
+




- (C7H14) +
Rule 9

, @SOLUTIONSSTUDY
Atom Type # of Atoms Mass Total Mass
e Hydrogen 18 1.00783 18.14094
Carbon 12 12.00000 144.00000
Nitrogen 0 14.0031 0.00000
l-(hexan-2-yl)benzene Oxygen 0 15.9949 0.00000
C12 H18
Sulfur 0 31.9721 0.00000
CnHmXxNyOz IHD Bromine 0 78.9183 0.00000
Index = (n) - (m/2) - (x/2) + (y/2) + 1 = 4 Exact Mass 162.14094

.
+
+
•3
- (CH )
Rule 7 ..
.
+


- (C4H9 )

Rule 7
•
.. 0)
t

.
+ - (C4H3 )
Rule 9 .. [Cf]
Atom Type # of Atoms Mass Total Mass
Hydrogen 16 1.00783 16.12528
Carbon 7 12.00000 84.00000
Nitrogen 0 14.0031 0.00000
heptan-2-ol
Oxygen 1 15.9949 15.99490
C7H160
Sulfur 0 31.9721 0.00000
CnHmXxNyOz IHD Bromine 0 78.9183 0.00000
Index = (n) - (m/2) - (x/2) + (y/2) + 1= 0 Exact Mass 116.12018

•
•+H
- (CsH11 )

Rule 8
.. + H


.. OH

H
- (CH;) +
•+ Rule 8



H
- (Ii)
Rule 8
.. OH




k•+
- (H70)
Rule 9 .. +

,Answers for Student Exercises 1 .1 to 1 .5 5

Atom Type # of Atoms Mass Total Mass
Hydrogen 22 1.00783 22.17226
COOH Carbon 11 12.00000 132.00000
Nitrogen 0 14.0031 0.00000
3,5,7-trimethyloctanoic acid
Oxygen 2 15.9949 31.98980
C11H2202
Sulfur 0 31.9721 0.00000
CnHmXxNyOz IHD Bromine 0 78.9183 0.00000
Index = (n) - (m/2) - (x/2) + (y/2) + 1 = 1 Exact Mass 186.16206




- (OH•)

Rule 8



+
• 0 0
OH
Rule 8
..
- (C10H21 ) Ill
'OcH II
+C...,
OH
+,..,..H +
0 OH
- (C9H13)
Rule 9
.. HO
A..... • HO
HO
Atom Type # of Atoms Mass Total Mass
Hydrogen 14 1.00783 14.10962
h
OH Carbon 6 12.00000 72.00000
Nitrogen 0 14.0031 0.00000
hexan-1-ol
Oxygen 1 15.9949 15.99490
C6H140
Sulfur 0 31.9721 0.00000
CnHmXxNyOz IHD Bromine 0 78.9183 0.00000
Index = (n) - (m/2) - (x/2) + (y/2) + 1 = 0 Exact Mass 102.10452
H
I •



Rule 9


- (CsH1•1 )
OH
•+ Rule 8


•
- (H ) +
OH ··
OH
•+ Rule 8

,
,Answers for Student Exercises 1.1 to 1.5 5

Atom Type # of Atoms Mass Total Mass
Hydrogen 18 1.00783 18.14094
Carbon 8 12.00000 96.00000
OH
Nitrogen 0 14.0031 0.00000
2-methylheptan-2-ol Oxygen 1 15.9949 15.99490
C8H180
Sulfur 0 31.9721 0.00000
CnHmXxNyOz IHD Bromine 0 78.9183 0.00000
Index = (n) - (m/2) - (x/2) + (y/2) + 1 = 0 Exact Mass 130.13584
•
- (CsH11 )
OH
•+ Rule 8

- (CH• )
3
OH OH
•+ Rule 8

H
I•



J7 Rule 8


Atom Type
Hydrogen
Rule 8


# of Atoms
16
..
- (CH2= C (CH3h)



Mass
1.00783
Total Mass
16.12528
s Carbon 7 12.00000 84.00000
butyl(propy1)sulfane Nitrogen 0 14.0031 0.00000
C7H16S Oxygen 0 15.9949 0.00000
Sulfur 1 31.9721 31.97210
CnHmXxNyOz IHD Bromine 0 78.9183 0.00000
Index = (n) - (m/2) - (x/2) + (y/2) + 1= 0 Exact Mass 132.09738




Rule 8




=SH
+
Rule 9




s
Rule 8 +

, @SOLUTIONSSTUDY

Atom Type # of Atoms Mass Total Mass
k
Hydrogen 20 1.00783 20.15660
Carbon 13 12.00000 156.00000
Nitrogen 0 14.0031 0.00000
(2-hexylphenyl)methanol Oxygen 1 15.9949 15.99490
C13H200 Sulfur 0 31.9721 0.00000
CnHmXxNyOz IHD Bromine 0 78.9183 0.00000
Index = (n) - (m/2) - (x/2) + (y/2) + 1 = 4 Exact Mass 192.15150


or


- (CsH1•1 )
..
r
Rule 7


- (OH•)
Rule 7 ..
- (H)O)
Rule 9
..
0 Atom Type # of Atoms Mass Total Mass


'd U ..,,::. ..,,::.
N0
(4-nitrophenyl )(phenyl)methanone
2
Hydrogen
Carbon
Nitrogen
Oxygen
9
13
1
3
1.00783
12.00000
14.0031
15.9949
9.07047
156.00000
14.00310
47.98470
C 13H9 N03
Sulfur 0 31.9721 0.00000
CnHmXxNyOz IHD Bromine 0 78.9183 0.00000
Index = (n) - (m/2) - (x/2) + (y/2) + 1 = 10 Exact Mass 227.05827


- (C5H4NO;)

.. d+"::
0


Rule 7&8
0N0 2


d+ - (CO)
Rule 8&9 o+
+u
0
(C5H5 )
• .. I "::
-
Rule 7&8
N0 2 N0 2
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