,
,Chapter 1: Arithmetic Needed for Dosage
5% 5% 5% 5% 5%
MULTIPLE CHOICE 5%
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to
5% 5 % 5% 5% 5% 5% 5 % 5% 5 % 5% 5% 5% 5% 5 % 5% 5% 5%
drink 1 5 oz. What portion of the water remained?
5% 5% 5% 5% 5% 5% 5% 5% 5% 5%
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available
5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5% 5 % 5 % 5 %
quantity (25 oz): 10 oz remain. To determine the portion of the water that remains, create a fr
5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5%
action by divi ding 10 oz (remaining portion) by 25 oz (total portion). Therefore, 10 divid
5% 5% 5% 5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
ed by 25 = 10/25. To reduce fractions, find the largest number that can be divided evenly
5 % 5 % 5 % 5 % 5 % 5% 5 % 5 % 5 % 5% 5 % 5 % 5 % 5% 5 % 5 %
5%into the numerator and the de nominator
5% 5 % 5 % 5% 5 % 5%
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest
5% 5% 5% 5% 5% 5% 5% 5 % 5% 5 % 5% 5% 5% 5% 5% 5% 5% 5% 5% 5%
terms of 2/5. 5 % 5%
Format: Multiple Choice Chapt5% 5% 5% 5
er: 1
% 5%
Client Needs: Physiological Integrity: Basic Care and Comfort
5% 5% 5% 5% 5% 5% x# 5%
Cognitive Level: Apply 5% 5%
Difficulty: Moderate 5%
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Inte
5% 5% 5% 5% 5% 5% 5% 5% 5%
grated Process: Teaching/Learning
5% 5% 5%
Objective: 1, 2 5% 5%
2. A patient/client was prescribed 240 W
5% mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed onl
5 % 5% 5% x# 5 % 5% 5% 5% 5% 5%
y 100 mL. What portion of the Ensure remained?
5% 5% 5% 5% 5% 5% 5% 5%
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total
5 % 5 % 5 % 5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
available quantity (240 mL): 140 mL remain. To determine the portion of the Ensure that
5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5
%remains, create a fraction by dividing 140 mL (remaining portion) by 240 mL (total portion).
5 % 5 % 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5 % 5%
Therefore, 140 divided by 240 = 7/12. To reduce fractions, find the largest number that can
5% 5% 5% 5 % 5 % 5 % 5% 5% 5% 5% 5 % 5 % 5% 5 % 5 % 5
%be divided evenly into the nu merator and the denominator (20); 140 divided by 20 (140/2
5 % 5 % 5% 5% 5 % 5% 5 % 5 % 5% 5 % 5% 5% 5 % 5% 5 %
0) = 7; 240/20 = 12. The fraction 140
5 % 5 % 5 % 5 % 5 % 5% 5% 5 %
/240 can be reduced to its lowest terms of 7/12.
5% 5% 5% 5% 5% 5% 5 % 5 % 5 %
Format: Multiple Choice Chapt5% 5% 5% 5
er: 1
% 5%
Client Needs: Physiological Integrity: Basic Care and Comfort
5% 5% 5% 5% 5% 5% x# 5%
Cognitive Level: Apply 5% 5%
Difficulty: Moderate 5%
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Inte
5% 5% 5% 5% 5% 5% 5% 5% 5%
grated Process: Teaching/Learning
5% 5% 5%
Objective: 1, 2 5% 5%
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, 3. A patient/client consumed
5 % oz. of coffee, 2/3 oz. of ice cream, and
5 % 5 % 5 % 5 % 5 % 5 % 5 % 5% 5 % 5 % 5% 5 %
oz. of beef broth. What is the total number of ounces consumed that should be document
5% 5% 5% 5% 5% 5% 5% 5 % 5% 5% 5% 5% 5 % 5% 5 %
ed for t he patient/client?
5% 5 % 5% 5%
a. 3 3/4 5 %
b. 4 5/12 5 %
c. 4 2/3 5 %
d. 4 4/9 5 %
ANS: B
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fra
5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
ction by multiplying the whole number by the denominator and then adding that total to the n
5 % 5% 5% 5% 5% 5 % 5% 5% 5% 5% 5% 5% 5% 5 % 5% 5%
umerator. For t he coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
5% 5% 5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denomi
5% 5% 5% 5% 5% 5% 5% 5 % 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5 %
nators, find the least common denominator (LCD). For 2, 3, and 4, the LCD =
5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction a
5% 5% 5% 5% 5% 5% 5 % 5% 5% 5% 5% 5% 5 % 5% 5% 5%
nd t hen multiply that result by the numerator of the fraction. The new fractions to be ad
5% 5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
ded are 27/12 (coffee), 8/12 (ice cream), and 18/12 (beef broth). After conversion of the fra
5 % 5 % 5% 5% 5% 5 % 5 % 5% 5% 5% 5 % 5% 5% 5% 5%
ctions, the numerators are added together and the fraction is reduced to the lowest terms.
5% 5% 5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
Format: Multiple Choice Chapt 5% 5% 5% 5
%er: 1 5%
Client Needs: Physiological Integrity: Basic Care and Comfort
5% 5% 5% 5% 5% 5% 5% 5%
Cognitive Level: Analyze 5% 5%
Difficulty: Difficult 5%
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
5% 5% 5% 5% 5% 5% 5% 5% 5%
I ntegrated Process: Communication and Documentation Object
5% 5% 5% 5% 5% 5%
iv e: 1, 2
5% 5% 5%
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters
5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5%
would
the 5% nurse document as consum 5% 5% 5%
WWW.TBSM.WS
ed
?
a. 360
b. 420
c. 510
d. 600
ANS: B
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total nu
5 % 5% 5% 5% 5 % 5 % 5% 5 % 5% 5% 5 % 5% 5% 5 % 5% 5 %
mber of milliliters consumed, multiply 180 7/3 (
5 % 5% 5% 5% 5% 5% 5% 5%
). When a mixed number is present, change it to an improper fraction by multiplying the who
5% 5% 5% 5% 5 % 5% 5% 5% 5 % 5% 5% 5% 5% 5% 5% 5%
le nu 5%
mber by the denominator and then adding that total to
5 % 5% 5% 5% 5% 5% 5% 5% 5%
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 ×
5% 5 % 5% 5 % 5% 5 % 5 % 5% 5% 5% 5% 5% 5% 5% 5 % 5% 5 % 5% 5% 5% 5 % 5 % 5% 5 %
5%7 = 420).5 % 5%
Format: Multiple Choice Chapt 5% 5% 5% 5
%er: 1 5%
Client Needs: Physiological Integrity: Basic Care and Comfort
5% 5% 5% 5% 5% 5% 5% 5%
Cognitive Level: Analyze 5% 5%
Difficulty: Difficult 5%
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
5% 5% 5% 5% 5% 5% 5% 5% 5%
I ntegrated Process: Communication and Documentation Object
5% 5% 5% 5% 5% 5%
iv e: 1, 2
5% 5% 5%
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilogram
5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5%
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,Chapter 1: Arithmetic Needed for Dosage
5% 5% 5% 5% 5%
MULTIPLE CHOICE 5%
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to
5% 5 % 5% 5% 5% 5% 5 % 5% 5 % 5% 5% 5% 5% 5 % 5% 5% 5%
drink 1 5 oz. What portion of the water remained?
5% 5% 5% 5% 5% 5% 5% 5% 5% 5%
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available
5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5% 5 % 5 % 5 %
quantity (25 oz): 10 oz remain. To determine the portion of the water that remains, create a fr
5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5%
action by divi ding 10 oz (remaining portion) by 25 oz (total portion). Therefore, 10 divid
5% 5% 5% 5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
ed by 25 = 10/25. To reduce fractions, find the largest number that can be divided evenly
5 % 5 % 5 % 5 % 5 % 5% 5 % 5 % 5 % 5% 5 % 5 % 5 % 5% 5 % 5 %
5%into the numerator and the de nominator
5% 5 % 5 % 5% 5 % 5%
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest
5% 5% 5% 5% 5% 5% 5% 5 % 5% 5 % 5% 5% 5% 5% 5% 5% 5% 5% 5% 5%
terms of 2/5. 5 % 5%
Format: Multiple Choice Chapt5% 5% 5% 5
er: 1
% 5%
Client Needs: Physiological Integrity: Basic Care and Comfort
5% 5% 5% 5% 5% 5% x# 5%
Cognitive Level: Apply 5% 5%
Difficulty: Moderate 5%
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Inte
5% 5% 5% 5% 5% 5% 5% 5% 5%
grated Process: Teaching/Learning
5% 5% 5%
Objective: 1, 2 5% 5%
2. A patient/client was prescribed 240 W
5% mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed onl
5 % 5% 5% x# 5 % 5% 5% 5% 5% 5%
y 100 mL. What portion of the Ensure remained?
5% 5% 5% 5% 5% 5% 5% 5%
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total
5 % 5 % 5 % 5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
available quantity (240 mL): 140 mL remain. To determine the portion of the Ensure that
5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5
%remains, create a fraction by dividing 140 mL (remaining portion) by 240 mL (total portion).
5 % 5 % 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5 % 5%
Therefore, 140 divided by 240 = 7/12. To reduce fractions, find the largest number that can
5% 5% 5% 5 % 5 % 5 % 5% 5% 5% 5% 5 % 5 % 5% 5 % 5 % 5
%be divided evenly into the nu merator and the denominator (20); 140 divided by 20 (140/2
5 % 5 % 5% 5% 5 % 5% 5 % 5 % 5% 5 % 5% 5% 5 % 5% 5 %
0) = 7; 240/20 = 12. The fraction 140
5 % 5 % 5 % 5 % 5 % 5% 5% 5 %
/240 can be reduced to its lowest terms of 7/12.
5% 5% 5% 5% 5% 5% 5 % 5 % 5 %
Format: Multiple Choice Chapt5% 5% 5% 5
er: 1
% 5%
Client Needs: Physiological Integrity: Basic Care and Comfort
5% 5% 5% 5% 5% 5% x# 5%
Cognitive Level: Apply 5% 5%
Difficulty: Moderate 5%
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Inte
5% 5% 5% 5% 5% 5% 5% 5% 5%
grated Process: Teaching/Learning
5% 5% 5%
Objective: 1, 2 5% 5%
1| P a g e
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, 3. A patient/client consumed
5 % oz. of coffee, 2/3 oz. of ice cream, and
5 % 5 % 5 % 5 % 5 % 5 % 5 % 5% 5 % 5 % 5% 5 %
oz. of beef broth. What is the total number of ounces consumed that should be document
5% 5% 5% 5% 5% 5% 5% 5 % 5% 5% 5% 5% 5 % 5% 5 %
ed for t he patient/client?
5% 5 % 5% 5%
a. 3 3/4 5 %
b. 4 5/12 5 %
c. 4 2/3 5 %
d. 4 4/9 5 %
ANS: B
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fra
5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
ction by multiplying the whole number by the denominator and then adding that total to the n
5 % 5% 5% 5% 5% 5 % 5% 5% 5% 5% 5% 5% 5% 5 % 5% 5%
umerator. For t he coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
5% 5% 5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denomi
5% 5% 5% 5% 5% 5% 5% 5 % 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5 %
nators, find the least common denominator (LCD). For 2, 3, and 4, the LCD =
5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction a
5% 5% 5% 5% 5% 5% 5 % 5% 5% 5% 5% 5% 5 % 5% 5% 5%
nd t hen multiply that result by the numerator of the fraction. The new fractions to be ad
5% 5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
ded are 27/12 (coffee), 8/12 (ice cream), and 18/12 (beef broth). After conversion of the fra
5 % 5 % 5% 5% 5% 5 % 5 % 5% 5% 5% 5 % 5% 5% 5% 5%
ctions, the numerators are added together and the fraction is reduced to the lowest terms.
5% 5% 5% 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 % 5 %
Format: Multiple Choice Chapt 5% 5% 5% 5
%er: 1 5%
Client Needs: Physiological Integrity: Basic Care and Comfort
5% 5% 5% 5% 5% 5% 5% 5%
Cognitive Level: Analyze 5% 5%
Difficulty: Difficult 5%
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
5% 5% 5% 5% 5% 5% 5% 5% 5%
I ntegrated Process: Communication and Documentation Object
5% 5% 5% 5% 5% 5%
iv e: 1, 2
5% 5% 5%
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters
5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5%
would
the 5% nurse document as consum 5% 5% 5%
WWW.TBSM.WS
ed
?
a. 360
b. 420
c. 510
d. 600
ANS: B
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total nu
5 % 5% 5% 5% 5 % 5 % 5% 5 % 5% 5% 5 % 5% 5% 5 % 5% 5 %
mber of milliliters consumed, multiply 180 7/3 (
5 % 5% 5% 5% 5% 5% 5% 5%
). When a mixed number is present, change it to an improper fraction by multiplying the who
5% 5% 5% 5% 5 % 5% 5% 5% 5 % 5% 5% 5% 5% 5% 5% 5%
le nu 5%
mber by the denominator and then adding that total to
5 % 5% 5% 5% 5% 5% 5% 5% 5%
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 ×
5% 5 % 5% 5 % 5% 5 % 5 % 5% 5% 5% 5% 5% 5% 5% 5 % 5% 5 % 5% 5% 5% 5 % 5 % 5% 5 %
5%7 = 420).5 % 5%
Format: Multiple Choice Chapt 5% 5% 5% 5
%er: 1 5%
Client Needs: Physiological Integrity: Basic Care and Comfort
5% 5% 5% 5% 5% 5% 5% 5%
Cognitive Level: Analyze 5% 5%
Difficulty: Difficult 5%
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
5% 5% 5% 5% 5% 5% 5% 5% 5%
I ntegrated Process: Communication and Documentation Object
5% 5% 5% 5% 5% 5%
iv e: 1, 2
5% 5% 5%
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilogram
5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5% 5%
2| P a g e
www.PlusBay.Plus
