A 30-inch diameter wastewater interceptor is located to be flowing half-full at about two fps. The
approximate extent of wastewater flowing thru the pipe is ________. - ANS-2,200 gallons in
step with minute
A entire blend activated sludge plant has a quick settling sludge and high amounts of pin floc
leaving the clarifier. One method of correcting the hassle is to ________. - ANS-Increase F/M
ratio by losing extra
A one-cylinder reciprocating sludge pump with a ten-inch bore and a five-inch stroke pumps at a
price of 50 cycles consistent with minute. How many minutes ought to the pump be operated to
pump 5,000 gallons of sludge? - ANS-60 mins
A primary clarifier has a flow of three.0 MGD and has a diameter of one hundred ft. It is 12 feet
deep and has 24 inches of freeboard. What is the detention time in hours? - ANS-Formulas
A remedy plant has a clarifier this is 60 toes in diameter and is 10 feet deep. The weir is 2 ft
inside the outer clarifier wall. The drift is 1.0 MGD. The weir and outflow channel is three toes
deep.
A. What is the detention time in hours?
B. What is the surface loading in gal/ft2/day?
C. What is the weir loading in gal/linear feet/day? - ANS-Formulas
A remedy plant has a clarifier that is 60 feet in diameter and is 10 feet deep. The weir is 2 toes
in the outer clarifier wall. The go with the flow is 1.Zero MGD. The weir and outflow channel is 3
ft deep. A. What is the detention time in hours? - ANS-Formula
A treatment plant has number one clarifiers. Each has a diameter of forty feet and a intensity of
12 toes. If the design go with the flow is 1.2 mgd, locate the surface loading on every clarifier in
gallons/ft2/day. Assume the drift is similarly cut up between the two clarifiers.
3.14 x 20 x 20 = 1256
1,two hundred,000 /2
= 600,000 gallons each
600,000/ 1256 - ANS-b. 478 gallons/ft2/day
A wastewater treatment plant has a clarifier that is eighty feet in diameter and is 12 toes deep.
The drift is two.5 mgd. The single weir is toes in the outer wall and is 3 toes deep
What is the clarifier detention time in hours?
A. Three.9
, b. 3.5
c. 5.Three
d. 4.2 - ANS-Formula
A wastewater treatment plant has a clarifier that is 80 feet in diameter and is 12 feet deep. The
waft is two.5 mgd. The unmarried weir is two toes within the outer wall and is three ft deep
What is the hydraulic loading on the clarifier in gal/sq. Toes/day?
A. 598
b. 698
c. 551
d. 614 - ANS-Formula
A wastewater treatment plant has a clarifier that is 80 ft in diameter and is 12 ft deep. The go
with the flow is 2.5 mgd. The unmarried weir is two ft in the outer wall and is three toes deep.
What is the weir loading in gal/linear toes/day?
A. 10,000
b. 10,460
c. 11,276
d. Eleven,four hundred - ANS-Formula
A sector in a body of water that become these days polluted would possibly show signs of
________. - ANS-low DO, scarce aquatic existence, low turbidity
A. What are the three foremost characteristics of "factor supply" water pollution in Texas? -
ANS-a. Can be without problems recognized. For example, "This is wherein they discharge."
b. Can be monitored for effluent traits.
C. Can be authorized by regulators.
According to 30 TAC Chapter 317, all pipe and fittings used in wastewater strain mains shall
have a minimal psi strain rating of ________. - ANS-150
According to Chapter 317 Design Criteria, a manhole may be hooked up inside 9 feet of an
present waterline if ________. - ANS-the manhole is completely watertight and examined for no
leakage
According to layout criteria, what are the minimal allowable diameters for a manhole? - ANS-24
inch opening and forty eight inch inside diameter
An activated sludge plant has a median every day waft of three.Five MG. The aeration tank
capability is 1.2 MG with a MLSS attention of 3200 mg/L. The clarifier has a potential of 400,000
gallons with a MLSS concentration of 6,000 mg/L. The wasting fee is 40,000 gallons per day
with a MLSS concentration of eight, 000 mg/L. The effluent TSS is eighteen mg/L. Assuming