Test Bank For Fundamentals of Physics, Extended 12th Edition by David Halliday||ISBN NO:10,1119773512||ISBN NO:13,978-1119773511||All Chapters||Complete Guide A+

Chapter 1:
tt MEASUREMENT

, Chapter 1: tt MEASUREMENT

1. The SI standard of time is based on:
tt tt tt tt tt tt tt



A. the daily rotation of the earth
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B. the frequency of light emitted by Kr86
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C. the yearly revolution of the earth about the sun
tt tt tt tt tt tt tt tt


D. a precision pendulum clock
tt tt tt


E. none of these tt tt



Ans: E tt t t




2. A nanosecond is:
tt tt


A. 109 s tt


B. 10−9 s tt


C. 10−10 s tt


D. 10−10 s tt


E. 10−12
Ans: B tt




3. The SI standard of length is based on:
tt tt tt tt tt tt tt



A. the distance from the north pole to the equator along a meridian passing through Paris
tt tt tt tt tt tt tt tt tt tt tt tt tt tt


B. wavelength of light emitted by Hg198 tt tt tt tt tt


C. wavelength of light emitted by Kr86 tt tt tt tt tt


D. a precision meter stick in Paris
tt tt tt tt tt


E. the speed of tt tt



light Ans: Ett tt t t




4. In 1866, the U. S. Congress defined the U. S. yard as exactly 3600/3937 international
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meter. This was done primarily because:
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A. length can be measured more accurately in meters than in yards
tt tt tt tt tt tt tt tt tt tt


B. the meter is more stable than the yard
tt tt tt tt tt tt tt


C. this definition relates the common U. S. length units to a more widely used system
tt tt tt tt tt tt tt tt tt tt tt tt tt tt


D. there are more wavelengths in a yard than in a meter
tt tt tt tt tt tt tt tt tt tt


E. the members of this Congress were exceptionally
tt tt tt tt tt tt



intelligent Ans: C
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5. Which of the following is closest to a yard in length?
tt tt tt tt tt tt tt tt tt tt


A. 0.01 m tt


B. 0.1m tt


C. 1 m tt


D. 100 m tt


E. 1000 m tt



Ans: C tt




Ans:
B
2 Chapter 1: MEASUREMENT tt

, 6. There is no SI base unit for area because:
tt tt tt tt tt tt tt tt



A. an area has no thickness; hence no physical standard can be built
tt tt tt tt tt tt tt tt tt tt tt


B. we live in a three (not a two) dimensional world
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C. it is impossible to express square feet in terms of meters
tt tt tt tt tt tt tt tt tt tt


D. area can be expressed in terms of square meters
tt tt tt tt tt tt tt tt


E. area is not an important physical
tt tt tt tt tt



quantity Ans: D
tt tt t t




7. The SI base unit for mass is:
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A. gram
B. pound
C. kilogram
D. ounce
E. kilopound
Ans: C
tt t t




8. A gram is:
tt tt



A. 10−6 kg tt


B. 10−3 kg t t


C. 1 kg tt


D. 103 kg tt


E. 106 kg tt



Ans: B tt




9. Which of the following weighs about a pound?
tt tt tt tt tt tt tt



A. 0.05 kg tt


B. 0.5 kg tt


C. 5 kg tt


D. 50 kg tt


E. 500 kg tt



Ans: D tt




10. (5.0 × 104) × (3.0 × 106) =
tt tt tt tt tt tt tt tt



A. 1.5 × 109 tt tt


B. 1.5 × 1010 tt tt


C. 1.5 × 1011 tt tt


D. 1.5 × 1012 tt tt


E. 1.5 × 1013 tt tt



Ans: C tt




11. (5.0 × 104) × (3.0 × 10−6) =
tt tt tt tt tt tt tt tt


A. 1.5 × 10−3 tt tt


B. 1.5 × 10−1 tt tt


C. 1.5 × 101 tt tt


D. 1.5 × 103 tt tt


E. 1.5 × 105 tt tt




Chapter 1: tt MEASUREMENT

, 12. 5.0 tt × 105 + 3.0 × 106 =
tt tt tt tt tt tt



A. 8.0 × 105 tt tt


B. 8.0 × 106 tt tt


C. 5.3 × 105 tt tt


D. 3.5 × 105 tt tt


E. 3.5 × 106 tt tt



Ans: E tt




13. (7.0 × 106)/(2.0 × 10−6) =
tt tt tt tt tt tt


A. 3.5 × 10−12 tt tt


B. 3.5 × 10−6 tt tt


C. 3.5
D. 3.5 × 106 tt tt


E. 3.5 × 1012 tt tt



Ans: E tt




14. The number of significant figures in 0.00150 is:
tt tt tt tt tt tt tt



A. t t2 t t


B. 3
t t t t


C. t t4 t t


D. 5
t t t t


E. 6
t t t t



Ans: B tt




15. The number of significant figures in 15.0 is:
tt tt tt tt tt tt tt



A. tt1 tt


B. 2
t t t t


C. 3
t t t t


D. 4
t t t t


E. 5
t t t t



Ans: C tt




16. 3.2 tt × 2.7 = tt tt tt



A. 9
B. 8
C. 8.6
D. 8.64
E. 8.640
Ans: C tt




Ans:
B
2 Chapter 1: MEASUREMENT tt