BIOC 385 - SW 3 questions and answers graded A+

BIOC 385 - SW 3 questions and
answers graded A+

PART 1: homodimer

PART 2: approximately 33.0 angstroms

PART 3: Y to A - correct answer ✔✔PART 1:

Observe the multiple subunits of glycogenin and compare them to one another at both the
overall structural level and that of the amino acid sequence. Using both ribbon structure and
ball-and-stick representations, zoom in and rotate the molecule and focus on secondary
structure similarities or differences among the subunits. To change the display to ball-and-stick
or ribbon, first select "a (amino)" and "b (amino)" on the bottom of the player screen by clicking
the green-outlined boxes next to each. From the dropdown menu, click the icon for either
"Toggle Ribbon for selection" or "Toggle Ball & Stick for selection" on the Display line. To remove
the green x's, click the icon for "Clear Selection" on the Misc line in the dropdown menu.

Which of the following is the best description of this protein?



PART 2:

Locate the two uridine diphosphate-glucose molecules that are both substrate for glycogenin.
From the



PART 1: Attachment of a monosaccharide determines blood type; whether the O antigen has a
GalNAc attached, a Gal attached, both GalNAc and Gal attached, or neither attached.



PART 2:

Type O: Expression of neither GTA nor GTB

Type A: Expression of GTA, α-1,3-N-acetylgalactosaminyltransferase

Type B: Expression of GTB, α-1,3-galactosyltransferase

Type AB: Expression of GTA and GTB

, PART 3:

Type A: Compatible red blood cell donors: O and A

Type B: Compatible red blood cell donors: O and B

Type AB: Compatible red blood cell donors: O, A, B, and AB

Type O: Compatible red blood cell donors: only O - correct answer ✔✔PART 1:

What is the underlying difference that determines blood type?



PART 2:

Match the blood type with the associated glycosyltransferase enzyme expression.



PART 3:

Match the compatible red blood cell donors with the appropriate blood types.



Step C (α-1,3-galactosyltransferase is GTB; B-type) - correct answer ✔✔α-1,3-
galactosyltransferase alone is responsible for which step in the figure below?



PART 1: α(1→4)



PART 2: α(1→6)



PART 3:

- Glycogen has a dimeric protein at the reducing end, whereas amylopectin has a single glucose
residue.

- Branching is more frequent in glycogen than in amylopectin, occurring every 8-12 glucose
residues instead of every 15-30.

- Amylopectin is found in plants, and glycogen is found in animals. - correct answer ✔✔PART 1: