Chapter 2 DZ questions and answers
graded A+ updated
What is the ratio of hydrogen atoms (H) to oxygen atoms (O) in 2 L of water? Enter the simplest
whole number ratio in order of hydrogen to oxygen, respectively. - ANS ✔2,1
How many atoms of hydrogen (H) are present in 200 molecules of ammonia (NH3)? - ANS ✔600
H atoms
A solution of ammonia and water contains 4.70×1025 water molecules and 6.80×1024 ammonia
molecules. How many total hydrogen atoms are in this solution? - ANS ✔H₂O:
2(4.70x10^²⁵)=9.4x10^25
NH₃: 3(6.80x10^24)=2.04x10^25
so then: 9.4x10^25+2.04x10^25=1.14x10^26 H atoms
There are two different compounds of sulfur and fluorine.
In SF6, the mass of fluorine per gram of sulfur is 3.55 g F/g S.
In the other compound, SFX, the mass of fluorine per gram of sulfur is 1.18 g F/g S.
What is the value of X for the second compound? - ANS ✔first: divide the 3.55 to 1.18 and
round it to the nearest whole number: 3.55/1.18=3
therefore, F6 to Fx = 3:1 (because there are 3-1.18 in 3.55)
SF6/SFx=2 (6/3=2)
X=2
If you were John Dalton and had never heard of a mole, which of the following would you think
were possible sets of formulas for the compounds A, B, and C, respectively
Check all that apply.
graded A+ updated
What is the ratio of hydrogen atoms (H) to oxygen atoms (O) in 2 L of water? Enter the simplest
whole number ratio in order of hydrogen to oxygen, respectively. - ANS ✔2,1
How many atoms of hydrogen (H) are present in 200 molecules of ammonia (NH3)? - ANS ✔600
H atoms
A solution of ammonia and water contains 4.70×1025 water molecules and 6.80×1024 ammonia
molecules. How many total hydrogen atoms are in this solution? - ANS ✔H₂O:
2(4.70x10^²⁵)=9.4x10^25
NH₃: 3(6.80x10^24)=2.04x10^25
so then: 9.4x10^25+2.04x10^25=1.14x10^26 H atoms
There are two different compounds of sulfur and fluorine.
In SF6, the mass of fluorine per gram of sulfur is 3.55 g F/g S.
In the other compound, SFX, the mass of fluorine per gram of sulfur is 1.18 g F/g S.
What is the value of X for the second compound? - ANS ✔first: divide the 3.55 to 1.18 and
round it to the nearest whole number: 3.55/1.18=3
therefore, F6 to Fx = 3:1 (because there are 3-1.18 in 3.55)
SF6/SFx=2 (6/3=2)
X=2
If you were John Dalton and had never heard of a mole, which of the following would you think
were possible sets of formulas for the compounds A, B, and C, respectively
Check all that apply.
