SHRI ANAND EDUCATION
EAST SAGARPUR NEW DELHI
TRIGONOMETRY ASSIGNMENT
Class 10 - Mathematics
Time Allowed: 5 hours Maximum Marks: 175
1. If X sin3θ + Y cos3θ = sinθ cosθ and X sinθ = Y cosθ , then ________. [1]
a) X4 + Y4 = 1 b) X2 + Y2 = 1
n
c) X2 - Y2 = 1 d) X3 + Y3 = 1
tio
2. (cos4A - sin4A) on simplification, gives [1]
a) 2 cos2A - 1 b) 2 sin2A + 1
a
c) 2 sin2A - 1 d) 2 cos2A + 1
uc
3. If (tan θ + cot θ ) = 5 then (tan2 θ + cot2 θ ) = ? [1]
a) 23 b) 25
Ed
c) 24 d) 27
4. If 16 cot x = 12, the sin x−cos x
sin x+cos x
equals. [1]
nd
a) 2
7
b) 3
7
c) 0 d) 1
7
na
–
5. If 2 sin 2θ = √3 then θ = ? [1]
a) 45° b) 90°
ri A
c) 60° d) 30°
6. If 2 tan A = 3, then the value of 4 sin A+3 cos A
is [1]
4 sin A−3 cos A
a) 3 b) does not exist
Sh
c) 7
d) 1
√13 √13
3
7. If 3 cos θ = 5 sin θ , then the value of
5 sin θ−2 sec
3
θ+2 cos θ
is [1]
5 sin θ+2 sec θ−2 cos θ
a) 542
2937
b) 271
979
c) d)
322 316
2657 2937
8. If sinθ = cosθ , then 2 tan2θ + sin2θ - 1 = ________. [1]
a) b)
2 −2
3 3
c) 3
2
d) −3
2
9. If sec θ + tan θ = x, the value of sec θ is [1]
2
a) 1
2
(x −
1
x
) b) x −1
2
x +1
1/4
EAST SAGARPUR NEW DELHI
TRIGONOMETRY ASSIGNMENT
Class 10 - Mathematics
Time Allowed: 5 hours Maximum Marks: 175
1. If X sin3θ + Y cos3θ = sinθ cosθ and X sinθ = Y cosθ , then ________. [1]
a) X4 + Y4 = 1 b) X2 + Y2 = 1
n
c) X2 - Y2 = 1 d) X3 + Y3 = 1
tio
2. (cos4A - sin4A) on simplification, gives [1]
a) 2 cos2A - 1 b) 2 sin2A + 1
a
c) 2 sin2A - 1 d) 2 cos2A + 1
uc
3. If (tan θ + cot θ ) = 5 then (tan2 θ + cot2 θ ) = ? [1]
a) 23 b) 25
Ed
c) 24 d) 27
4. If 16 cot x = 12, the sin x−cos x
sin x+cos x
equals. [1]
nd
a) 2
7
b) 3
7
c) 0 d) 1
7
na
–
5. If 2 sin 2θ = √3 then θ = ? [1]
a) 45° b) 90°
ri A
c) 60° d) 30°
6. If 2 tan A = 3, then the value of 4 sin A+3 cos A
is [1]
4 sin A−3 cos A
a) 3 b) does not exist
Sh
c) 7
d) 1
√13 √13
3
7. If 3 cos θ = 5 sin θ , then the value of
5 sin θ−2 sec
3
θ+2 cos θ
is [1]
5 sin θ+2 sec θ−2 cos θ
a) 542
2937
b) 271
979
c) d)
322 316
2657 2937
8. If sinθ = cosθ , then 2 tan2θ + sin2θ - 1 = ________. [1]
a) b)
2 −2
3 3
c) 3
2
d) −3
2
9. If sec θ + tan θ = x, the value of sec θ is [1]
2
a) 1
2
(x −
1
x
) b) x −1
2
x +1
1/4