IICRC S500 Water Mitigation UPDATED
ACTUAL Exam Questions and CORRECT
Answers
The homeowner - CORRECT ANSWER - is responsible to take the necessary steps to
preserve and protect their property from further damage
Four principles of water damage restoration: - CORRECT ANSWER - Provide for health
and safety of workers and occupants; Document everything; Mitigate, and Dry
Four principles of drying - CORRECT ANSWER - Extract, Evaporate, dehumidify,
control temp
Extraction - CORRECT ANSWER - is removing excess water and is the first step in
mitigation
Evaporation - CORRECT ANSWER - is achieved by using energy (heat) to transform
water trapped in porous materials into a vapor, thereby releasing the moisture from the materials.
Dehumidification - CORRECT ANSWER - the process of removing water vapor from the
air.
Rate of Dehumidification - CORRECT ANSWER - must be at least equal to the rate of
evaporation.
True or False - CORRECT ANSWER - Elevated vapor pressure in a room Can cause
secondary damage to hygroscopic materials
True or False - CORRECT ANSWER - The control of temperature is important to enhance
both evaporation and dehumidification for effective drying
, True or False - CORRECT ANSWER - When temperature increases evaporation of
absorbed water increases and water vapor suspended in air also increases.
Classification of Water Intrusion - CORRECT ANSWER - described as Class 1, 2, 3, or 4.
Must be determined to calculate the amount of dehumidification required in drying process,
based on the amount of wet surface area, permeance/porosity of materials in drying area.
Class 1 - CORRECT ANSWER - is the least amount of water absorption and evaporation
load, affecting less 5% of porous materials with minimal absorption into low evaporation
materials.
Class 2 - CORRECT ANSWER - has a significant amount of water absorption and
evaporation load, affection 5-40% porous materials, with minimal absorption into low
evaporated materials
Class 3 - CORRECT ANSWER - has the greatest amount of water absorption and
evaporation load, affecting more than 40% porous materials and minimal absorption into low
evaporated materials
Class 4 - CORRECT ANSWER - has deeply held or bound water, and significant
absorption into low evaporation materials.
Determine the Class of water for a 20' x 20' x 8 ' room, with an entirely wet floor.. - CORRECT
ANSWER - Affected area/Total SF = % affected
400/1440 = .27777 x 100 = 28%
28% = Class 2
Determine the Class of Water for a 20' x 20' x 8' room, with only half the floor affected and
arriving within 24 hours of loss. - CORRECT ANSWER - Affected area/total sf = %
affected
200/1440 = .13888 x 100 = 14%
ACTUAL Exam Questions and CORRECT
Answers
The homeowner - CORRECT ANSWER - is responsible to take the necessary steps to
preserve and protect their property from further damage
Four principles of water damage restoration: - CORRECT ANSWER - Provide for health
and safety of workers and occupants; Document everything; Mitigate, and Dry
Four principles of drying - CORRECT ANSWER - Extract, Evaporate, dehumidify,
control temp
Extraction - CORRECT ANSWER - is removing excess water and is the first step in
mitigation
Evaporation - CORRECT ANSWER - is achieved by using energy (heat) to transform
water trapped in porous materials into a vapor, thereby releasing the moisture from the materials.
Dehumidification - CORRECT ANSWER - the process of removing water vapor from the
air.
Rate of Dehumidification - CORRECT ANSWER - must be at least equal to the rate of
evaporation.
True or False - CORRECT ANSWER - Elevated vapor pressure in a room Can cause
secondary damage to hygroscopic materials
True or False - CORRECT ANSWER - The control of temperature is important to enhance
both evaporation and dehumidification for effective drying
, True or False - CORRECT ANSWER - When temperature increases evaporation of
absorbed water increases and water vapor suspended in air also increases.
Classification of Water Intrusion - CORRECT ANSWER - described as Class 1, 2, 3, or 4.
Must be determined to calculate the amount of dehumidification required in drying process,
based on the amount of wet surface area, permeance/porosity of materials in drying area.
Class 1 - CORRECT ANSWER - is the least amount of water absorption and evaporation
load, affecting less 5% of porous materials with minimal absorption into low evaporation
materials.
Class 2 - CORRECT ANSWER - has a significant amount of water absorption and
evaporation load, affection 5-40% porous materials, with minimal absorption into low
evaporated materials
Class 3 - CORRECT ANSWER - has the greatest amount of water absorption and
evaporation load, affecting more than 40% porous materials and minimal absorption into low
evaporated materials
Class 4 - CORRECT ANSWER - has deeply held or bound water, and significant
absorption into low evaporation materials.
Determine the Class of water for a 20' x 20' x 8 ' room, with an entirely wet floor.. - CORRECT
ANSWER - Affected area/Total SF = % affected
400/1440 = .27777 x 100 = 28%
28% = Class 2
Determine the Class of Water for a 20' x 20' x 8' room, with only half the floor affected and
arriving within 24 hours of loss. - CORRECT ANSWER - Affected area/total sf = %
affected
200/1440 = .13888 x 100 = 14%
