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Summary Pearson Edexcel A Level Chemistry (Year 1 and Year 2) - Unit 3 - Redox I (9CH0)

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The ultimate summary of Chapter 3 of Pearson (Edexcel) A-Level Chemistry Year 1 textbook. This document is heavily illustrated/hand-drawn for better knowledge visualisation, so that you know exactly what you’re learning from this chapter of the textbook and hit the nail on the head in every question on your finals!

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Chapter 3 redox i
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3 - Redox Ⅰ
●​ ***Reduction: gain of electrons/hydrogen (in chemical reaction); decrease in
oxidation number
●​ ***Oxidation: loss of electrons/hydrogen (```); increase ```
○​ An example of continuous oxidation: NH3 ⇌ N2 ⇌ NO2- ⇌ NO3-​
​ ​ ​ ​ ​ -3​ 0​ +3​ +5
○​ Oxidation of oxygen eg O2 + 2F2 → 2F2O​
​ ​ ​ 0​ 0​ -1+2
●​ ***Oxidation number: theoretical charge of an atom in compound (if compound was
purely ionic)
○​ Ie elements have oxidation number of 0
○​ Sum of all oxidation states of all atoms in molecule/ion = overall charge of
molecule/ion
○​ RULES:
1.​ Hydrogen = +1 (otherwise hydride = -1)
2.​ Oxygen = -2 (unless peroxide [O22-] = -1, superoxide [O2-] = -½; others
+2)
3.​ Group 7 = -1
4.​ Group 1 = +1, Group 2 = +2
○​ No change in oxidation number (in reaction) - spectator ion
■​ No change FOR ALL IONS - NOT redox reaction
●​ ***Oxidising agent: oxidises sth else during reaction (while itself being reduced)
○​ Ie strong oxidising agents are more electronegative (stronger tendency to
gain electrons)
●​ ***Reducing agent: reduces ```` (``` oxidised)
○​ Ie strong reducing agents are less electronegative (stronger tendency to lose
electrons)
●​ ***Disproportionation: when a species is simultaneously oxidised and reduced at
the same time
○​ Eg 2Cu+ (aq) → Cu (s) + Cu2+ (aq) {copper (I) unstable in solution}
○​ Eg2 3Fe2+ (aq) → 2Fe3+ + Fe (s)
○​ Eg3 Cl2 + 2NaOH → NaClO + NaCl + H2O {in cold, aqueous NaOH}
■​ Eg3b 3Cl2 + 6NaOH → 5NaClO3 + NaCl + 3H2O {in hot, concd NaOH}
○​ Eg4 2H2O2 → 2H2O + O2 {decomposition of hydrogen peroxide}
○​ Eg5 Cl2 + H2O → HCl + HClO {production of commercial bleach}


Half equations → ionic (full) equations
●​ Eg oxidation half equation: Zn (s) → Zn2+ (aq) + 2e-​
Reduction ``: Cu2+ (aq) + 2e- → Cu (s)​
⇒ Sum to get redox equation (e- eliminated): Cu2+ (aq) + Zn (s) → Cu (s) + Zn2+ (aq)​
{Equations can ONLY be combined directly when e- are on opposite sides of
equations}
●​ RULES for balancing ionic equations:
1.​ (Balance chemical species - in terms of quantity)


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