WGU QTT2 Finite Mathematics Task 1 |Passed on First
Attempt |Latest Update with Complete Solution
Jeffrey Martin
Finite Mathematics – QTT2
Task 1
Part 1: Computational Proficiency with Real Numbers
Use your assigned numbers from “Part 1” of the “Finite Math Assignment Form: Task 1”
supporting document to do the following:
EVALUATOR COMMENTS: ATTEMPT 1
The final answers of 9 59/80, 73√3, and 49√15/5 are correct for A + B, C - D, and C ÷ E. Their explanations
are accurate.
The final answer of 225/504 is incorrect for A ÷ B. This is because the result of dividing 550 by 2 is not
225.
A. Compute each of the following without using a calculator and explain the process. Show all
work and use exact answers only. Express your final answer in simplest form and rationalize
any denominators.
• A+B
• A÷B
• C–D
• C÷E
The first part of this task asks us to add A+B, since these two numbers have fractions, the
first step is to get the least common denominator. The denominators are 16 & 10, we could just
multiply them to get 160, but in this case we can see that there is a lower common denominator
in the number 80- to get that we multiply 16 by 5, and we multiply 10 by 8. Then we need to
35 24
multiply the corresponding numerators by the same thing- giving us 3 and 6 , now that we
80 80
have common denominators, we simply add the whole numbers giving us 9, and then add the
, 59
numerators which gives us 59 and lastly the denominator remains 80. The answer is 9 . The
80
fraction is simplified as much as it can be so we are done.
7 3
The next question asks us to divide A by B, so 3 ÷6 when dividing fractions I find it
16 10
55
easiest to use improper fractions, so I multiplied 3x16 and added that to the 7, giving me then
16
63 55 63
multiplied 10x6 and added that to 3 which gave me . So the problem now looks like ÷ .
10 16 10
Dividing fractions can be done by multiplying by the reciprocal, in this case that gives us
55 10
×
16 63
550
Which equals a quick look and you realize we can divide both numbers by 2 to give us
1008
27 5
504
And that is the simplest form.
The third question in part 1 is C-D, looking at the chart provided I see that C-D is
7 √588−5 √75. Looking at this question I can see that the roots can be simplified by dividing
them by 3, so the equation can be written as (7 × √196 × √3)−¿ (5 × √25 × √3) this gives us two
roots that are perfect squares and the remaining roots are the same so they can easily be
subtracted. The next step makes it (7 × 14 × √ 3 ) − ( 5 × 5 × √ 3 ) which is 98 √3−25 √3, now just
subtract and we get 73 √3 for the final answer.
The last question in part 1 is C ÷ E or 7 √588 ÷ 2 √5. The first step is to simplify what I can, in
98 √3
this case, we can make it 7 × √196 × √3 which is 7 × 14 × √3∨ when written like this we
2 √5
49 √3
see that we can divide 98 by 2 to give us now we can’t leave a radical in the denominator
√5
49 √15
so if we multiply the top and bottom by √ 5 we get as our final answer.
5
Part 2: Properties of the Real Number System
Use your assigned problem from “Part 2” of the “Finite Math Assignment Form: Task 1”
supporting document to do the following:
B. Explain each step, excluding those that are labeled as “no justification needed.”
For each step, identify the property of the real numbers being used and explain how that
property is being applied.
Attempt |Latest Update with Complete Solution
Jeffrey Martin
Finite Mathematics – QTT2
Task 1
Part 1: Computational Proficiency with Real Numbers
Use your assigned numbers from “Part 1” of the “Finite Math Assignment Form: Task 1”
supporting document to do the following:
EVALUATOR COMMENTS: ATTEMPT 1
The final answers of 9 59/80, 73√3, and 49√15/5 are correct for A + B, C - D, and C ÷ E. Their explanations
are accurate.
The final answer of 225/504 is incorrect for A ÷ B. This is because the result of dividing 550 by 2 is not
225.
A. Compute each of the following without using a calculator and explain the process. Show all
work and use exact answers only. Express your final answer in simplest form and rationalize
any denominators.
• A+B
• A÷B
• C–D
• C÷E
The first part of this task asks us to add A+B, since these two numbers have fractions, the
first step is to get the least common denominator. The denominators are 16 & 10, we could just
multiply them to get 160, but in this case we can see that there is a lower common denominator
in the number 80- to get that we multiply 16 by 5, and we multiply 10 by 8. Then we need to
35 24
multiply the corresponding numerators by the same thing- giving us 3 and 6 , now that we
80 80
have common denominators, we simply add the whole numbers giving us 9, and then add the
, 59
numerators which gives us 59 and lastly the denominator remains 80. The answer is 9 . The
80
fraction is simplified as much as it can be so we are done.
7 3
The next question asks us to divide A by B, so 3 ÷6 when dividing fractions I find it
16 10
55
easiest to use improper fractions, so I multiplied 3x16 and added that to the 7, giving me then
16
63 55 63
multiplied 10x6 and added that to 3 which gave me . So the problem now looks like ÷ .
10 16 10
Dividing fractions can be done by multiplying by the reciprocal, in this case that gives us
55 10
×
16 63
550
Which equals a quick look and you realize we can divide both numbers by 2 to give us
1008
27 5
504
And that is the simplest form.
The third question in part 1 is C-D, looking at the chart provided I see that C-D is
7 √588−5 √75. Looking at this question I can see that the roots can be simplified by dividing
them by 3, so the equation can be written as (7 × √196 × √3)−¿ (5 × √25 × √3) this gives us two
roots that are perfect squares and the remaining roots are the same so they can easily be
subtracted. The next step makes it (7 × 14 × √ 3 ) − ( 5 × 5 × √ 3 ) which is 98 √3−25 √3, now just
subtract and we get 73 √3 for the final answer.
The last question in part 1 is C ÷ E or 7 √588 ÷ 2 √5. The first step is to simplify what I can, in
98 √3
this case, we can make it 7 × √196 × √3 which is 7 × 14 × √3∨ when written like this we
2 √5
49 √3
see that we can divide 98 by 2 to give us now we can’t leave a radical in the denominator
√5
49 √15
so if we multiply the top and bottom by √ 5 we get as our final answer.
5
Part 2: Properties of the Real Number System
Use your assigned problem from “Part 2” of the “Finite Math Assignment Form: Task 1”
supporting document to do the following:
B. Explain each step, excluding those that are labeled as “no justification needed.”
For each step, identify the property of the real numbers being used and explain how that
property is being applied.
