INSTRUCTOR’S
SOLUTIONS MANUAL
BEGINNING ALGEBRA:
EARLY GRAPHING
FOURTH EDITION
John Tobey
North Shore Community College
Danvers, Massachusetts
Jeffrey Slater
North Shore Community College
Danvers, Massachusetts
Jamie Blair
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Orange Coast College
Costa Mesa, California
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Jennifer Crawford
Normandale Community College
Bloomington, Minnesota
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, Contents
Chapter 0 1
Chapter 1 18
Chapter 2 37
Chapter 3 74
Chapter 4 109
Chapter 5 143
Chapter 6 165
Chapter 7 188
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Chapter 8 217
Chapter 9 241
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Practice Final Examination 272
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, Chapter 0
0.1 Exercises 8
25 1
26. = 3 25 = 8
13 3 24 3
2. : 17 is the denominator
17 1
3 17 11
4. 1: or 79 2
3 17 28. = 7 79 = 11
7 7 7
3 09
6. 3
4 7
2
20 5 × 4 5 15
8. = = 124 4 1
24 6 × 4 6 30. = 8 124 = 15 = 15
8 8 8 2
8 1× 8 1
10. = = 44
48 6 × 8 6 40
4
72 18 × 4
12. = =4
18 18 × 1
2 (4 × 5) + 2 20 + 2 22
32. 4 = = =
32 32 × 1 1 5 5 5 5
14. = =
64 32 × 2 2
1 (5 × 12) + 1 60 + 1 61
34. 5 = = =
33 11 × 3 3 12 12 12 12
16. = =
55 11 × 5 5 5 (1 × 6) + 5 6 + 5 11
36. 1 = = =
6 6 6 6
63 9 × 7 7
18. = =
81 9 × 9 9 2 (6 × 3) + 2 18 + 2 20
38. 6 = = =
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3 3 3 3 3
19 4
20. = 5 19 = 3
5 5 1 (10 × 9) + 1 90 + 1 91
15 40. 10 = = =
4 9 9 9 9
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78
54
7
5 42. = 78 ÷ 6
22. = 7 54 = 7 6
7 49 7 13
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5 6 78
6
6 18
41 5
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24. = 6 41 = 6 18
6 36 6 0
5 78
= 13
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, Chapter 0: A Brief Review of Arithmetic Skills ISM: Beginning Algebra: Early Graphing
5 ? 5 × 6 30 0.2 Exercises
44. = ⇒ =
9 54 9 × 6 54
2. You must change the fractions to equivalent
fractions with a common denominator.
5 ? 5 × 5 25
46. = ⇒ =
9 45 9 × 5 45 21 17
4. and
30 20
13 ? 13 × 3 39
48. = ⇒ = 30 = 2 ⋅ 3 ⋅ 5
17 51 17 × 3 51 20 = 2 ⋅ 2 ⋅ 5
LCD = 2 ⋅ 2 ⋅ 3 ⋅ 5 = 60
10 ? 10 × 4 40
50. = ⇒ =
15 60 15 × 4 60 5 1
6. and
18 24
7 ? 7 × 5 35 18 = 2 ⋅ 3 ⋅ 3
52. = ⇒ =
8 40 8 × 5 40 24 = 2 ⋅ 2 ⋅ 2 ⋅ 3
LCD = 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ 3 = 72
45 ? 45 × 2 90
54. = ⇒ =
50 100 50 × 2 100 5 7
8. and
16 48
20 5× 4 5 16 = 2 ⋅ 2 ⋅ 2 ⋅ 2
56. = =
424 106 × 4 106 48 = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 3
LCD = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 3 = 48
1400 70 × 20 70
58. = =
2420 121× 20 121 11 7
10. and
12 20
3 3 12 = 2 ⋅ 2 ⋅ 3
60. = is raisins
1+ 3 +1 5 20 = 2 ⋅ 2 ⋅ 5
LCD = 2 ⋅ 2 ⋅ 3 ⋅ 5 = 60
1+ 3 4
62. = does not contain nuts 7 8
1+ 3 +1 5 12. and
30 45
6 6 3× 2 3 30 = 2 ⋅ 3 ⋅ 5
64. = = =
6 + 8 14 7 × 2 7 45 = 3 ⋅ 3 ⋅ 5
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3 LCD = 2 ⋅ 3 ⋅ 3 ⋅ 5 = 90
of the students enrolled in 1994 were male.
7 1 3 9
14. , , and
7 14 35
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Classroom Quiz 0.1
7=7
56 7 × 8 7 14 = 2 ⋅ 7
1. = = 35 = 5 ⋅ 7
88 11× 8 11
LCD = 2 ⋅ 5 ⋅ 7 = 70
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11 (5 × 14) + 11 70 + 11 81
2. 5 ⇒ = = 3 5 11
14 14 14 14 16. , , and
8 12 42
8=2⋅2⋅2
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109 1
3. =9 12 = 2 ⋅ 2 ⋅ 3
12 12
42 = 2 ⋅ 3 ⋅ 7
9
LCD = 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ 7 = 168
12 109
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108
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