lOMoARcPSD|28627292
ENGR 244-W2024-Midterm-solutions
Mechanics of Materials (Concordia University)
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, lOMoARcPSD|28627292
The bell-crank mechanism shown in Figure P1.33 is in equilibrium for an applied load of P = 7 kN
applied at A. Assume a = 200 mm, b = 150 mm, and θ = 65°. Determine the minimum diameter d
required for pin B for each of the following conditions:
(a) The average shear stress in the pin may not exceed 40 MPa.
(b) The bearing stress in the bell crank may not exceed 100 MPa.
= (c) The bearing stress in the support bracket may not exceed 165 MPa.
20
solution :
B
Determine reaction at support
EMB = 0
0 FI x 150 = (1000 x 200 XSin65 )
%
65
N
z
·
·
S
Fi = 8459N - I /12
¡
65
By+ F, + 7000 XCos
= 0
IFX = 0
FBD/ 112 I
BX = - 11417 N / / 1 1
¡
=0
By 1000 xsin65 = 0
IFy
-
:
6344 N / / / /
By =
2
RB = , By + By
=
1306/N / / / /
<
Downloaded by Sarujan02 Thangavel ()
ENGR 244-W2024-Midterm-solutions
Mechanics of Materials (Concordia University)
Scan to open on Studocu
Studocu is not sponsored or endorsed by any college or university
Downloaded by Sarujan02 Thangavel ()
, lOMoARcPSD|28627292
The bell-crank mechanism shown in Figure P1.33 is in equilibrium for an applied load of P = 7 kN
applied at A. Assume a = 200 mm, b = 150 mm, and θ = 65°. Determine the minimum diameter d
required for pin B for each of the following conditions:
(a) The average shear stress in the pin may not exceed 40 MPa.
(b) The bearing stress in the bell crank may not exceed 100 MPa.
= (c) The bearing stress in the support bracket may not exceed 165 MPa.
20
solution :
B
Determine reaction at support
EMB = 0
0 FI x 150 = (1000 x 200 XSin65 )
%
65
N
z
·
·
S
Fi = 8459N - I /12
¡
65
By+ F, + 7000 XCos
= 0
IFX = 0
FBD/ 112 I
BX = - 11417 N / / 1 1
¡
=0
By 1000 xsin65 = 0
IFy
-
:
6344 N / / / /
By =
2
RB = , By + By
=
1306/N / / / /
<
Downloaded by Sarujan02 Thangavel ()
