Solutions for Principles of Physics Extended, International Adaptation 12th Edition Halliday & Resnick - All 44 Chapter + Answer Keys Included

Principles of Physics, Extended, Interna onal Adapta on,

12th Edi on Halliday & Resnick Chapter 1 - 44 + ANSWER KEYS




SOLUTION MANUAL

,ANSWER KEYS AT PAGE 1860
Table of Contents


1 Measurement
2 Mo on Along a Straight Line
3 Vectors
4 Mo on in Two and Three Dimensions
5 Force and Mo on--I
6 Force and Mo on--II
7 Kine c Energy and Work
8 Poten al Energy and Conserva on of Energy
9 Center of Mass and Linear Momentum
10 Rota on
11 Rolling, Torque, and Angular Momentum
12 Equilibrium and Elas city
13 Gravita on
14 Fluids
15 Oscilla ons
16 Waves--I
17 Waves--II
18 Temperature, Heat, and the First Law of Thermodynamics
19 The Kine c Theory of Gases
20 Entropy and the Second Law of Thermodynamics

,21 Coulomb's Law
22 Electric Fields
23 Gauss' Law
24 Electric Poten al
25 Capacitance
26 Current and Resistance
27 Circuits
28 Magne c Fields
29 Magne c Fields Due to Currents
30 Induc on and Inductance
31 Electromagne c Oscilla ons and Alterna ng Current
32 Maxwell's Equa ons; Magne sm of Ma?er
33 Electromagne c Waves
34 Images
35 Interference
36 Diffrac on
37 Rela vity
38 Photons and Ma?er Waves
39 More About Ma?er Waves
40 All About Atoms
41 Conduc on of Electricity in Solids
42 Nuclear Physics
43 Energy from the Nucleus
44 Quarks, Leptons, and the Big Bang

, Chapter 1

1. THINK In this problem we’re given the radius of Earth, and asked to compute its
circumference, surface area and volume.

EXPRESS Assuming Earth to be a sphere of radius

RE  6.37  106

 3
km m

m 10 6.37 103 km,
the corresponding circumference, surface area and volume are:
4 3
C  2 RE , A  4 RE2 , V RE .
3
The geometric formulas are given in Appendix E.

ANALỴZE (a) Using the formulas given above, we find the circumference to be

C  2 RE  2 (6.37  103 km)  4.00104 km.

(b) Similarlỵ, the surface area of Earth is


A  4RE2  4 6.37 103 km
 2  5.10 108 km2 ,
(c) and its volume is
4 3 4   3 
V RE  6.37 103 km  1.08 1012 km3 .
3 3

LEARN From the formulas given, we see that C RE , A RE2 , and V R3E . The ratios
of volume to surface area, and surface area to circumference are V / A  RE / 3 and
A / C  2RE .

2
. The conversion factors are: 1 grỵ  1/10 line , 1 line  1/12 inch and 1 point = 1/72
inch. The factors implỵ that
1 grỵ = (1/10)(1/12)(72 points) = 0.60 point.

Thus, 1 grỵ2 = (0.60 point) 2 = 0.36 point2, which means that 0.50 grỵ 2 = 0.18 point 2 .

3. The metric prefixes (micro, pico, nano, …) are given for readỵ reference on the inside
front cover of the textbook (see also Table 1–2).



1