Week 1 Test - Grade: 100%
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Click on “Start” to begin the Test.
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need to; however, the time will continue to elapse. You can also skip questions and go back to them as needed during the test. Use the 'skip'
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Questions Limits Points Due Date
15 Questions 180 Minutes 100 pts possible No due date.
Attempt 1 100% (100 of 100) Completed on 03/09/25 at 01:42AM
Score for this quiz: 100% ( 100 /100)
Submitted Mar 9 at 1:42am
This attempt took 40 minutes.
Question 1 : 6.65 ptsSkip to question text.
If −x2+x+1≤f(x)≤−x+2 for all x, find limx→1f(x).
Enter only the value of the limit in the space provided below. If the answer is not an integer, enter it as a fraction in simplest form. Do not
enter a mixed number. If the limit does not exist, enter “does not exist”.
Your Answer: 1
Correct Answer(s):
1
Since −x2+x+1≤f(x)≤−x+2, by the Squeeze Theorem, limx→1−x2+x+1≤limx→1f(x)≤limx→1−x+2 −12+1+1≤limx→1f(x)≤−1+2
1≤limx→1f(x)≤1Thus, limx→1f(x)=1.
6..65
, Question 2 : 6.65 ptsSkip to question text.
f(x)={x, x<1x+2, x≥1Evaluate limx→ 1 + f(x).
3
2
1
The one-sided limit does not exist.
The plus-sign in the limit indicates a right-handed limit. For right-handed limits, you only have to consider the domain values greater than the one
being approached in the limit. f(x)={x, x<1x+2, x≥1limx→ 1 + f(x)=limx→ 1 + (x+2)=(1+2)=3
6..65
Question 3 : 6.65 ptsSkip to question text.
After jumping out of a plane at t=0, a skydiver's altitude in the air in meters isgiven by the position functionp(t)=−50t2+200t+2350, where t
is thetime in seconds. At what time will theparachuter be 100 meters from the ground?
t = 9 or t = −5
t = 9.28
t = −477650
t=9
Set p(t)=100 and solve for t.p(t)=−50t2+200t+2350=100−50t2+200t+2250=0−t2+4t+45=0t2−4t−45=0(t−9)(t+5)=0t=9 or t=−5Since t=−5 doesn't ma
ke sense in thecontext of the problem (the skydiver jumpedout of the plane at t=0), we omit thissolution.
6..65
Question 4 : 6.65 ptsSkip to question text.
What is the change in U.S. population from July 1, 1985 to July 1, 1987?
Nat'l. Pop.
Date
Pop. Change
July 1, 272,690,8
2,442,810
1999 13
July 1, 270,248,0
2,464,396
1998 03
July 1, 267,783,6
2,555,035
1997 07
July 1, 265,228,5
2,425,296
1996 72
July 1, 262,803,2
2,476,255
1995 76
July 1, 260,327,0
2,544,413
1994 21
July 1, 257,782,6
2,752,909
1993 08
Instructions:
Click on “Start” to begin the Test.
This Test may be printed by clicking the Print icon at the top of the Test window AFTER starting the Test.
We suggest you work out the answers on the printed Test, then submit your answers online.
THIS IS A TIMED TEST. YOU HAVE 3 HOURS TO COMPLETE THE TEST ONCE YOU CLICK "START." You can start and stop the Test if you
need to; however, the time will continue to elapse. You can also skip questions and go back to them as needed during the test. Use the 'skip'
button to skip a question and question navigation pull-down menu to jump back to any questions you skipped.
Once you have completed the Test online, click “Submit Answers.” Your answers will be scored and the answer key with step-by-step
solutions will become available.
Questions? Reach out to us at . We’re here and happy to help.
Questions Limits Points Due Date
15 Questions 180 Minutes 100 pts possible No due date.
Attempt 1 100% (100 of 100) Completed on 03/09/25 at 01:42AM
Score for this quiz: 100% ( 100 /100)
Submitted Mar 9 at 1:42am
This attempt took 40 minutes.
Question 1 : 6.65 ptsSkip to question text.
If −x2+x+1≤f(x)≤−x+2 for all x, find limx→1f(x).
Enter only the value of the limit in the space provided below. If the answer is not an integer, enter it as a fraction in simplest form. Do not
enter a mixed number. If the limit does not exist, enter “does not exist”.
Your Answer: 1
Correct Answer(s):
1
Since −x2+x+1≤f(x)≤−x+2, by the Squeeze Theorem, limx→1−x2+x+1≤limx→1f(x)≤limx→1−x+2 −12+1+1≤limx→1f(x)≤−1+2
1≤limx→1f(x)≤1Thus, limx→1f(x)=1.
6..65
, Question 2 : 6.65 ptsSkip to question text.
f(x)={x, x<1x+2, x≥1Evaluate limx→ 1 + f(x).
3
2
1
The one-sided limit does not exist.
The plus-sign in the limit indicates a right-handed limit. For right-handed limits, you only have to consider the domain values greater than the one
being approached in the limit. f(x)={x, x<1x+2, x≥1limx→ 1 + f(x)=limx→ 1 + (x+2)=(1+2)=3
6..65
Question 3 : 6.65 ptsSkip to question text.
After jumping out of a plane at t=0, a skydiver's altitude in the air in meters isgiven by the position functionp(t)=−50t2+200t+2350, where t
is thetime in seconds. At what time will theparachuter be 100 meters from the ground?
t = 9 or t = −5
t = 9.28
t = −477650
t=9
Set p(t)=100 and solve for t.p(t)=−50t2+200t+2350=100−50t2+200t+2250=0−t2+4t+45=0t2−4t−45=0(t−9)(t+5)=0t=9 or t=−5Since t=−5 doesn't ma
ke sense in thecontext of the problem (the skydiver jumpedout of the plane at t=0), we omit thissolution.
6..65
Question 4 : 6.65 ptsSkip to question text.
What is the change in U.S. population from July 1, 1985 to July 1, 1987?
Nat'l. Pop.
Date
Pop. Change
July 1, 272,690,8
2,442,810
1999 13
July 1, 270,248,0
2,464,396
1998 03
July 1, 267,783,6
2,555,035
1997 07
July 1, 265,228,5
2,425,296
1996 72
July 1, 262,803,2
2,476,255
1995 76
July 1, 260,327,0
2,544,413
1994 21
July 1, 257,782,6
2,752,909
1993 08
