surname names
Number Number
Morning (Time: 1 hour 45 minutes) Paper
B ■ ■
Advanced
PAPER 2: Advanced Physiology, Evolution and Ecology
Instructions
• Use black ink or ball-point pen.
centre number and candidate number.
Answer the questions in the spaces provided –
there may be more space than you need.
Information
• The total mark for this paper is 90.
– use this as a guide as to how much time to spend on each question.
In question(s) marked with an asterisk (*), marks will be awarded for your ability to structure
your answer logically showing how the points that you make are related or follow on from each
other where appropriate.
Advice
• Read each question carefully before you start to answer it.
• Check your answers if you have time at the end.
Turn over
, Answer ALL questions.
Some questions must be answered with a cross in a box . If you change your mind about an
answer, put a line through the box and then mark your new answer with a cross .
1 The photograph shows part of a root tip cell, as seen with an electron microscope.
P
Q
X Y
S
R
(Source: © BIOPHOTO ASSOCIATES / SCIENCE PHOTO
LIBRARY)
(a) (i) Which of the following structures is surrounded by a tonoplast? (1)
A P
B Q
C R
D S
(ii) In which of the following structures does the process of translation occur? (1)
A P
B Q
C R
D S
2 ■■■■
, (iii) How many of the labelled structures in this cell will be present in a cell of an organism
in the domain Archaea?
(1)
A 0
B 1
C 2
D 3
(b) The width of structure P, measured between X and Y, is 36 μm.
Calculate the magnification of this photograph.
Give your answer in standard form.
(2)
Answer ..............................................................
3
■■■■ Turn over
, (c) Some plants have adaptations that prevent them being eaten by animals.
Sorghum is a plant that stores a substance called dhurrin inside leaf cells in the structures
labelled S in the photograph.
Dhurrin is broken down by the enzyme glucosidase to release hydrogen cyanide. Glucosidase is
stored within the chloroplasts of leaf cells.
Hydrogen cyanide inhibits aerobic respiration.
Explain why dhurrin is stored within structure S, and glucosidase is stored separately in the
chloroplasts.
(2)
. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. . . . .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. . .. ......................
. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. . . . .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. . .. .. .. .. ... .. .. .. ... .. .. .. ... ......................
. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. . . . .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. ... .. .. .. ... .. .. . . ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... ......................
. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. . . . .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. . .. ......................
. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. .. .. .. ... . . .. .. ... .. .. .. ... .. .. .. ... . . .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. . .. ......................
(Total for Question 1 = 7 marks)
4
■■■■
Number Number
Morning (Time: 1 hour 45 minutes) Paper
B ■ ■
Advanced
PAPER 2: Advanced Physiology, Evolution and Ecology
Instructions
• Use black ink or ball-point pen.
centre number and candidate number.
Answer the questions in the spaces provided –
there may be more space than you need.
Information
• The total mark for this paper is 90.
– use this as a guide as to how much time to spend on each question.
In question(s) marked with an asterisk (*), marks will be awarded for your ability to structure
your answer logically showing how the points that you make are related or follow on from each
other where appropriate.
Advice
• Read each question carefully before you start to answer it.
• Check your answers if you have time at the end.
Turn over
, Answer ALL questions.
Some questions must be answered with a cross in a box . If you change your mind about an
answer, put a line through the box and then mark your new answer with a cross .
1 The photograph shows part of a root tip cell, as seen with an electron microscope.
P
Q
X Y
S
R
(Source: © BIOPHOTO ASSOCIATES / SCIENCE PHOTO
LIBRARY)
(a) (i) Which of the following structures is surrounded by a tonoplast? (1)
A P
B Q
C R
D S
(ii) In which of the following structures does the process of translation occur? (1)
A P
B Q
C R
D S
2 ■■■■
, (iii) How many of the labelled structures in this cell will be present in a cell of an organism
in the domain Archaea?
(1)
A 0
B 1
C 2
D 3
(b) The width of structure P, measured between X and Y, is 36 μm.
Calculate the magnification of this photograph.
Give your answer in standard form.
(2)
Answer ..............................................................
3
■■■■ Turn over
, (c) Some plants have adaptations that prevent them being eaten by animals.
Sorghum is a plant that stores a substance called dhurrin inside leaf cells in the structures
labelled S in the photograph.
Dhurrin is broken down by the enzyme glucosidase to release hydrogen cyanide. Glucosidase is
stored within the chloroplasts of leaf cells.
Hydrogen cyanide inhibits aerobic respiration.
Explain why dhurrin is stored within structure S, and glucosidase is stored separately in the
chloroplasts.
(2)
. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. . . . .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. . .. ......................
. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. . . . .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. . .. .. .. .. ... .. .. .. ... .. .. .. ... ......................
. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. . . . .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. ... .. .. .. ... .. .. . . ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... ......................
. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. . . . .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. . .. ......................
. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. .. .. .. ... . . .. .. ... .. .. .. ... .. .. .. ... . . .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. ... .. .. .. . .. ......................
(Total for Question 1 = 7 marks)
4
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