100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached 4.2 TrustPilot
logo-home
Exam (elaborations)

Test Bank For Algebra and Trigonometry, 25th Edition All Chapters - 9781119778288.pdf

Rating
2.0
(1)
Sold
-
Pages
156
Grade
A+
Uploaded on
17-04-2025
Written in
2024/2025

Test Bank For Algebra and Trigonometry, 25th Edition All Chapters -

Institution
Course











Whoops! We can’t load your doc right now. Try again or contact support.

Connected book

Written for

Course

Document information

Uploaded on
April 17, 2025
Number of pages
156
Written in
2024/2025
Type
Exam (elaborations)
Contains
Questions & answers

Subjects

Content preview

DOWNLOAD THE Test Bank for Algebra and Trigonometry 6th Edition Blitzer
G G G G G G G G G G



Ch.G2 FunctionsGandGGraphs
2.1 BasicsGofGFunctionsGandGTheirGGraphs
1 FindG theG DomainG andG RangeG ofG aG Relation

MULTIPLEG CHOICE.G ChooseG theG oneG alternativeG thatG bestG completesG theG statementG orG answersG theG question.

GiveG theG domainG andG rangeG ofG theG relation.
1)G {(-5,G -5),G (-2,G -6),G (12,G 7),G (12,G -8)}
A) domainG =G{-5,G 12,G -2};G rangeG =G{-5,G 7,G -6,G -8}
B) domainG =G{-5,G 7,G -6,G -8};G rangeG =G{-5,G 12,G -2}
C) domainG =G{-5,G 12,G -2,G 22};G rangeG =G{-5,G 7,G -6,G -8}
D) domainG =G{-5,G 12,G -2,G -12};G rangeG =G{-5,G 7,G -6,G -8}

2)G {(-2,G -8),G (12,G 5),G (2,G 1),G (2,G -5)}
A) domainG =G{2,G -2,G 12};G rangeG =G{1,G -8,G 5,G -5} B)G domainG =G{2,G -2,G 12,G -2};G rangeG =G{1,G -8,G 5,G -5}
C)G domainG =G{2,G -2,G 12,G 12};G rangeG =G{1,G -8,G 5,G -5} D)G domainG =G{1,G -8,G 5,G -5};G rangeG =G{2,G -2,G 12}

3)G {(4,G 4),G (-9,G 8),G (7,G 1),G (-7,G -5)}
A) domainG=G{-7,G 4,G 7,G-9};GrangeG=G{-5,G 4,G 1,G 8}
B) domainG=G{-5,G 4,G 1,G 8};GrangeG=G{-7,G 4,G 7,G -9}
C) domainG =G{-7,G 4,G 7,G -9};G rangeG =G{-5,G -4,G 4,G 1,G 8}
D) domainG =G{-7,G 4,G 7,G -9};G rangeG =G{-5,G -5,G 4,G 1,G 8}

4)G {(-12,G 8),G (-12,G -5),G (-3,G 2),G (-10,G -8),G (6,G 3)}
A) domainG =G{-10,G 6,G -12,G -3};G rangeG =G{-8,G 3,G -5,G 2,G 8}
B) domainG =G{-10,G -4,G 6,G -12,G -3};G rangeG =G{-8,G 3,G -5,G 2,G 8}
C) domainG =G{-10,G 14,G 6,G -12,G -3};G rangeG =G{-8,G 3,G -5,G 2,G 8}
D) domainG =G{-8,G 3,G -5,G 2,G 8};G rangeG =G{-10,G -10,G 6,G -12,G -3}

5)G {(-1,G -4),G (-2,G -3),G (-2,G 0),G (7,G 3),G (23,G 5)}
A) domain:G {-1,G 7,G -2,G 23};G range:G {-4,G -3,G 0,G 3,G 5} B)G domain:G {-4,G -3,G 3,G 5};G range:G {-1,G 7,G -2,G 23}
C)G domain:G {-4,G -3,G 0,G 3,G 5};G range:G {-1,G 7,G -2,G 23} D)G domain:G {-1,G 7,G -2,G 23};G range:G {-4,G -3,G 3,G 5}

6)G {(-4,G -8),G (-12,G 8),G (-10,G 1),G (3,G -3),G (4,G 9)}
A) domainG =G{4,G -12,G 3,G -4,G -10};G rangeG =G{9,G 8,G -3,G -8,G 1}
B) domainG =G{9,G 8,G -3,G -8,G 1};G rangeG =G{4,G -12,G 3,G -4,G -10}
C) domainG =G{4,G 9,G -12,G 8,G 3};G rangeG =G{-3,G -4,G -8,G -10,G 1}
D) domainG =G{-3,G -4,G -8,G -10,G 1};G rangeG =G{4,G 9,G -12,G 8,G 3}

7)G {(-4,G 13),G (-3,G 6),G (0,G -3),G (3,G 6),G (5,G 22)}
A) domain:G {-4,G -3,G 0,G 3,G 5};G range:G {13,G 6,G -3,G 22} B)G domain:G {-4,G -3,G 3,G 5};G range:G {13,G 6,G -3,G 22}
C)G domain:G {13,G 6,G -3,G 22};G range:G {-4,G -3,G 0,G 3,G 5} D)G domain:G {13,G 6,G -3,G 22};G range:G {-4,G -3,G 3,G 5}

2 DetermineG WhetherG aG RelationG isG aG Function

MULTIPLEG CHOICE.G ChooseG theG oneG alternativeG thatG bestG completesG theG statementG orG answersG theG question.

DetermineG whetherG theG relationG isG aG function.
1)G {(-3,G 2),G (3,G -1),G (4,G 7),G (7,G -5),G (11,G 4)}
A) Function B)G NotGaGfunction

2)G {(-6,G -3),G (-2,G 3),G (-1,G -8),G (-1,G 8)}
A) NotGaGfunction B)G Function

PageG 1

mynursytest.store

,DOWNLOAD THE Test Bank for Algebra and Trigonometry 6th Edition Blitzer
G G G G G G G G G G



3)G {(-9,G 9),G (-9,G -1),G (2,G -8),G (5,G 4),G (10,G -9)}
A) NotGaGfunction B)G Function

4)G {(3,G -1),G (3,G 8),G (5,G -6),G (7,G 3),G (11,G -2)}
A) NotGaGfunction B)G Function

5)G {(-4,G 1),G (-1,G -9),G (1,G -3),G (5,G -6)}
A) Function B)G NotGaGfunction

6)G {(-9,G 5),G (-9,G -4),G (1,G -6),G (5,G -5),G (8,G -2)}
A) NotGaGfunction B)G Function

7)G {(-6,G -9),G (-4,G -8),G (1,G 6),G (3,G -9)}
A) Function B)G NotGaGfunction

8)G {(-6,G 3),G (-1,G -1),G (3,G -1),G (3,G -2)}
A) NotGaGfunction B)G Function

9)G {(-5,G 3),G (-2,G -2),G (4,G 5),G (8,G 9)}
A) Function B)G NotGaGfunction

10)G {(-3,G 7),G (2,G -9),G (4,G 1),G (8,G 5),G (11,G -1)}
A) Function B)G NotGaGfunction

3 DetermineG WhetherG anG EquationG RepresentsG aG Function

MULTIPLEG CHOICE.G ChooseG theG oneG alternativeG thatG bestG completesG theG statementG orG answersG theG question.

DetermineG whetherG theG equationG definesG yG asG aG functionG ofG x.
1) xG+GyG=G81
A) yGisG aG functionG ofG x B)G yGisG notGaGfunctionGofG x

2) 6xG+G6yG=G11
A) yGisG aG functionG ofG x B)G yGisG notGaGfunctionGofG x

3) x2G+GyG=G4
A) yGisG aG functionG ofG x B)G yGisG notGaGfunctionGofG x

4) xG+Gy2G =G49
A) yGisG aG functionG ofG x B)G yGisG notGaGfunctionGofG x

5) x2G+Gy2G=G16
A) yGisG aG functionG ofG x B)G yGisG notGaGfunctionGofG x

6) y2G=G3x
A) yGisG aG functionG ofG x B)G yGisG notGaGfunctionGofG x

7) xG=Gy2
A) yGisG aG functionG ofG x B)G yGisG notGaGfunctionGofG x

8) yG=Gx3
A) yGisG aG functionG ofG x B)G yGisG notGaGfunctionGofG x


PageG 2

mynursytest.store

,DOWNLOAD THE Test Bank for Algebra and Trigonometry 6th Edition Blitzer
G G G G G G G G G G



9) yG=G-G xG+G6
A) yGisG aG functionG ofG x B)G yGisG notGaGfunctionGofG x

10) yG=G -6xG+G5
A) yGisG aG functionG ofG x B)G yGisG notGaGfunctionGofG x

11) xG+Gy3G =G1
A) yGisG aG functionG ofG x B)G yGisG notGaGfunctionGofG x

12) xyG +G6yG=G1
A) yGisG aG functionG ofG x B)G yGisG notGaGfunctionGofG x

13) |x|G-GyG=G2
A) yGisG aG functionG ofG x B)G yGisG notGaGfunctionGofG x

4 EvaluateG aG Function

MULTIPLEG CHOICE.G ChooseG theG oneG alternativeG thatG bestG completesG theG statementG orG answersG theG question.

EvaluateG theG functionG atG theG givenG valueG ofG theG independentG variableG andG simplify.
1) f(x)G =G-6xG -G5; f(-3)
A) 13 B)G 33 C)G 23 D)G -11

2) f(x)G =Gx2G +G3; f(xG +G4)
2
A) x +G8xG+G19
G B)G x2G +G16 C)G x2G +G8xG+G16 D)G x2G +G7

3) f(x)G=G3x2G -G3xG-G5;G G f(xG -G1)
A) 3x2G -G9xG+G1 B)G -9x2G +G3xG +G1 C)G 3x2G -G9xG-G5 D)G 3x2G -G18xG-G5

4) g(x)G =G2xG +G4; g(xG-G1)
A) 2xG+G2 B)G2xG+G4 C)G 2xG+G1 G
D)G
1G
xG+G4
G2




5) h(x)G=GxG-G3G; h(16)
A) 13 B)G -19 C)G 19 D)G -13

6) f(x)G=G xG+G20; f(-4)
A) 4 B)G -4 C)G 2 D)G notGaGrealGnumber

x2G-G7G
7) f(x)G=G ;G G f(4)
x3G -G2x
G 9G G9 G9 G2
A) B) G C) G D)
56 64 62 7

x3G+G6G
8) f(x)G=G ;
f(4)
Gx2G+G4
35 16 G11
7
G B)
G
C)
G D)G
A) 8 5 10
2




PageG 3

mynursytest.store

, DOWNLOAD THE Test Bank for Algebra and Trigonometry 6th Edition Blitzer
G G G G G G G G G G



SolveG theG problem.
9) TheGfunctionGP(x)G=G0.6xG-
G89GmodelsGtheGrelationshipGbetweenGtheGnumberGofGpretzelsGxGthatGaGcertainGvendorGsellsGandGtheGprof

itGtheGvendorGmakes.GFindGP(500),GtheGprofitGtheGvendorGmakesGfromGsellingG500Gpretzels.
A) $211 B)G $300 C)G $389 D)G $411

10) TheGtotalGcostGinGdollarsGforGaGcertainGcompanyGtoGproduceGxGemptyGjarsGtoGbeGusedGbyGaGjellyGproduc
erGisGgivenGbyGtheGfunctionGC(x)G=G0.5xG+G20,000.GFindG C(50,000),GtheGcostGofGproducingG50,000G jars.
A) $45,000 B)G $25,000 C)G $20.50 D)G $50,020




PageG 4

mynursytest.store
$20.99
Get access to the full document:

100% satisfaction guarantee
Immediately available after payment
Both online and in PDF
No strings attached


Also available in package deal

Reviews from verified buyers

Showing all reviews
8 months ago

2.0

1 reviews

5
0
4
0
3
0
2
1
1
0
Trustworthy reviews on Stuvia

All reviews are made by real Stuvia users after verified purchases.

Get to know the seller

Seller avatar
Reputation scores are based on the amount of documents a seller has sold for a fee and the reviews they have received for those documents. There are three levels: Bronze, Silver and Gold. The better the reputation, the more your can rely on the quality of the sellers work.
TESTBANKSELLER Teachme2-tutor
Follow You need to be logged in order to follow users or courses
Sold
13
Member since
8 months
Number of followers
2
Documents
500
Last sold
2 weeks ago

4.8

712 reviews

5
603
4
71
3
27
2
8
1
3

Recently viewed by you

Why students choose Stuvia

Created by fellow students, verified by reviews

Quality you can trust: written by students who passed their tests and reviewed by others who've used these notes.

Didn't get what you expected? Choose another document

No worries! You can instantly pick a different document that better fits what you're looking for.

Pay as you like, start learning right away

No subscription, no commitments. Pay the way you're used to via credit card and download your PDF document instantly.

Student with book image

“Bought, downloaded, and aced it. It really can be that simple.”

Alisha Student

Frequently asked questions