IICRC Water Mitigation exam questions with
correct answers
The homeowner - verified answers; is responsible to take the necessary steps to preserve and
protect their property from further damage
Four principles of water damage restoration: - verified answers; Provide for health and safety
of workers and occupants; Document everything; Mitigate, and Dry
Four principles of drying - verified answers; Extract, Evaporate, dehumidify, control temp
Extraction - verified answers; is removing excess water and is the first step in mitigation
Evaporation - verified answers; is achieved by using energy (heat) to transform water trapped
in porous materials into a vapor, thereby releasing the moisture from the materials.
Dehumidification - verified answers; the process of removing water vapor from the air.
Rate of Dehumidification - verified answers; must be at least equal to the rate of evaporation.
True or False - verified answers; Elevated vapor pressure in a room Can cause secondary
damage to hygroscopic materials
True or False - verified answers; The control of temperature is important to enhance both
evaporation and dehumidification for effective drying
, True or False - verified answers; When temperature increases evaporation of absorbed water
increases and water vapor suspended in air also increases.
Classification of Water Intrusion - verified answers; described as Class 1, 2, 3, or 4. Must be
determined to calculate the amount of dehumidification required in drying process, based on
the amount of wet surface area, permeance/porosity of materials in drying area.
Class 1 - verified answers; is the least amount of water absorption and evaporation load,
affecting less 5% of porous materials with minimal absorption into low evaporation materials.
Class 2 - verified answers; has a significant amount of water absorption and evaporation load,
affection 5-40% porous materials, with minimal absorption into low evaporated materials
Class 3 - verified answers; has the greatest amount of water absorption and evaporation load,
affecting more than 40% porous materials and minimal absorption into low evaporated
materials
Class 4 - verified answers; has deeply held or bound water, and significant absorption into low
evaporation materials.
Determine the Class of water for a 20' x 20' x 8 ' room, with an entirely wet floor.. - verified
answers; Affected area/Total SF = % affected
400/1440 = .27777 x 100 = 28%
28% = Class 2
Determine the Class of Water for a 20' x 20' x 8' room, with only half the floor affected and
arriving within 24 hours of loss. - verified answers; Affected area/total sf = % affected
200/1440 = .13888 x 100 = 14%
14% = Class 2
correct answers
The homeowner - verified answers; is responsible to take the necessary steps to preserve and
protect their property from further damage
Four principles of water damage restoration: - verified answers; Provide for health and safety
of workers and occupants; Document everything; Mitigate, and Dry
Four principles of drying - verified answers; Extract, Evaporate, dehumidify, control temp
Extraction - verified answers; is removing excess water and is the first step in mitigation
Evaporation - verified answers; is achieved by using energy (heat) to transform water trapped
in porous materials into a vapor, thereby releasing the moisture from the materials.
Dehumidification - verified answers; the process of removing water vapor from the air.
Rate of Dehumidification - verified answers; must be at least equal to the rate of evaporation.
True or False - verified answers; Elevated vapor pressure in a room Can cause secondary
damage to hygroscopic materials
True or False - verified answers; The control of temperature is important to enhance both
evaporation and dehumidification for effective drying
, True or False - verified answers; When temperature increases evaporation of absorbed water
increases and water vapor suspended in air also increases.
Classification of Water Intrusion - verified answers; described as Class 1, 2, 3, or 4. Must be
determined to calculate the amount of dehumidification required in drying process, based on
the amount of wet surface area, permeance/porosity of materials in drying area.
Class 1 - verified answers; is the least amount of water absorption and evaporation load,
affecting less 5% of porous materials with minimal absorption into low evaporation materials.
Class 2 - verified answers; has a significant amount of water absorption and evaporation load,
affection 5-40% porous materials, with minimal absorption into low evaporated materials
Class 3 - verified answers; has the greatest amount of water absorption and evaporation load,
affecting more than 40% porous materials and minimal absorption into low evaporated
materials
Class 4 - verified answers; has deeply held or bound water, and significant absorption into low
evaporation materials.
Determine the Class of water for a 20' x 20' x 8 ' room, with an entirely wet floor.. - verified
answers; Affected area/Total SF = % affected
400/1440 = .27777 x 100 = 28%
28% = Class 2
Determine the Class of Water for a 20' x 20' x 8' room, with only half the floor affected and
arriving within 24 hours of loss. - verified answers; Affected area/total sf = % affected
200/1440 = .13888 x 100 = 14%
14% = Class 2
