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BRAE 340 Exam 1 Questions and Answers 100% Solved

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BRAE 340 Exam 1 Questions and Answers 100% Solved An elevated water tank is used to feed water into a drip system. How high (ft) must the tank outlet be in order to cause a 31 psi pressure at the inlet of the drip system? Correct Answ_psi x 2.31 ft/psi = ft The correct answer is: 71.6 What concentration (ppm) is equivalent to a soil moisture tension of 1.5 bars? Correct Answ_bars x 100 = cb cb x 1dS/m/30 cb = dS/m dS/m x 700 ppm/1 dS/m = ppm The correct answer is: 3500

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BRAE 340

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BRAE 340 Exam 1 Questions and Answers
100% Solved

An elevated water tank is used to feed water into a drip system. How high (ft) must the tank

outlet be in order to cause a 31 psi pressure at the inlet of the drip system? Correct Answ_psi

x 2.31 ft/psi = ft

The correct answer is: 71.6




What concentration (ppm) is equivalent to a soil moisture tension of 1.5 bars? Correct

Answ_bars x 100 = cb

cb x 1dS/m/30 cb = dS/m

dS/m x 700 ppm/1 dS/m = ppm

The correct answer is: 3500




What salinity (ds/m) is equivalent to a soil moisture tension of 0.34 bars? Correct Answ_1

bar = 100 centibars (cb); 1 dS/m ≈ 30 cb

bars x 100 = cb x 1 dS/m/30 cb = dS/m

The correct answer is: 1.13 dS/m

,If a soil has a moisture tension of 0.17 bars and the salinity of the soil water is 1.48 dS/m, what is

the total tension experienced by the plant roots? That is, what is the sum of the moisture tension

and the osmotic (due to salinity) tension? Correct Answ_moisture tension = bars x 100

cb/bar = cb

osmotic tension = dS/m x 30 cb/(1 dS/m) = cb

total tension = moisture tension (cb) + osmotic tension (cb)

The correct answer is: 61 cb




What pumping rate (CFS) is required to deliver 63 acre-inches in 20 hours? Correct

Answ_rate = amount ÷ time

rate = ac-in/hr x 1 CFS/1 ac-in/hr = CFS

The correct answer is: 3.15




An alfalfa crop uses 0.38 inches per day. How many days will it take to extract 4.42 inches from

the soil? Correct Answ_Time = amount (in)/ rate (in/day) = days


The correct answer is: 11.6




What is the average depth applied (inches) to a 9 acre level basin if the irrigation pump runs at 11

CFS for 4 hours? Correct Answ_1 CFS ≈ 1 ac-in/hr

, ac-in/hr x hours = ac-in

ac-in ÷ acre = inches

The correct answer is: 4.89




A rain gauge is constructed of a funnel with diameter D = 4 inches, fixed to the top of a tube with

diameter d = 1 inches (see drawing). Rain water stands 3.38 inches high in the bottom of the

tube. How much rainfall does that indicate? Correct Answ_Volume in tube = column x tube

area

Tube area = ∏ d2/4 = sq-in

Volume in tube = rainfall (in) x tube area = cu-in

Rain depth = volume in tube (cu-in) ÷ top funnel area (sq-in)

The correct answer is: 0.21 inches




A pump delivers a gross flow rate of 2.7 CFS to a 9 acre field for 9 hours. The irrigation

efficiency is 74%. What is the net amount of water benefiting the crop? Correct Answ_CFS x

60 sec/1 min x 60 min/1 hr = cu-ft/hr

cu-ft/hr x hours x 1 ac/43560 sq-ft = ac-ft

ac-ft / acres x 12 in/ft = inches gross (this is a gross amount because it is coming from the pump)

Net = Gross (in) x (IE/100) = inches net

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