with solutions 2025
Which of the following code blocks produces the output given below?['odd', 'even', 'odd',
'even'] - ANSWER new_list = [3, 4, 5, 6]
for i in range(len(new_list)):
if new_list[i] % 2 == 0:
new_list[i] = 'even'
else:
new_list[i] = 'odd'
print(new_list)
Select the output generated by the following code:
new_list = [10, 10, 20, 20, 30, 40]
for i in range(3):
print(new_list[i])
new_value = new_list.pop(0) - ANSWER 10
20
30
What is output?
new_list = [10, 20, 30, 40]
for i in new_list[:]:
print(i)
new_value = new_list.pop(0) - ANSWER 10
,20
30
40
What is output?
b1 = [7, 5, 9, 6]
b1 = sorted(b1)
b2 = b1
b2.append(2)
print(b1, b2) - ANSWER [5, 6, 7, 9, 2] [5, 6, 7, 9, 2]
What is output?
b1 = [7, 5, 9, 6]
b1.sort()
b2 = b1.copy()
b1.append(10)
b2 = b2[::-1]
print(b1, b2) - ANSWER [5, 6, 7, 9, 10] [9, 7, 6, 5]
What is output?
b1 = [[7, 5, 9], [3, 2, 1]]
b1.sort()
b2 = b1[:]
,print(b1, b2)
for elem in b2:
elem.sort()
print(b1, b2) - ANSWER [[3, 2, 1], [7, 5, 9]] [[3, 2, 1], [7, 5, 9]]
[[1, 2, 3], [5, 7, 9]] [[1, 2, 3], [5, 7, 9]]
Which of the following options can sort the list in descending order?
i. list_name.sort(reverse=True)
ii. sorted(list_name, reverse=True)
iii. sorted(list_name)[::-1]
iv. sorted(list_name) - ANSWER i, ii, iii
What will be the date type for type(list_name.sort())
and type(sorted(list_name))? - ANSWER < class 'NoneType'>, < class 'list'>
Which of the following statements is incorrect for python dictionaries? - ANSWER Dictionaries
cannot contain objects of arbitrary type
What is the length of the dictionary my_dict = {'Country':'India', 'State': {'City':'Delhi',
'Temperature':40}}? - ANSWER 2
After the program runs, what is the value of y?
def print_sum(num1, num2)print(num1 + num2)y = print_sum(4, 5) - ANSWER 9
, Select the option to get the value of temperature from the dictionary my_dict =
{'Country':'India', 'State': {'City':'Delhi', 'Temperature':40}} - ANSWER
my_dict['State']['Temperature']
What is output?
my_dict = {'AA':3, 'BB': 2, 'CC':1, 'DD':0}
v1 = list(my_dict.keys())[list(my_dict.values()).index(1)]
v2 = {v:k for k, v in my_dict.items()}[0]
print(v1,v2) - ANSWER CC DD
What is output?
dict = {1: 'X', 2: 'Y', 3: 'Z'}print(dict.get(2, 'A')) - ANSWER Y
What is output?
objects = {}objects['a'] = 'Chair'objects['b'] = 'Table'objects['c'] =
'Sofa'objects.clear()print(objects) - ANSWER {}
What is output?
dict1 = {1: 'Hi', 2: 'Bye'}dict2 = {2: 'Yes'}dict1.update(dict2)dict3 = {3:
'No'}dict1.update(dict3)print(dict1) - ANSWER {1: 'Hi', 2: 'Yes', 3: 'No'}
What is the value of rgb_a?