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ALEKS Basic Math Placement Test Review Questions Well Answered.

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how to find domain with a given equation - Answer -if a fraction, set denom. to zero, then solve -in equation, plug in 0 for x *usually can be a + or - solution* (-) + (-)= ... (-) x (-)= ... (-) divided by a (-)= ... - Answer (-) (+) (+) quotient - Answer division adding and subtracting fractions - Answer -make denoms the same -add/subtract numerators multiplying fractions - Answer just multiply numerators across and denoms across and simplify dividing fraction - Answer multiply by reciprocal (change second fraction to reciprocal) multiplying/dividing/adding mixed fractions - Answer turn them into regular fractions (multiplying # by denom, adding it to num, keeping denom the same) and continue subtracting mixed fractions - Answer *first: make denoms the same* set up as if you're subtracting two large numbers (on top and on bottom) how to solve problems like 5-2 (1/3) - Answer 1) make problem 5- (2 (1/3))

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ALEKS Basic Math Placement Test
Review Questions Well Answered.
how to find domain with a given equation - Answer -if a fraction, set denom. to zero, then solve

-in equation, plug in 0 for x

*usually can be a + or - solution*



(-) + (-)= ...

(-) x (-)= ...

(-) divided by a (-)= ... - Answer (-)

(+)

(+)



quotient - Answer division



adding and subtracting fractions - Answer -make denoms the same

-add/subtract numerators



multiplying fractions - Answer just multiply numerators across and denoms across and simplify



dividing fraction - Answer multiply by reciprocal (change second fraction to reciprocal)



multiplying/dividing/adding mixed fractions - Answer turn them into regular fractions (multiplying # by
denom, adding it to num, keeping denom the same) and continue



subtracting mixed fractions - Answer *first: make denoms the same*

set up as if you're subtracting two large numbers (on top and on bottom)



how to solve problems like 5-2 (1/3) - Answer 1) make problem 5- (2 (1/3))

, 2) separate : 5- 2- (1/3) to get: 3- (1/3)

3) rewrite whole #: 2+1- (1/3)

4) rewrite as: 2 + (3/3) - (1/3) to ed up with:

2 (2/3)



inequality problem rule (<, >, etc like problems) - Answer When *multiplying/dividing* each side by a
*positive* number, the inequality sign *stays the same*



When *multiplying/dividing* each side by a *negative* number, we *flip* the inequality sign.



area and circumference of circle - Answer A= pi x r^2

C= 2 x pi x r



area and perimeter of a triangle - Answer A= (1/2)bh (unit squared)

P= side+side+ side



Volume and surface area of a rectangular prism - Answer V=lwh (unit to the 3rd power)

SA= 2(wl + hl+ hw)



distance formula - Answer d= rate x time



percent to fraction - Answer percent as numerator and 100 as denominator, then simplify



fraction to percent - Answer 1) do long division with denom as outside and numerator as inside

2) move decimal over 2 places to make it into a %

*do not forget decimal*

ORRRR

make denom 100 (multiply num and denom of original fraction by whatever to get it to 100)

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