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Exam (elaborations)

Test Bank for Fundamentals of Physics 10th Edition by Resnick, Walker and Halliday

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TEST BANK For Fundamentals of Physics 10th Edition By Resnick, Walker and Halliday Chapters 1 - 44 ChapterR 1 1. VariousRgeometricRformulasRareRgivenRinRAppendixRE. (a) ExpressingRtheRradiusRofRtheREarthRas RRR 6.37RR106 Rm103 RkmRmR R6.37RR103 Rkm, itsRcircumferenceRisRsRR2RRRR2R(6.37RR103 Rkm)RR4.00R104 Rkm. (b) TheRsurfaceRareaRofREarthRisRARR4R R2 R4R 6.37RR103 RRkm 2 R5.10RR10 8 km2. (c)RTheRvolumeRofREarthRisRVRR 4RRR3 RRRR 4R6.37RR103 RRkm3RRRR1.08RR1012 RRkm3. 3 3 2. TheRconversionRfactorsRare:R1RgryRR1/10RlineR,R1RlineRR1/12RinchRandR1RpointR=R 1/72Rinch.RTheRfactorsRimplyRthat 1RgryR=R(1/10)(1/12)(72Rpoints)R=R0.60Rpoint. Thus,R1Rgry2 R=R(0.60Rpoint)2 R=R0.36Rpoint2,RwhichRmeansRthatR0.50Rgry2 R=R0.18Rpoint2 R. 3. TheRmetricRprefixesR(micro,Rpico,Rnano,R…)RareRgivenRforRreadyRreferenceRonRtheRins ideRfrontRcoverRofRtheRtextbookR(seeRalsoRTableR1–2). (a)RSinceR1RkmR=R1RR103 RmRandR1RmR=R1RR106 R m, 1kmRR103 RmRR 103 Rm1 06 RmRmR R10 9 m. TheRgivenRmeasurementRisR1.0RkmR(twoRsignificantRfigures),RwhichRimpliesRourRres ultRshouldRbeRwrittenRasR1.0RR109 R m. (b)R WeR calculateR WeR concludeR 4 .R (c)R SinceR theR numberR ofR 1cmR =R micronsR inR 1R centimeter.R SinceR 1R 102 RmR=R 102m106 R RmR mR R1 04 thatR theR fractionR ofR oneR centimeterR equalR toR 1.0R cmR =R 102 Rm, m. mRisR1.0RR10 1R ydR =R (3R ft)(0.3048R m/ft)R =R 0.9144R m, 1 2 CHAPTERR1 12 48 1.0RydR=R 0.91m106 R RmRmR R9.1RR1 05 m. 4. (a)RUsingRtheRconversionRfactorsR1RinchR=R2.54RcmRexactlyRandR6RpicasR=R1Rinch,R weRobtain 0.80RcmR=R 0.80RcmR   1Rinch R6RpicasR RR1.9Rpicas. R2.54RcmR R1RinchR    (b)RWithR12RpointsR=R1Rpica,RweRha ve     0.80RcmR=R 0.80RcmR   1Rinch R6RpicasR R12RpointsR RR23Rpoints. R2.54RcmR R1RinchR RR1Rpica        5. GivenRthatR1Rfurlon g R201.168RmR,R1RrodRR5.0292R m andR1RchainRR20.117RmR,RweRfind theRrelevantRconversionRfactorsRtoRbe 1.0RfurlongRR201.168RmRR(201.168R mR) and 1Rrod 5.0292 R40Rrods, 1.0RfurlongRR201.168RmRR(201.168Rm R) 1Rchain 20.117R m 10RchainsR. NoteRtheRcancellationRofRmR(meters),RtheRunwantedRunit.RUsingRtheRgivenRconversi onRfactors,RweRfind (a) theRdistanceRdRinRrodsRtoRbe dRR4.0RfurlongsR4.0RfurlongsR 40Rrod s 1Rfurlong R160Rrods, (b) andRthatRdistanceRinRchainsRtoRbe dRR4.0RfurlongsR4.0Rfurlongs10RchainsRR40Rchains. 1Rfurlong 6. WeRmakeRuseRofRTableR1-6. (a) WeRlookRatRtheRfirstR(―cahiz‖)Rcolumn:R1RfanegaRisRequivalentRtoRwhatRamountRofRcah iz?RWeRnoteRfromRtheRalreadyRcompletedRpartRofRtheRtableRthatR1RcahizRequalsRaRdozenRfa nega.RThus,R1RfanegaR=R 1 Rcahiz,RorR8.33RR102 Rcahiz.RS

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