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Examen

NS FL 2 C/P FREE STANDING QUESTIONS WITH ACCURATE ANSWERS

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A climber using bottled oxygen accidentally drops the oxygen bottle from an altitude of 4500 m. If the bottle fell straight down this entire distance, what is the velocity of the 3kg bottle just prior to impact at sea level? (Note: ignore air resistance) A. 300 m/s B. 150 m/s C. 30 m/s D. 3 m/s - As an object falls, the kinetic energy (KE) that it gains is equal to the potential energy (PE) that it loses. Thus, for this object, we can say that 1/2m(vfinal)2 = mgΔh, where g ~ 10 m/s2: ½(3) (vfinal)2 = 3(10) (4500) (vfinal)2 = (10)(4500)(2) (vfinal)2 = 9 x 104 vfinal = 3 x 102 m/s = 300 m/s What is the approximate partial pressure of oxygen at 1500 m? A. 0.09 atm B. 0.11 atm C. 0.15 atm D. 0.18 atm - Table 1 shows the barometric pressure at 1500 m = 641 mmHg or 85 kPa. From the conversion that 1 atm = 760 mm Hg = 105 Pa, we can calculate that the pressure at 1500 m will be 0.84 atm. Paragraph two states that air is 21% oxygen, meaning that ~ 21% of the 0.84 atm will be due to oxygen (according to Dalton's law of partial pressures). 0.84 atm x 0.21 = 0.176 atm ~ 0.18 atm. Homotropic regulation - Homotropic regulation is when a molecule serves as a substrate for its target enzyme, as well as a regulatory molecule of the enzyme's activity. O2 is a homotropic allosteric modulator of hemoglobin. The four subunits of hemoglobin actually bind to oxygen cooperatively, meaning the binding of oxygen to one of the four subunits will increase the likelihood that the remaining sites will bind with oxygen as well. This is the cause of the sigmoidal curve in oxygen-Hb curve

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Institución
NS FL 2 C/P
Grado
NS FL 2 C/P

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Subido en
6 de febrero de 2025
Número de páginas
10
Escrito en
2024/2025
Tipo
Examen
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NS FL 2 C/P FREE STANDING
QUESTIONS WITH ACCURATE
ANSWERS
A climber using bottled oxygen accidentally drops the oxygen bottle from an altitude of
4500 m. If the bottle fell straight down this entire distance, what is the velocity of the 3-
kg bottle just prior to impact at sea level? (Note: ignore air resistance)

A. 300 m/s
B. 150 m/s
C. 30 m/s
D. 3 m/s - ✔✔As an object falls, the kinetic energy (KE) that it gains is equal to the
potential energy (PE) that it loses. Thus, for this object, we can say that 1/2m(vfinal)2 =
mgΔh, where g ~ 10 m/s2:

½(3) (vfinal)2 = 3(10) (4500)

(vfinal)2 = (10)(4500)(2)

(vfinal)2 = 9 x 104

vfinal = 3 x 102 m/s = 300 m/s

What is the approximate partial pressure of oxygen at 1500 m?

A. 0.09 atm
B. 0.11 atm
C. 0.15 atm
D. 0.18 atm - ✔✔Table 1 shows the barometric pressure at 1500 m = 641 mmHg or 85
kPa. From the conversion that 1 atm = 760 mm Hg = 105 Pa, we can calculate that the
pressure at 1500 m will be 0.84 atm. Paragraph two states that air is 21% oxygen,
meaning that ~ 21% of the 0.84 atm will be due to oxygen (according to Dalton's law of
partial pressures). 0.84 atm x 0.21 = 0.176 atm ~ 0.18 atm.

Homotropic regulation - ✔✔Homotropic regulation is when a molecule serves as a
substrate for its target enzyme, as well as a regulatory molecule of the enzyme's
activity. O2 is a homotropic allosteric modulator of hemoglobin. The four subunits of
hemoglobin actually bind to oxygen cooperatively, meaning the binding of oxygen to
one of the four subunits will increase the likelihood that the remaining sites will bind with
oxygen as well. This is the cause of the sigmoidal curve in oxygen-Hb curve

, Remember: Chain formation is not a property of oxygen and it cannot have " Dissolved
oxygen forms a chain of atoms that is easier for Hb to bind."

The kinetic molecular theory of gases states that gaseous mixtures do not act differently
from pure gases - ✔✔T

Fluid pressure changes with depth are assumed to be linear. Which statement best
explains why this does not hold true for atmospheric pressure changes?

A.
At very high temperatures, air behaves less ideally.
B.
The volume of a mass of air is not constant.
C.
The majority of molecules in air are nonpolar.
D.
Air is not of a uniform composition. - ✔✔B

Remember volume of gas is not constant

While the composition of oxygen and nitrogen in air does not change with altitude, the
decreasing temperature at high altitude does change the percent of air that is composed
of H2O. Assuming constant relative humidity, which of the following can be asserted
about the total grams of H2O in a given volume of air at 3000 m above sea level versus
at sea level?

A.
Assuming constant relative humidity means that air has roughly the same mass of H2O
per unit volume at 3000 m above sea level.
B.
Whether air at very high altitude has more or less mass of H2O per unit volume than it
does at sea level depends on the temperature at high altitude.
C.
Air has significantly more mass of H2O per unit volume at 3000 m above sea level.
D.
Air has significantly less mass of H2O per unit volume at 3000 m above sea level. -
✔✔With decreasing temperature, air is able to hold less H2O. Since colder air can hold
less total H2O, this means the same relative humidity would result in less total water in
the air.

This might be due to less solubility in low temperature and thus less water available and
thus less humid

At STP, each mole of gas evolved occupies 22.4 L of volume. - ✔✔T
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