Lucy Kerr Part B
1084899
.
Physics 1080 Lab #4 2) 1 c or 294K 2) c or 294K
Part A .
Oil #30 Radius ofSmall sphere 5684 Pa 5390 Pa
distance
change 9 nu 0 0167
. cmils 0 0202
.
cm'Is
velocity= time
change ~ =
2g/ppread Poil) -
20 -
10
= 0 0016916
.
0 . 01328
(4 73) .
-
(2 37) .
=19036On a
.
= 4 23 .
um/s/100
Sample Calculation
V2o-10 =
0 0423 m/s
Question: If you were to break the 64 mm capillary in half and
repeat the flow rate measurement with water, how would your
.
= 1 247 mm
Q1 4 AP measured values change?
.
=
~ =
(Pbread -
Pfluid) -
g
.
D2 Q2 r" AP2
18 N
=100 (DDI Poiseuille's Law states that the flow rate is inversely
rz proportional to the capillary's length, therefore if you split the
= r
(2150 -
875)(9 81)(4 . .
66x10-3)2 ,
0 . 042 =
18N 64 mm capillary in half and repeat the flow rate measurement
N =
(1275)(9 811 (4 . . 66 x 10
-
3)2
= 1 26 7 mm
.
=
r( using water, the flow rate Q would rise. When the length is cut
(18) (0 042) .
in half, the fluid may move more freely because to the
=
0 366 . Pas
(1 247)
. + (1 267)
.
= 10 .
17) x(0 .0202) decreased barrier to flow, which nearly doubles the flow rate.
Taug =
2
= 0 .
1949mm
Oil #SO
= 1 . 257mm = 0 . 195mm
20 -
10
=
(9 47 .
-
4 76).
= 2 12 cm/s/100
Based on your results discuss how well Poiseuille's law applied to the movement of
.
Vao-10 =
0 0212
.
mis fluids through capillary tubes due to a pressure differential. Discuss any limitations
of the lab and any suggested improvements.
~ =
(Pbread -
Pfluid) -
g
.
D2
18 N
Given that the flow rate Q clearly depended on the capillary length and radius, in accordance
890) (9 81)(4 66x10-3)2
12150
with the theoretical model, the results suggest that Poiseuille's Law describes the flow of
-
. .
0 042 =
18 N
fluids through capillary tubes under a pressure difference. Nevertheless, the experiment
.
3)2
11260)(9 811(4 66x10
probably had flaws that affected how accurate our measurements were. As the fluid flowed,
-
. .
u =
(18) 10 021(
the reservoir's liquid height gradually decreased, changing the pressure over time and making
.
= 0 723. Pas it difficult to maintain a steady pressure differential. Inaccuracies may also be introduced by
tiny leaks, misaligned capillaries, or temperature changes that gently alter viscosity.
Using a more regulated pressure source, like a pump, would assist keep the pressure
differential steady and enhance the lab. Using capillaries with more accurate measurements
and using temperature control to guarantee constant viscosity could be two more
enhancements. Reducing human error in flow rate recording may also be possible with more
precise timing devices. All things considered, Poiseuille's Law offers a solid theoretical
foundation, but these real-world drawbacks emphasize the necessity of meticulous control in
experimental settings to provide reliable results.
1084899
.
Physics 1080 Lab #4 2) 1 c or 294K 2) c or 294K
Part A .
Oil #30 Radius ofSmall sphere 5684 Pa 5390 Pa
distance
change 9 nu 0 0167
. cmils 0 0202
.
cm'Is
velocity= time
change ~ =
2g/ppread Poil) -
20 -
10
= 0 0016916
.
0 . 01328
(4 73) .
-
(2 37) .
=19036On a
.
= 4 23 .
um/s/100
Sample Calculation
V2o-10 =
0 0423 m/s
Question: If you were to break the 64 mm capillary in half and
repeat the flow rate measurement with water, how would your
.
= 1 247 mm
Q1 4 AP measured values change?
.
=
~ =
(Pbread -
Pfluid) -
g
.
D2 Q2 r" AP2
18 N
=100 (DDI Poiseuille's Law states that the flow rate is inversely
rz proportional to the capillary's length, therefore if you split the
= r
(2150 -
875)(9 81)(4 . .
66x10-3)2 ,
0 . 042 =
18N 64 mm capillary in half and repeat the flow rate measurement
N =
(1275)(9 811 (4 . . 66 x 10
-
3)2
= 1 26 7 mm
.
=
r( using water, the flow rate Q would rise. When the length is cut
(18) (0 042) .
in half, the fluid may move more freely because to the
=
0 366 . Pas
(1 247)
. + (1 267)
.
= 10 .
17) x(0 .0202) decreased barrier to flow, which nearly doubles the flow rate.
Taug =
2
= 0 .
1949mm
Oil #SO
= 1 . 257mm = 0 . 195mm
20 -
10
=
(9 47 .
-
4 76).
= 2 12 cm/s/100
Based on your results discuss how well Poiseuille's law applied to the movement of
.
Vao-10 =
0 0212
.
mis fluids through capillary tubes due to a pressure differential. Discuss any limitations
of the lab and any suggested improvements.
~ =
(Pbread -
Pfluid) -
g
.
D2
18 N
Given that the flow rate Q clearly depended on the capillary length and radius, in accordance
890) (9 81)(4 66x10-3)2
12150
with the theoretical model, the results suggest that Poiseuille's Law describes the flow of
-
. .
0 042 =
18 N
fluids through capillary tubes under a pressure difference. Nevertheless, the experiment
.
3)2
11260)(9 811(4 66x10
probably had flaws that affected how accurate our measurements were. As the fluid flowed,
-
. .
u =
(18) 10 021(
the reservoir's liquid height gradually decreased, changing the pressure over time and making
.
= 0 723. Pas it difficult to maintain a steady pressure differential. Inaccuracies may also be introduced by
tiny leaks, misaligned capillaries, or temperature changes that gently alter viscosity.
Using a more regulated pressure source, like a pump, would assist keep the pressure
differential steady and enhance the lab. Using capillaries with more accurate measurements
and using temperature control to guarantee constant viscosity could be two more
enhancements. Reducing human error in flow rate recording may also be possible with more
precise timing devices. All things considered, Poiseuille's Law offers a solid theoretical
foundation, but these real-world drawbacks emphasize the necessity of meticulous control in
experimental settings to provide reliable results.
