Questions and Answers 100% Pass
Toggle hangers shall be permitted only for the support of pipe __________
inches or smaller in size under ceilings of hollow tile or metal lath and
plaster. - ANSWER✔✔-1 2/2 in. (ref. NFPA 13 2016 Sec. 9.2.1.1.2.
While conducting a flow test, the chosen hydrant should be ______ -
ANSWER✔✔-As close to the property where the sprinkler system is being
installed. (Ref, NFPA 13 Sec. A.24.2.2. or NFPA 291)
What formula is used to determine the discharge coefficiant relating
pressure and flow rate? - ANSWER✔✔-K = Q / (Square root of P)
What best describes a tree system? - ANSWER✔✔-Cross mains and the
branch lines are not tied together, providing only one path of water flow.
Factors that define Occupancy Group Hazard 2 include: - ANSWER✔✔-
Quantity and combustibility of contents are moderate to high.
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,Stockpiles of contents with moderate rates of heat release do not exceed 12
ft and stockpiles with high heat release do not exceed 8 ft
(Ref NFPA 13 Sec. 5.3.2)
Which of the following standards contain reqs. pertaining to the
installation of underground piping? - ANSWER✔✔-NFPA 13 & 24 (Both in
Chapter 10)
Which of the following should you inspect on an extension cord before
each use? - ANSWER✔✔-The grounding prong & the insulation for nicks,
cuts, or damage
________ indicates a mandatory req. according to NFPA definitions. -
ANSWER✔✔-Shall.
(Ref. NFPA 13 2016, Sec. 3.2.4.)
100 GPM is flowing through 100' of 1 1/4 in. Sch. 40 pipe. How many feet
of 1 1/2 in. pipe will produce the same friction loss? - ANSWER✔✔-
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, Assume this is Schedule 40 pipe, C = 120. Use the Hazen-Williams formula
to calculate the friction loss for the 1 ¼ in. pipe and the 1 ½ in. pipe.
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
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