Limestone does NOT decompose when heated to 900 K due to the fact, at 900 K, ΔH is:
A.
Nice and less than TΔS.
B.
Superb and extra than TΔS.
C.
Terrible and much less than TΔS.
D.
Bad and greater than TΔS.
Does not decompose = not spontaneous!!
Consequently delta S desires to be - and delta H is +
B
effective S approach that it will be spontaneous
therefore we need S to be negative
When limestone is heated at some stage in Step 1, an equilibrium is installed. Which of the
subsequent expressions is the equilibrium regular for the decomposition of limestone?
A.
[CaO]
B.
[CaCO3]
C.
[CO2]
D.
[CaO] × [CaCO3]
whilst writing Keq, NEVER encompass solids or beverages in the equation
,handiest encompass aq or gasoline
Keq = [product]/[reactant]
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During Reaction 2, did the oxidation nation of N change?
A.
Yes; it changed from -3 to -four.
B.
Yes; it changed from 0 to +1.
C.
No; it remained at -3.
D.
No; it remained at +1.
Consider a way to discover the oxidation kingdom!
Trace, for the ion you're looking for, have that has the X variable!
NH3
(x) + (3) = 0
x =-three
NH4+
x + (4) = +1
x = -three
If all of Gas X (from Step 6) is held in a sealed chamber at STP, what will be its approximate
volume?
, A. 22.4 L
B. 44.8 L
C. 67.2 L
D. 89.6 L
1 mol = 22.4 L
Why became it vital that the cuvettes containing the glucose oxidase and the blood sample were
same in terms of optical houses?
A. To permit the contrast of the absorption spectra
B. To lessen the absorption within the glass partitions
C. To decrease the uncertainty within the wavelength
D. To increase the absorption in the answers
Passage: "a blood sample with 1/30 dilution ratio become mixed in a transparent cuvette with an
oxygen-acceptor solution containing glucose oxidase."
curvettes in spectroscopy
they're measuring absorbance!! Therefore we want to have a "reference" the use of the curvette
A! To enable the evaluation of the absorption spectra
What is the approximate strength of a photon inside the absorbed radiation that yielded the
statistics in Table 1?
(Note: Use 1 eV = 1.6 × 10–19 J and hc = 19.8 × 10–26 J•m.)
A. 1 eV
B. 2 eV
C. Three eV
D. 4 eV
plug it into E=hc/lambda, then divide it through the 1eV conversion
2 eV
According to Table 1, what's the awareness of the glucose in the blood from which the diluted
pattern became taken?
A. 60 mg/dL