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ALEKS Basic Math Placement Test Review UPDATED Exam Questions and CORRECT Answers

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ALEKS Basic Math Placement Test Review UPDATED Exam Questions and CORRECT Answers how to find domain with a given equation - Correct Answer- -if a fraction, set denom. to zero, then solve -in equation, plug in 0 for x *usually can be a + or - solution* (-) + (-)= ... (-) x (-)= ... (-) divided by a (-)= ... - Correct Answer- (-) (+) (+) quotient - Correct Answer- division

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ALEKS Basic Math Placement
Course
ALEKS Basic Math Placement

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ALEKS Basic Math Placement Test Review
UPDATED Exam Questions and
CORRECT Answers

how to find domain with a given equation - Correct Answer- -if a fraction, set denom. to zero,
then solve
-in equation, plug in 0 for x
*usually can be a + or - solution*


(-) + (-)= ...
(-) x (-)= ...
(-) divided by a (-)= ... - Correct Answer- (-)
(+)
(+)


quotient - Correct Answer- division


adding and subtracting fractions - Correct Answer- -make denoms the same
-add/subtract numerators


multiplying fractions - Correct Answer- just multiply numerators across and denoms across
and simplify


dividing fraction - Correct Answer- multiply by reciprocal (change second fraction to
reciprocal)


multiplying/dividing/adding mixed fractions - Correct Answer- turn them into regular
fractions (multiplying # by denom, adding it to num, keeping denom the same) and continue


subtracting mixed fractions - Correct Answer- *first: make denoms the same*
set up as if you're subtracting two large numbers (on top and on bottom)

, how to solve problems like 5-2 (1/3) - Correct Answer- 1) make problem 5- (2 (1/3))
2) separate : 5- 2- (1/3) to get: 3- (1/3)
3) rewrite whole #: 2+1- (1/3)
4) rewrite as: 2 + (3/3) - (1/3) to ed up with:
2 (2/3)


inequality problem rule (<, >, etc like problems) - Correct Answer- When
*multiplying/dividing* each side by a *positive* number, the inequality sign *stays the
same*


When *multiplying/dividing* each side by a *negative* number, we *flip* the inequality
sign.


area and circumference of circle - Correct Answer- A= pi x r^2
C= 2 x pi x r


area and perimeter of a triangle - Correct Answer- A= (1/2)bh (unit squared)
P= side+side+ side


Volume and surface area of a rectangular prism - Correct Answer- V=lwh (unit to the 3rd
power)
SA= 2(wl + hl+ hw)


distance formula - Correct Answer- d= rate x time


percent to fraction - Correct Answer- percent as numerator and 100 as denominator, then
simplify


fraction to percent - Correct Answer- 1) do long division with denom as outside and
numerator as inside
2) move decimal over 2 places to make it into a %

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ALEKS Basic Math Placement
Course
ALEKS Basic Math Placement

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