Math 120 Final with correct answers 100 %

The Frisbee outlet store has marginal cost of $59 for a box of Frisbee's and has a fixed monthly cost of $800. The outlet sells a box of Frisbee's of $89. 1. Let x represent the number of boxes and P(x) represent the corresponding monthly profit in dollars. Find the profit function. 2. How man boxes of Frisbee's should be sold to break even? 3. How many boxes of Frisbee's should be sold to make a profit of $1800? - Correct Answer Solution 1: C(x): 59x+1800 R(x): 89x P(x): R(x)-C(x) P(x): 30x-1800 Solution 2: Set P(x)=0 ; 0=30x-1800 > 1800=30x > x=60 You must sell 60 boxes to break even Solution 3: P(x)=30x-1800 ; 1800=30x-1800 > 3600=30x > x=120 You must sell 120 boxes. The Pepsi company is willing to supply ten 12-pks for $3 each and thirty five 12-pks for $4 each. The demand for the sodas (q) is given by q=-20p+100 where (p) is the price per 12-pk 4. Find the linear supply function in the form of (q=mp+b) where q is the number of 12-pks supplied and p is the price of 12-pks in dollars. 5. What is the equilibrium price? What is the equilibrium quantity? - Correct Answer Solution 4: (3,10) (4,35) M= 35-10/4-3 = 25/1 =25 q=25p+b find B at (3,10) > 10=25(3)+b> 10=75+b > B=-65 ; q=25p-65 Solution 5: Supply demand: -20p+100=25p-65 +20p+65 +20p+65 165= 45p ; p=165/45= 3.66... Equilibrium price is $3.67 q=-20p+100> q=-20(11/3)+100=26.6 Equilibrium quantity is 26.6= 27 X hours slept: 4 5 6 7 8 9 10 Y Score: 82 63 6. Use the best fit line to predict the score on a est for a student who slept 3 hours= - Correct Answer Solution 6: L1 - L2 4 58 5 65 6 73 7 83 8 85 9 82 10 63 y=2...(x+58.892857)= (365.429) Important to place in calculator setting., to place function so value can be looked up in table.