Applications, 12th edition By S. A. Hummelbrunner
,Contemporary Business Mathematics, 12e (Hummelbrunner)
Chapter 1 Review of Arithmetic
1) Simplify: (28 - 4)/3
Answer: (28 - 4)/3 = 24/3 = 8
Diff: 1 Type: SA Page Ref: 5-6
Topic: 1.1 Basics of Arithmetic
Objective: 1-1: Simplify arithmetic expressions using the basic order of operations.
2) Simplify: 8 + 6 ∗ 2
Answer: 8 + 12 = 20
Diff: 1 Type: SA Page Ref: 5-6
Topic: 1.1 Basics of Arithmetic
Objective: 1-1: Simplify arithmetic expressions using the basic order of operations.
3) Simplify: 5(4 + 3)
Answer: 5 ∗ 7 = 35
Diff: 1 Type: SA Page Ref: 5-6
Topic: 1.1 Basics of Arithmetic
Objective: 1-1: Simplify arithmetic expressions using the basic order of operations.
4) Simplify:
Answer: 5/20 = .25
Diff: 1 Type: SA Page Ref: 5-6
Topic: 1.1 Basics of Arithmetic
Objective: 1-1: Simplify arithmetic expressions using the basic order of operations.
5) Simplify:
Answer: 40/20 = 2
Diff: 1 Type: SA Page Ref: 5-6
Topic: 1.1 Basics of Arithmetic
Objective: 1-1: Simplify arithmetic expressions using the basic order of operations.
6) Simplify: 9(8 - 5) + 5(6 + 4)
Answer: 9 ∗ 3 + 5 ∗ 10 = 27 + 50 = 77
Diff: 1 Type: SA Page Ref: 5-6
Topic: 1.1 Basics of Arithmetic
Objective: 1-1: Simplify arithmetic expressions using the basic order of operations.
7) Evaluate:
Answer: 268/(4400 ∗ .4262295) = 268/1875.4098 = .1429021
Diff: 2 Type: SA Page Ref: 5-6
Topic: 1.1 Basics of Arithmetic
Objective: 1-1: Simplify arithmetic expressions using the basic order of operations.
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,8) Evaluate and round to 3 decimal places: 125(6 + 0.35 ∗ 142/678)
Answer: 125 ∗ (6 + 0.35 ∗ 0.2094395) = 125 ∗ (6 + 0.0733038) = 125 ∗ (6.0733038) = 759.163
Diff: 2 Type: SA Page Ref: 5-6
Topic: 1.1 Basics of Arithmetic
Objective: 1-1: Simplify arithmetic expressions using the basic order of operations.
9) Evaluate: 400(1 + .10 ∗ 100/365)
Answer: 400 ∗ (1 + .10 ∗ .2739726) = 400 ∗ (1 + .02739726) = 400 ∗ (1.02739726) = 410.959
Diff: 2 Type: SA Page Ref: 5-6
Topic: 1.1 Basics of Arithmetic
Objective: 1-1: Simplify arithmetic expressions using the basic order of operations.
10) Evaluate and round to one decimal place: 9210(5 - 1.38 ∗ 169/420)
Answer: 9210 ∗ (5 - 1.38 ∗ 0.40238095) = 9210 ∗ (5 - 0.5552857) = 9210(4.444714) = 40,935.8
Diff: 2 Type: SA Page Ref: 5-6
Topic: 1.1 Basics of Arithmetic
Objective: 1-1: Simplify arithmetic expressions using the basic order of operations.
11) Evaluate:
Answer: 2424/(1 + .2 ∗ .4547945) = 2424/(1 + .0909589) = 2424/1.0909589 = 2221.899
Diff: 2 Type: SA Page Ref: 6-11
Topic: 1.2 Fractions
Objective: 1-2: Determine equivalent fractions, and convert fractions to decimals, decimals to percents, and vice
versa.
12) Evaluate and round to three decimal places:
Answer: 3140/(2 + 0.35 * 0.2123288) = 3140/(2 + 0.0743151) = 2910/2.074315068 = 1513.753
Diff: 2 Type: SA Page Ref: 7-13
Topic: 1.2 Fractions
Objective: 1-2: Determine equivalent fractions, and convert fractions to decimals, decimals to percents, and vice
versa.
13) Evaluate:
Answer: 5000/(1 + .1 ∗ .5) = 5000/(1 + 0.05 ) = 5000/1.05 = 4761.90
Diff: 2 Type: SA Page Ref: 6-11
Topic: 1.2 Fractions
Objective: 1-2: Determine equivalent fractions, and convert fractions to decimals, decimals to percents, and vice
versa.
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, 14) Spade Realty sold lots for $23 240 per hectare. What is the total sales value if the lot sizes, in hectares,
were 2 , 3 , 4 ?
Answer: 23240 ∗ ( +3 +4 )
= 23240 ∗ (2 10/20 + 3 5/20 + 4 4/20)
= 23240 ∗ (9 19/20) = 23240 ∗ 9.95
= $231238
Diff: 2 Type: SA Page Ref: 6-11
Topic: 1.2 Fractions
Objective: 1-2: Determine equivalent fractions, and convert fractions to decimals, decimals to percents, and vice
versa.
15) Three mechanics worked 15 , 14 , 18 hours respectively. What was the total cost of labour if the
mechanics were paid $14.75 per hour?
Answer: Total Hours
= 15 + 14 + 18
= 15.5 + 14.75 + 18.125
= 48.375
Total cost of labor = 48.375 ∗ 14.75 = $713.53
Diff: 2 Type: SA Page Ref: 6-11
Topic: 1.2 Fractions
Objective: 1-2: Determine equivalent fractions, and convert fractions to decimals, decimals to percents, and vice
versa.
16) Ana, Aamir and Charlotte worked 11 , 14 , and 22 hours respectively. What was the total cost of
labour if they were paid $18.00 per hour?
Answer: Total Hours
= 11 + 14 + 22
= 11.75 + 14.65 + 22.80
= 49.20
Total cost of labor = 49.20 ∗ 18.00 = $885.60
Diff: 2 Type: SA Page Ref: 7-13
Topic: 1.2 Fractions
Objective: 1-2: Determine equivalent fractions, and convert fractions to decimals, decimals to percents, and vice
versa.
17) A retailer returned 300 defective items to the manufacturer and received a credit for the retail price of
$0.75 less a discount of 1/3 of the retail price. What was the amount of the credit received by the retailer?
Answer: Retail value = 300($0.75) = $225
Credit = (1-1/3 )∗ $225 = (2/3) ∗ $225 = $150
Diff: 2 Type: SA Page Ref: 16-21
Topic: 1.4 Applications - Averages
Objective: 1-3: Through problem solving, compute simple arithmetic and weighted averages.
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