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Exam (elaborations)

Solutions for Principles of Foundation Engineering, 10th Edition Das (All Chapters included)

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Complete Solutions Manual for Principles of Foundation Engineering, 10th Edition by Braja M. Das ; ISBN13: 9780357684658....(Full Chapters included Chapter 1 to 17)...****CH-1 SOLUTIONS NOT AVAILABLE****1. Introduction. 2. Geotechnical Properties of Soil. 3. Natural Soil Deposits and Subsoil Exploration. 4. Soil Improvement and Ground Modification. 5. Shallow Foundations: Ultimate Bearing Capacity. 6. Ultimate Bearing Capacity of Shallow Foundations: Special Cases. 7. Vertical Stress Increase in Soil. 8. Settlement of Shallow Foundations. 9. Mat Foundations. 10. Uplift Capacity of Shallow Foundations and Helical Anchors. 11. Pile Foundations. 12. Drilled Shaft Foundations. 13. Foundations on Difficult Soil. 14. Lateral Earth Pressure. 15. Retaining Walls. 16. Sheet-Pile Walls. 17. Braced Cuts.

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Uploaded on
May 29, 2024
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2023/2024
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AN INSTRUCTOR’S SOLUTIONS MANUAL TO ACCOMPANY

PRINCIPLES OF FOUNDATION
ENGINEERING, TENTH EDITION
BRAJA M. DAS




Principles of
FOUNDATION NGINEERING
Principles of




FOUNDATION
ENGINEERING
Tenth Edition




Tenth
Edition



Braja M. Das

, INSTRUCTOR'S SOLUTIONS MANUAL
TO ACCOMPANY



Principles of Foundation
Engineering
Tenth Edition


BRAJA M. DAS
Dean Emeritus, California State University, Sacramento,
California, USA

, Contents

Chapter 2 ............................................................................................................................ 1

Chapter 3 .......................................................................................................................... 11

Chapter 4 .......................................................................................................................... 19

Chapter 5 .......................................................................................................................... 25

Chapter 6 .......................................................................................................................... 37

Chapter 7 .......................................................................................................................... 49

Chapter 8 .......................................................................................................................... 55

Chapter 9 .......................................................................................................................... 69

Chapter 10 ........................................................................................................................ 75

Chapter 11 ........................................................................................................................ 79

Chapter 12 ........................................................................................................................ 95

Chapter 13 ...................................................................................................................... 107

Chapter 14 ...................................................................................................................... 113

Chapter 15 ...................................................................................................................... 125

Chapter 16 ...................................................................................................................... 137

Chapter 17 ...................................................................................................................... 151

, Chapter 2


(87.5)(9.81)
2.1 d.    17.17 kN /m 3
(1000)(0.05)

 17.17
c.     14.93 kN /m 3
1 w 1  0.15

Gs w
a. Eq. (2.12):  d 
1 e

(2.68)(9.81)
14.93  ; e = 0.76
1 e

e 0.76
b. Eq. (2.6): n    0.43
1  e 1  0.76

e. From Eq. (2.14):

Vw wGs  (0.15)(2.68) 
S    100  53%
Vv e  0.76

2.2 a. From Eqs. (2.11) and (2.12), it can be seen that

 20.1
d    16.48 kN/m3
1 w 1  0.22

Gs w Gs (9.81)
b.  d  16.48 kN/m3  
1 e 1 e

Eq. (2.15): e  wGs  (0.22)(Gs ) . So

9.81Gs
16.48  ; Gs  2.67
1  0.22Gs




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