MATH 110 Module 4 Exam.| PORTGE LEARNING

MATH 110 Module 4 Exam.| PORTGE LEARNING Module 4 Exam Exam Page 1 A factory has eight safety systems. During an emergency, the probability of any one of the safety systems failing is .08. What is the probability that six or more safety systems will fail during an emergency? f(x) = ( (n!) / (x!(n-x)!) ) x ( (p^x) x ((1-p)^n-x)) ) n = 8 x = 6, 7, 8 (number of failures) p = 0.08 6 failures: n = 8 x = 6 p = 0.8 n-x = 8-6 = 2 ( (8!) / (6!(2)!) ) x ( (0.08^6) x ((1-0.08)^2)) ) = 6.2 x 10^-6 7 failures: n = 8 x = 7 p = 0.8 n-x = 8-7 = 1 ( (8!) / (7!(1)!) ) x ( (0.08^7) x ((1-0.08)^1)) ) = 1.54 x 10^-7 8 failures: n = 8 x = 8 p = 0.8 n-x = 8-8 = 0 ( (8!) / (8!(0)!) ) x ( (0.08^8) x ((1-0.08)^0)) ) = 1.68 x 10^-9 f(6) = 6.21 x 10^-6