Momentum marking Scheme

- Mark Scheme /


Question Answer Marks AO Element Notes Guidance

1(a) PE lost = KE gained in any form 3
(1)
2
v = 2gh OR
0.16 × 10 × 115 = 0.5 × 0.16 ×
2
v (1)
(speed =) 48 m / s (1)

1(b) momentum = mv (1) 2
(momentum=) 7.7 kg m / s OR
7.7 N s (1)

2(a) (a =) (v – u) ÷ t OR 2
(62 – 6.0) ÷ 35 OR
56 ÷ 35 (1)
2
1.6 m / s (1)

2(b) (F =) ma OR 2
Δ p ÷ Δ t OR
5
2.5 × 10 × 1.6 OR
5
(62 × 2.5 × 10 – 6.0 × 2.5 ×
5
10 ) ÷ 35 (1)
5
4.0 × 10 N (1)

2(c) (p =) mv OR 2
5
2.5 × 10 × 6.0 (1)
6
1.5 × 10 kg m / s (1)

, - Mark Scheme /


Question Answer Marks AO Element Notes Guidance

3(a) (impulse =) change of 3
momentum (1)
(impulse =) 71(10 – 4) (1)
(impulse =) 430 N s (1)

3(b) (impulse =) force × time 1

3(c) (average F =) impulse / time (= 2
.2) (1)
(average F =) 360 N (1)

4 EITHER 4
(change in momentum) = mv
OR (change in momentum) =
6
1.2 × 10 × 0.04 (1)
4
(=) 4.8 × 10 (kg m/s) (1)
change in momentum = Ft in
any form (1)
4
(force = 4.8 × .3 =)
5
1.6 × 10 N (1)
OR
a = (v-u)/t = 0.04/0.3 (1)
2
= 0.13 (m/s ) (1)
F = ma (1)
6
(force = 1.2 × 10 × 0.13 =)
5
1.6 × 10 N (1)