0.59 m. The loop is hinged along the y - axis, and its plane makes an angle of theta = 36 degree
with the x-axis. A uniform magnetic field of 0.28 T is directed along the x - axis and the current
in the loop is 9.2 A in the direction shown. What is the magnitude of the torque exerted on the
loop? Answer in units of N m
Solution
torque = number of turns * current * area * B field * cos@ =
= 338 * 9.2 * 0.63 * 0.59 * 0.28 * cos36 =
= 261.8 N-m