Exam (elaborations)
Churchill Paper 1C Marking Guide – AQA Higher Tier
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3 Gradient of L = 2 − 0 (−3) − 0 = – 2 Gradient of options is m in y = mx + c Gradients = – 2 2 3 3 3 2 2 Parallel so same gradient, hence y = 4 – 2 x y = 2 x – 1 y = 2 – 3 x y = 3 x + 1 B1 Total 1 3 3 2 2 Let no. of LH people = x At first, no. of RH people = 15 x 12 RH join so new no. of RH people = 15 x + 12 M1 Ratio is now 9 : 1 so 15 x + 12 = 9x M1 12 = 3 x x = 8 There are 8 left-handed people A1 Total 3
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AQA Mathematics
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AQA mathematics
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- AQA mathematics
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- AQA mathematics
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- June 12, 2023
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mathematics paper 1 higher tier
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churchill paper 1c marking guide – aqa higher tier
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