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AAMC FL 5 Questions and Answers 2023

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AAMC FL 5 Questions and Answers 2023 Question 6 Thought process: - Didn't know the structure of flavin, therefore needed to narrow down answer from answer choices: - Knew A was a pyrimidine, cross that out - Had not seen structure of B before - Knew C was ubiquinone (still chose just because ubiquinone was mentioned in the passage (stupid)) - Didn't try and analyze structure of D at the time Correct thought process: - Cross out A bc pyrimidine - Never seen B before (come back to later) - Cross out C because ubiquinone - Cross out D because histidine - Therefore, left with correct answer B Two open flasks I and II contain different volumes of the same liquid. Suppose that the pressure is measured at a point 10 cm below the surface of the liquid in each container. How will the pressures compare? A. The pressures will be equal. B. Pressure in flask I will be less. C. Pressure in flask II will be less. D. The pressures cannot be compared from the information given. Not sure how I missed this one, even wrote out the equation during the exam. Need to pay more attention to what I'm doing when answering If all else is held constant, which of the following changes would NOT double the volume of a gas? A. Doubling the pressure B. Doubling the absolute temperature C. Halving the pressure D. Doubling the number of gas molecules Got lazy and didn't work out all answer choices What is the number of neutrons in the nucleus of the atom used to produce laser radiations? A. 48 B. 49 C. 50 D. 51 Concept: - Ions do not lost protons - Ions only lose ELECTRONS Approximately how many moles of Kr+ are contained in the laser tube at 0°C and 1 atm? A. 3 x 10-7 B. 2 x 10-6 C. 4 x 10-5 D. 5 x 10-4 Define STP Conditions: 1 atm, 0C - If constants aren't given you don't need to solve problem, but can help to know - I missed this problem because I didn't read the passage close enough at first, which gave me the volume I needed to solve the problem The radiation of wavelength 605 nm CANNOT be used to produce the fluorescence radiations depicted in Figure 3 because: A. the energy of the absorbed radiation must be larger than the energy of the fluorescence radiation. B. the energy of the absorbed radiation must be smaller than the energy of the fluorescence radiation. C. the 605-nm radiation has more energy than the 407-nm radiation. D. the 605-nm radiation is not visible. HAVE TO READ THE PASSAGE CLOSELY - sometimes I get caught up in thinking I can rationalize an answer choice from outside conceptual knowledge when it's impossible - it literally states almost word for word in the passage the answer Samples from various time points of the proteolysis of TPMTwt were subjected to SDS-PAGE under reducing conditions. Which figure best depicts the expected appearance of the gel? Didn't pay attention to question hard enough - really need to focus on what the question is asking The second purification step is which type of chromatographic separation? A. Affinity B. Size exclusion C. Cation exchange D. Anion exchange Wasn't even paying attention to the correct part of the passage - Neglected to answer based on where the info was in the passage, because I got stuck on prior information Which classification of amino acids applies to the Trp residues after photochemical modification by CCl3CO2H? A. Acidic B. Basic C. Hydrophobic D. Polar neutral - realized that a COOH group was added - I was trying to think too broadly rather than following AAMC logic about what that specific addition did to the molecule Which type of heterocycle is found on two amino acid residues blocking access to W15? A. Imidazole B. Indole C. Pyrimidine D. Pyrrole - How to logically think through this problem without knowing what the structure of an imidazole is: - Mentions in the passage that trp has is blocked by a HIS residue - Cross out B bc in the passage it mentions trp has an indole group - Cross out C because DNA - Cross out D because pyrrole does not have 2 N-H's and is found in heme - Overall, need to rely on passage information more than just thinking I should know things In which phase(s) will the MCS precursor be predominantly found after the extraction step? The MCS precursor will: A. be found in the aqueous layer. B. be found in the tert-butyl methyl ether layer. C. be distributed equally between the aqueous layer and the tert-butyl methyl ether layer. D. form a precipitate between the aqueous and tert-butyl methyl ether layers. - Got too ahead of myself with the extraction steps/didn't fully understand the concept: - Essentially if trying to separate compounds with highly dissimilar solubilities, then don't need to do acid/base extraction. Extraction will simply be using a polar/non-polar solvent to separate the mixture - In acid base (got confused because next sentence mentions NAOH digestion), all are in organic phase, but then add acid/base to organic phase and it will ionize/move compound to more dense aqueous phase An ice cube at 0°C and 1 atm is heated to form steam at 100°C and 1 atm. Ignoring heat loss to the surroundings, what part of the process uses the most heat? (Note: Specific heat of water = 1 cal/g°C. Heat of fusion = 80 cal/g. Heat of vaporization = 540 cal/g.) A. Melting the ice cube B. Heating all the water from 0°C to 50°C C. Heating all the water from 50°C to 100°C D. Vaporizing all the water Such a stupid miss - logically in my head I went with B even though I looked at the heat capacity calculation and knew it was D - Be more confident in answer choice If the red line in the Balmer series has a wavelength of 656 nm, which of the following is closest to its frequency? A. 4.6 × 1014 Hz B. 4.6 × 10−​14 Hz C. 2.1 × 1015 Hz D. 2.1 × 10−​15 Hz Calculation miss, wasn't paying attention to what question wanted

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AAMC FL 5 Questions and Answers 2023
Question 6 - answer Thought process:
- Didn't know the structure of flavin, therefore needed to narrow down answer from
answer choices:
- Knew A was a pyrimidine, cross that out
- Had not seen structure of B before
- Knew C was ubiquinone (still chose just because ubiquinone was mentioned in the
passage (stupid))
- Didn't try and analyze structure of D at the time

Correct thought process:
- Cross out A bc pyrimidine
- Never seen B before (come back to later)
- Cross out C because ubiquinone
- Cross out D because histidine
- Therefore, left with correct answer B

Two open flasks I and II contain different volumes of the same liquid. Suppose that the
pressure is measured at a point 10 cm below the surface of the liquid in each container.
How will the pressures compare?
A.
The pressures will be equal.
B.
Pressure in flask I will be less.
C.
Pressure in flask II will be less.
D.
The pressures cannot be compared from the information given. - answer Not sure
how I missed this one, even wrote out the equation during the exam. Need to pay more
attention to what I'm doing when answering

If all else is held constant, which of the following changes would NOT double the
volume of a gas?
A.
Doubling the pressure
B.
Doubling the absolute temperature
C.
Halving the pressure
D.
Doubling the number of gas molecules - answer Got lazy and didn't work out all
answer choices

, What is the number of neutrons in the nucleus of the atom used to produce laser
radiations?
A.
48
B.
49
C.
50
D.
51 - answer Concept:
- Ions do not lost protons
- Ions only lose ELECTRONS

Approximately how many moles of Kr+ are contained in the laser tube at 0°C and 1
atm?
A.
3 x 10-7
B.
2 x 10-6
C.
4 x 10-5
D.
5 x 10-4 - answer Define STP Conditions: 1 atm, 0C
- If constants aren't given you don't need to solve problem, but can help to know
- I missed this problem because I didn't read the passage close enough at first, which
gave me the volume I needed to solve the problem

The radiation of wavelength 605 nm CANNOT be used to produce the fluorescence
radiations depicted in Figure 3 because:
A.
the energy of the absorbed radiation must be larger than the energy of the fluorescence
radiation.
B.
the energy of the absorbed radiation must be smaller than the energy of the
fluorescence radiation.
C.
the 605-nm radiation has more energy than the 407-nm radiation.
D.
the 605-nm radiation is not visible. - answer HAVE TO READ THE PASSAGE
CLOSELY
- sometimes I get caught up in thinking I can rationalize an answer choice from outside
conceptual knowledge when it's impossible
- it literally states almost word for word in the passage the answer

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