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DSC_1520 Assignment (2022)

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DSC_1520 Assignment (2022) The equation of the straight line is given by y = mx + c Use the point (3;1) to find c the y-intercept OPTION 1 S(t) = 1800 + 1500e− 0,3t+1,5 2000 = 1800 + 1500e− 0,3t+1,5 = 1500e− 0,3t+1,5 200 = 1500e−0,3t+1,5 Page 2 of 11 t = 12 days OPTION 4 a = 80 ; b = 0.5 OPTION 2 = = = = 1.5 - = 0.3t Page 3 of 11 Pd = Ps 50 – 0.6Q = 20 + 0.4Q 50-20 = 0.4Q + 0.6Q 30 = Q (horizontal co-ordinate) From Pd = 50 – 0.6Q P = 50 – 0.6(30) P = 32 (vertical co-ordinate) Intercept (30;32) Page 4 of 11 OPTION 2 At the intercept equilibrium is reached when 30 units are produced at R32/unit OPTION 2 At equilibrium Pd = Ps 50 – 3Q = 14 + 1.5Q 50-14 = 1.5Q + 3Q 36 = 4.5Q Q = 8 P = 50-3(8) = 26 P = 26 Use the supply function for Producer surplus Ps = 14 + 1.5Q a=14; P=26; Q=8 X Q x (P-a) X 8 x (26-14) = 48 Use the demand function for consumer surplus Pd = 50 -3Q a=50; P=26; Q=8 Page 5 of 11 X Q x (a-P) X Q x (50-26) = 96 OPTION 2 = 8.773 ≈8.77 OPTION 2 P Page 6 of 11 When P = 10 then OPTION 4 TR = P x Q = P(6000 – 30P) = 6 000P – 30P2 TC = 5 000 + 2Q) = 5 000 + 2(6000 – 30P) = 17 000 – 60P PROFIT = TR – TC = 6 000P – 30P2 – (17 000 – 60P) = 6 000P – 30P2 – 17 000 + 60P = -30P2 + 6 060P – 17 000

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QUANTITATIVE MODELLING


DSC_1520 ASSIGNMENT
(2022)

, DSC_1520 ASSIGNMENT (2022)




The equation of the straight line is given by y = mx + c




Use the point (3;1) to find c the y-intercept




OPTION 1




S(t) = 1800 + 1500e−0,3t+1,5

2000 = 1800 + 1500e−0,3t+1,5

2000 - 1800 = 1500e−0,3t+1,5

200 = 1500e−0,3t+1,5

Page 1 of 11

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