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MAT1511 Assignment 2 (Answers) Semester 1 - 2023

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MAT1511 Assignment 2 (Answers) Semester 1 - 2023 Questions asked: 1. Write (2+3i) (4−3i) (3+2i) 2 (4) in the form a+bi, where a,b ∈ R. 2. Given z1 = 2∠180o , ; z2 = 3∠270o and z3 = 1∠180o . Determine the following and leave your answers in rectangular form: (i) (z1) 2 +z2 z2 +z3 (5) (ii) z1 z2z3 (5) 3. Let Z = −1− √ 3i (i) Write Z in a polar form (2) (ii) Use De Moivre’s Theorem to determine Z 4 . (3) Z and leave your answer in polar form with the angle in radians (a) Z = 1−i √ 3 2 (5)  2, 5π 4  ,  2,− 5π 4  ,  −2,− π 4  . (3) (b) Convert into rectangular coordinates:  −4,− 13π 6  . (3) 4 4. Use De Moivre’s Theorem to determine the cube root of 5. (a) Plot the following points in the same polar coordinates system MAT1511/101/0/2023 (c) Convert the following rectangular coordinates into polar coordinates (r,θ) so that r ≥ 0 and −2π ≤ θ ≤ 2π : √ 3,−1  . (3) 35.0m/s through a pipe that is at an angle of 75o with the horizontal. What are the components of its velocity? (3) F1 = −2i +2j, F2 = i −6j, F3 = 3i −5j. Determine F4 and its magnitude. (4) 15 km/h crosswind flowing in the direction S30oW. (a) Find the speed the aeroplane. (7) (b) Determine the directionof the aeroplane. (Leave your answer in terms of square root)(3) [TOTAL: 50]

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, 1. Write (2+3i) (4−3i) (3+2i) 2 (4) in the form a+bi, where a,b ∈ R.
To simplify the expression, let's perform the calculations step by step:

1. (2 + 3i) * (4 - 3i):

Using the FOIL method (First, Outer, Inner, Last), we can expand the expression as follows:

= 2 * 4 + 2 * (-3i) + 3i * 4 + 3i * (-3i)
= 8 - 6i + 12i - 9i^2

Remember that i^2 is equal to -1. Substituting it into the equation:

= 8 - 6i + 12i - 9(-1)
= 8 - 6i + 12i + 9
= 17 + 6i

2. (3 + 2i) / (4):

Dividing the complex number by a real number is straightforward. We simply divide each term by 4:

= (3/4) + (2i/4)
= 3/4 + i/2

Now, let's proceed to the next step:

3. (17 + 6i) * (3/4 + i/2):

Again, using the FOIL method, we can expand the expression:

= (17 * 3/4) + (17 * i/2) + (6i * 3/4) + (6i * i/2)
= 51/4 + 17i/2 + 18i/4 - 6
= 51/4 + 17i/2 + 9i/2 - 6
= (51 + 17i + 9i - 24) / 4
= (27 + 26i) / 4

Finally, we divide each term by 4:

= 27/4 + 26i/4
= 27/4 + 13/2i

Therefore, the expression (2+3i)(4-3i) / (3+2i)(4) can be simplified to 27/4 + 13/2i.

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