Genetics Exam 1 Module 2 Exam(A+ graded 100% verified latest update)

Genetics Exam 1 Module 2 Exam(A+ graded 100% verified latest update)QUESTION 1 1. I confirm that I am completing this exam on my own, without consulting outside sources. I also confirm that I am completing the exam completely independently, on my own. I have not discussed the exam or its content with others, and I will not discuss the exam or its content with others until after the exam deadline. Yes, I confirm. No, I do not. QUESTION 2 1. In pea plants, round seeds (R) are dominant over wrinkled seeds (r). You find a pea plant with round seeds and want to test if it is homozygous or heterozygous for round seeds. What would be the BEST way to find out? Sequence its whole genome Cross it with another plant that has round seeds and see what kinds of offspring you get Try to identify its parents and see whether they had round or wrinkled seeds Cross it with a plant that has wrinkled seeds and see what kinds of offspring you get QUESTION 3 1. In pea plants, purple flowers (P) are dominant over white flowers (p). You cross two plants that have purple flowers, and you get 100 offspring. 77 of the offspring have purple flowers and 23 of the offspring have white flowers. Which of the following are the MOST likely genotypes of the parents? Pp and pp PP and PP Pp and PP Pp and Pp QUESTION 4 1. You identify a strain of mice that do not develop tails. You hypothesize that taillessness (loss of tails) is caused by a Mendelian, recessive, X-linked mutation. Which would be the BEST way to test this hypothesis? Cross a tailless female mouse with a normal (tailed) male mouse Cross a tailless male mouse with a normal (tailed) female mouse Cross a tailless male mouse with a tailless female mouse All of these are equally viable options QUESTION 5 1. In fruit flies, mutations in the autosomal gene vestigial (vg) cause the wings to be tiny and underdeveloped; the two alleles are designated as vg+ (wild-type, normal allele) and vg- (mutant allele). You perform a cross between a fly with vestigial wings and a fly with normal wings from a true-breeding strain, to obtain F1 flies. What are the genotypes of the gametes that can be produced by the F1 flies? vg+/vg- and vg-/vg- vg+/vg+ only vg+/vg+, vg+/vg-, and vg-/vg- vg+ and vg- QUESTION 6 1. In pea plants, inflated pods (C) are dominant over constricted pods (c). You have a true-breeding strain of peas with inflated pods, and a true-breeding strain with constricted pods. You cross a pea plant from the true-breeding inflated strain, with a plant from the true-breeding constricted strain to get an F1 generation. You then cross the F1 plants back to a true-breeding constricted plant. You obtain 100 F2 offspring total. How many offspring with each phenotype do you expect to get? 75 inflated, 25 constricted 25 inflated, 75 constricted 50 inflated, 50 constricted 67 inflated, 33 constricted QUESTION 7 1. In fruit flies, yellow eyes are caused by a recessive, X-linked mutation (ye-; the wild- type allele is ye+). You cross a male with yellow eyes to a female fly with normal red eyes from a true-breeding strain. Which of the following is the BEST prediction for what types of offspring you will see in the F1 generation? The males will all have red eyes, and the females will all have red eyes The males will all have yellow eyes, and the females will all have yellow eyes The males will all have red eyes, and the females will all have yellow eyes The males will all have yellow eyes, and the females will all have red eyes QUESTION 8 1. In fruit flies, yellow eyes are caused by a recessive, X-linked mutation (ye-; the wild- type allele is ye+). You cross a female with yellow eyes to a male fly with normal red eyes from a true-breeding strain. Which of the following is the BEST prediction for what types of offspring you will see in the F1 generation? The males will all have yellow eyes, and the females will all have red eyes The males will all have red eyes, and the females will all have yellow eyes The males will all have red eyes, and the females will all have red eyes The males will all have yellow eyes, and the females will all have yellow eyes QUESTION 9 1. The genes Q and R are unlinked, and each have two alleles (Q and q for the first gene, R and r for the second gene). You cross a QQrr fly with an qqRR fly to obtain an F1 fly. The gamete genotypes that gan be produced by the F1 fly are... QQ and RR Qq and Rr QR, Qr, qR and qr QR and rr QUESTION 10 1. You cross two tomato plants that both have the genotype Aa Bb Cc Dd Ee. What is the probability of getting one offspring with the genotype AA BB Cc Dd EE? (Make sure to submit your answer as a decimal, NOT a fraction or percentage) QUESTION 11 1. You cross a PP QQ plant with a pp qq plant. You then cross the F1 plant to a Pp qq plant. Fill in the numbers below to indicate the genotypic ratios you expect to get in the F2 generation: (a few of them have already been filled in for you) PP QQ Pp QQ pp QQ 1 PP Qq 2 Pp Qq pp Qq PP qq Pp qq pp qq QUESTION 12 1. You have two mutant strains of fruit flies. The first has forked bristles (the dominant allele F leads to wild-type bristles, and the recessive f allele leads to forked bristles); the second is wingless (the dominant allele W leads to flies with wings; the recessive w allele leads to wingless flies). Both genes are autosomal. You cross a true-breeding fly with forked bristles and normal wings, to a true-breeding fly with wild-type bristles and no wings (wingless), to obtain F1 flies. You then cross the F1 flies to each other to obtain 160 F2 flies. If the genes are unlinked, in the F2 generation you expect to get about: 40 flies with wild-type wings and wild-type bristles; 40 flies with forked bristles and wild-type wings; 40 flies with wild-type bristles and no wings [wingless]; 40 flies with forked bristles and no wings [wingless] 90 flies with wild-type wings and wild-type bristles; 30 flies with forked bristles and wild-type wings; 30 flies with wild-type bristles and no wings [wingless]; 10 flies with forked bristles and no wings [wingless] 80 flies with wild-type wings and wild-type bristles; 80 flies with forked bristles and no wings [wingless] 120 flies with wild-type wings and wild-type bristles; 40 flies with forked bristles and no wings [wingless] QUESTION 13 1. You isolate two mutations in zebrafish. The first mutation causes an albino phenotype (A = dominant, striped pigmentation; a = recessive, albino); the second mutation causes an eyeless phenotype (E = normal eyes; e = eyeless). You cross an albino eyeless fish, with a true-breeding wild-type fish (i.e., normal striped pigmentation and normal eyes). You then backcross one of the F1 fish to a mutant eyeless, albino fish. In the F2 generation, you obtain 300 eyeless, albino fish; 25 eyeless fish with normal striped pigmentation; 25 fish albino fish with normal eyes; and 300 fish with normal eyes and normal striped pigmentation. The most likely reason that these numbers differ from the typical Mendelian ratios is... epistasis the two genes are linked variable expressivity the eyeless gene is sex- linked QUESTION 14 1. In flour beetles, the gene A controls antenna length (A = long [dominant], a = short [recessive]), and the gene B controls claw phenotype (B = broad [dominant], b = narrow [recessive]). You cross a true-breeding beetle with short antennae and broad claws, to a true-breeding beetle with long antennae and narrow claws. You then cross the F1 beetle to a true-breeding beetle with short antennae and narrow claws. If the two genes are closely linked, in the F2 generation you expect that: most offspring will have short antennae and narrow claws, or long antennae and broad claws you will get equal numbers of offspring with the four different possible combinations of phenotypes (long antennae + broad claws; long antennae + narrow claws; short antennae + broad claws; short antennae + narrow claws; in a 1:1:1:1 ratio) most offspring will have long