Gaganpreet Cheema
3611260
Assignment 2b
Problem 7 a
Die 1 Die 2 Die 1 + Die 2
2 3 5
3 4 7
4 4 8
1 3 4
5 4 9
Problem 7b
Die 1 Die Die 1 + Die 2 Recode (Die 1 + Die 2)
2 3 5 Less than 8
3 4 7 Less than 8
4 4 8 At least 8
1 3 4 Less than 8
5 4 9 At least 8
Problem 7c
Frequency table results for Recode (Die 1 + Die 2):
Count = 1000
Recode (Die 1 + Die 2) Frequency Relative Frequency
At least 8 466 0.466
Less than 8 534 0.534
Problem 7d
Theoretically (based on the classical view of probability), you should expect to see the relative
frequency of the “at least 8” category to be close to 15/36 = 0.4167 This is based on the
observation that there are 15 (out of 36) different possible outcomes that can occur for the event
“at least 8” to occur: ((4,4), (6,2), (2,6), (5,3), (3,5), (5,4), (4,5), (6,3), (3,6), (5,5), (6,4), (4,6),
3611260
Assignment 2b
Problem 7 a
Die 1 Die 2 Die 1 + Die 2
2 3 5
3 4 7
4 4 8
1 3 4
5 4 9
Problem 7b
Die 1 Die Die 1 + Die 2 Recode (Die 1 + Die 2)
2 3 5 Less than 8
3 4 7 Less than 8
4 4 8 At least 8
1 3 4 Less than 8
5 4 9 At least 8
Problem 7c
Frequency table results for Recode (Die 1 + Die 2):
Count = 1000
Recode (Die 1 + Die 2) Frequency Relative Frequency
At least 8 466 0.466
Less than 8 534 0.534
Problem 7d
Theoretically (based on the classical view of probability), you should expect to see the relative
frequency of the “at least 8” category to be close to 15/36 = 0.4167 This is based on the
observation that there are 15 (out of 36) different possible outcomes that can occur for the event
“at least 8” to occur: ((4,4), (6,2), (2,6), (5,3), (3,5), (5,4), (4,5), (6,3), (3,6), (5,5), (6,4), (4,6),
