QMI1500 ASSIGNMENT 01 SEMESTER 01 - 2022

QMI1500 ASSIGNMENT
01 SEMESTER 01 - 2022

,1

, QUESTION 1

Solving

−7 − 3 × 2(−5) + 6 − 21 ÷ 3

gives

[1] 26.

[2] 99.

[3] 95.

[4] 22.

Simplifying the expression gives:

FOLLOW THE BEMDAS ORDER OF OPERATIONS

Brackets; Exponents; Multiplication & Division; Addition & Subtraction:

−7 − 3 × 2 (−5) + 6 − 21 ÷ 3
Multiply and divide (left to right): 3 × 2 ( −5) = -30
3 × 2 ( -5)
3×2=6
= 6( - 5)
= −7 – ( -30) + 6 – 21 ÷ 3
Apply rule: 𝑎 × (−𝑏) = −𝑎 × 𝑏
6( - 5) = -6 × 5
= -30

Multiply and divide (left to right): 21 ÷ 3 = 7
= −7 – ( -30) + 6 – 7 21 ÷ 3 = 7

Add and subtract (left to right): −7 – ( -30) + 6 – 7 = 22
= -7 + 30 + 6 -7 −7 – ( -30) + 6 – 7

Apply rule: − (− 𝑎) = + 𝑎
− ( −30) = +30

If more than one operation have the same priority, operate
from left to right. + and − have the same priority.
= 23 + 6 – 7 -7 + 30 = 23

= 29 - 7 23 + 6 = 29

= 22 29 – 7 = 22
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