HIGHSCHOOL Q&A ON ALGEBRAIC EXPRESSIONS
Teacher Joel Kubai
1. Five year ago, a mother’s age was four times that of her daughter. In four years to come,
she will be 2 ½ times the age of her daughter. Calculate the sum of their present ages
2. Mutua bought 160 trays of 8 eggs each at shs.150 per tray. On transportation 12 eggs
broke. He later discovered that 20 eggs were rotten. If he sold the rest at shs.180 per
tray, how much profit did he make?
3. Simplify;
(a) 6a – 2b + 7a – 4b + 2
(b) 2x – 2 3x + 2
-
2x 4x
4. Simplify 6x2y2 + 13xy-5
3x2y2 – 13xy + 4
5. Given that x + y = 8 and x2 + y2 = 24
Find;
(a) the value of x2 + 2xy + y2
(b) Find the value of ; 2xy
(c) x2 – 2xy + y2
(d) x – y
(e) Value of x and y
, 6. Simplify the expression. 6x2 + 35x - 6
2x2 – 72
7. Simplify the expression
2
/3 (3x -2) – ¾ (2x -2)
8. Simplify by factorizing completely:
4y2 – x2
2x2 – yx -6y2
9. Simplify as far as possible.
3 - 1
x–y x+y
10. By calculation, find the coordinates of the intersection of the graphs y = x2 + 2x -5
and y = 3x +1
11. Simplify:
(a) y2 + 2y =¼
y3 – y2 – 6y
(b) hence solve:- y2 + 2y = ¼
y3 – y2 – 6y
12. A rectangular field measures 63.9m by 104.6metres find the minimum number of poles to be
erected for fencing if they are to be at most 2.4meters apart.
Teacher Joel Kubai
1. Five year ago, a mother’s age was four times that of her daughter. In four years to come,
she will be 2 ½ times the age of her daughter. Calculate the sum of their present ages
2. Mutua bought 160 trays of 8 eggs each at shs.150 per tray. On transportation 12 eggs
broke. He later discovered that 20 eggs were rotten. If he sold the rest at shs.180 per
tray, how much profit did he make?
3. Simplify;
(a) 6a – 2b + 7a – 4b + 2
(b) 2x – 2 3x + 2
-
2x 4x
4. Simplify 6x2y2 + 13xy-5
3x2y2 – 13xy + 4
5. Given that x + y = 8 and x2 + y2 = 24
Find;
(a) the value of x2 + 2xy + y2
(b) Find the value of ; 2xy
(c) x2 – 2xy + y2
(d) x – y
(e) Value of x and y
, 6. Simplify the expression. 6x2 + 35x - 6
2x2 – 72
7. Simplify the expression
2
/3 (3x -2) – ¾ (2x -2)
8. Simplify by factorizing completely:
4y2 – x2
2x2 – yx -6y2
9. Simplify as far as possible.
3 - 1
x–y x+y
10. By calculation, find the coordinates of the intersection of the graphs y = x2 + 2x -5
and y = 3x +1
11. Simplify:
(a) y2 + 2y =¼
y3 – y2 – 6y
(b) hence solve:- y2 + 2y = ¼
y3 – y2 – 6y
12. A rectangular field measures 63.9m by 104.6metres find the minimum number of poles to be
erected for fencing if they are to be at most 2.4meters apart.
