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CHEM 121 Final Exam Questions and Answers- Portage Learning $18.98   Add to cart

Exam (elaborations)

CHEM 121 Final Exam Questions and Answers- Portage Learning

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CHEM 121 Final Exam Questions and Answers- Portage Learning/CHEM 121 Final Exam Questions and Answers- Portage Learning/CHEM 121 Final Exam Questions and Answers- Portage Learning

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  • September 1, 2021
  • 29
  • 2021/2022
  • Exam (elaborations)
  • Questions & answers
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Millenialnurse
Exam 1
Question 1
1.
Convert 1005.3 to exponential form and explain
your answer .
2.
Convert 4.87 x 10
-6
to ordinary form and explain
your answer .
1. Convert 1005.3 = larger than 1 = positive exponent,
move decimal 3 places
= 1.0053 x 10
3
2. Convert 4.87 x 10
-6
=negative exponent =smaller
than 1, move decimal 6
places = 0.00000487
Question 2
Using the following information, do the conversions
shown below , showing all work:
1 ft = 12 inches
1 pound = 16 oz
1 gallon = 4 quarts
1 mile = 5280 feet
1 ton = 2000 pounds
1 quart = 2 pints
kilo (= 1000)
milli (= 1/1000)
centi (= 1/100)
deci
(= 1/10)
1 / 3

1.
25.6 mg = ? grams
2.
1.5 gal = ? qts
1.
25.6 mg x 1 g / 1000 mg = 0.0256 grams
2.
1.5 gal x 4 qts / 1 gal = 6.0 qts
Question 3
Do the conversions shown below , showing all work:
1.
246
o
K = ?
o
C
2.
45
o
C = ?
o
F
3.
18
o
F = ?
o
K
1.
246
o
K - 273 = -27
o
C
o
K →
o
C
(make smaller) -273
2.
45
o
C x 1.8 + 32 = 1 13
o
F
o
C →
o
F
(make larger) x 1.8 + 32
3.
18
o
F - 32 ÷ 1.8 = -7.8 + 273 = 265.2
o
K
o
F →
o
C →
o
K
Question 4
1.
Show the calculation of the density of benzene
if 28.6 g occupies 32.7 ml.
2 / 3

2.
Show the calculation of the volume of 14.3 grams of acetone with density of
0.785 g/ml
1.
D = M / V = 28.6 / 32.7 = 0.875
2.
V = M / D = 14.3 / 0.785 = 18.2 ml
Question 5
1.
1.0780 contains ? significant figures.
2.
5.23 contains ? significant figures.
3.
5.23 x 1.0780 = ? (give answer to correct number
of significant figures)
1.
1.0780
contains
5
significant figures
2.
5.23
contains
3
significant figures
3.
5.23 x 1.0780 = 5.63794 = 5.64 (to 3 significant
figures for 5.23)
Question 6
Classify each of the following as an element, compound,
solution or heterogeneous
mixture and explain your answer .
1.
Honey - is not on periodic table (not element)
- no element names (not
compound) appears to be one substance = SolutionPowered by TCPDF (www.tcpdf.org)
3 / 3

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