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hello reader ! this is a question bank of question on projectile motion . hope you'll like it

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Galib Physics Classes, Beed
Time: 1 Hour 15 Mins DPP - Physics Marks: 200

Topic: Projectile Motion Batch: NEET / JEE

Syllabus: Projectile Motion (2D Motion, Height, Range, Time of Flight, Trajectory, Tower & Incline)


1. A body is projected with an initial velocity of 40 m/s 9. The maximum height attained by a projectile launched
at an angle of 30◦ with the horizontal. The horizon- from ground with speed 𝑢 = 40 m/s at 𝜃 = 30◦ (𝑔 =
tal and vertical components of its initial velocity are 10 m/s2 ) is:
respectively: (1) 10 m (2) 20 m (3) 30 m (4) 40 m
√ √
(1) 20 m/s, 20 3 m/s (2) 20 3 m/s, 20 m/s 10. The relationship between maximum height 𝐻 and total
(3) 40 m/s, 20 m/s (4) 20 m/s, 40 m/s time of flight 𝑇 for a projectile is:
2. A particle is projected with a speed of 50 m/s at an an- 𝑔𝑇 2 𝑔𝑇 2
gle of 53◦ above horizontal (cos 53◦ = 3/5, sin 53◦ = (1) 𝐻 = (2) 𝐻 =
2 4
4/5). Taking 𝑔 = 10 m/s2 , its velocity vector at 𝑔𝑇 2 𝑔𝑇 2
𝑡 = 2 s is: (3) 𝐻 = (4) 𝐻 =
8 16
(1) (30𝑖ˆ + 20 𝑗ˆ) m/s (2) (40𝑖ˆ + 20 𝑗ˆ) m/s 11. A projectile has a total time of flight 𝑇 = 6 s. Taking
(3) (30𝑖ˆ + 40 𝑗ˆ) m/s (4) (20𝑖ˆ + 30 𝑗ˆ) m/s 𝑔 = 10 m/s2 , the maximum height reached by the
projectile is:
3. A projectile is launched with speed 𝑢 at angle 𝜃 to the
horizontal. The speed of the projectile at its highest (1) 15 m (2) 30 m (3) 45 m (4) 90 m
point is: 12. Two projectiles are launched with the same speed 𝑢 at
(1) Zero (2) 𝑢 sin 𝜃 (3) 𝑢 cos 𝜃 (4) 𝑢 angles 30◦ and 60◦ with the horizontal. The ratio of
their times of flight 𝑇1 : 𝑇2 is:
4. A bullet is fired at an angle of 45◦ with the horizontal √ √
with initial kinetic energy 𝐸 . Its kinetic energy at the (1) 1 : 3 (2) 3 : 1 (3) 1 : 3 (4) 1 : 1
highest point of its trajectory is: 13. Two projectiles are launched with the same initial

(1) 𝐸 (2) 𝐸/2 (3) 𝐸/ 2 (4) Zero speed at angles 30◦ and 60◦ with the horizontal. The
√ ratio of their maximum heights 𝐻1 : 𝐻2 is:
5. A particle is projected with speed 𝑢 = 20 2 m/s at an √
angle of 45◦ with horizontal. Taking 𝑔 = 10 m/s2 , the (1) 1 : 3 (2) 1 : 3 (3) 3 : 1 (4) 1 : 9
angle that its velocity vector makes with horizontal at 14. A projectile is fired at an angle 𝜃 such that its hori-
𝑡 = 1 s is: zontal range 𝑅 is equal to 4 times its maximum height
(1) 60◦ (2) 30◦ 𝐻 . The angle of projection 𝜃 is:
(3) tan−1 (1/2) (4) 45◦ (1) 30◦ (2) 45◦ (3) 60◦ (4) 75◦

6. For a projectile launched from ground with speed 𝑢 15. If the horizontal range of a projectile is 𝑅 = 80 3 m
at angle 𝜃 , the magnitude of change in momentum and its maximum height is 𝐻 = 60 m, the angle of
between launch and landing is: projection is:
(1) Zero (2) 𝑚𝑢 sin 𝜃 (1) 30◦ (2) 45◦ (3) 60◦ (4) 75◦
(3) 2𝑚𝑢 sin 𝜃 (4) 2𝑚𝑢 cos 𝜃 16. A projectile has a maximum range of 100 m when
7. A particle is projected with a speed of 30 m/s at an launched on level ground (𝑔 = 10 m/s2 ). The maxi-
angle of 30◦ to the horizontal (𝑔 = 10 m/s2 ). The mum height reached during this maximum range flight
total time of flight is: is:
(1) 1.5 s (2) 3.0 s (3) 4.5 s (4) 6.0 s (1) 50 m (2) 25 m (3) 100 m (4) 12.5 m
8. A projectile takes 4 s to reach the highest point of its 17. Two objects are projected with the same initial speed
trajectory. The total time of flight of the projectile is: at complementary angles 𝜃 1 and 𝜃 2 (𝜃 1 + 𝜃 2 = 90◦ ).
The ratio of their horizontal ranges 𝑅1 : 𝑅2 is:
(1) 4 s (2) 6 s (3) 8 s (4) 12 s
(1) 1 : 2 (2) 2 : 1

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