1|Page
BIO 340 FINAL EXAM VERSION B NEWEST 2026/2027
COMPLETE 100 VERIFIED QUESTIONS AND ANSWERS
(VERIFIED ANSWERS) |ALREADY GRADED A+||QUICK PASS!!!
Which of the following is the correct order of events in mitosis?
- Sister chromatids line up at the metaphase plate. The
kinetochore becomes attached to the mitotic spindle. The
nucleus reforms and the cell divides. Cohesin proteins break
down and the sister chromatids separate.
- The kinetochore becomes attached to the mitotic spindle.
Cohesin proteins break down and the sister chromatids
separate. Sister chromatids line up at the metaphase plate. The
nucleus reforms and the cell divides.
- The kinetochore becomes attached to the cohesin proteins.
Sister chromatids line up at the metaphase plate. The
kinetochore breaks down and the sister chromatids separate.
The nucleus reforms and the cell divides.
- The kinetochore becomes attached to the mitotic spindle.
Sister chromatids line up at the metaphase plate. Cohesin
proteins break down and the sister chromatids separate. The
nucleus reforms and the cell divides. - ANSWER-The
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kinetochore becomes attached to the mitotic spindle. Sister
chromatids line up at the metaphase plate. Cohesin proteins
break down and the sister chromatids separate. The nucleus
reforms and the cell divides.
John has alkaptonuria; it "runs in the family". John and his
grandmother are both homozygous for alkaptonuria. John's
grandmother has two brothers and a sister. One of the brothers
had alkaptonuria and his daughter is John's mother. Based on
this information, John's parents are:
Not carrying the alkaptonuria gene.
Both heterozygous for the alkaptonuria gene.
Both homozygous for the alkaptonuria gene.
There isn't enough information. - ANSWER-Both heterozygous
for the alkaptonuria gene.
If John marries someone who is heterozygous for alkaptonuria,
then which of the following statements is true? Remember
alkaptonuria is a recessive disorder.
None of the children will have or be carriers of alkaptonuria.
All the children will have alkaptonuria.
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All of the children will inherit at least one copy of the
alkaptonuria gene.
All of the children are heterozygous for alkaptonuria. -
ANSWER-All of the children will inherit at least one copy of the
alkaptonuria gene.
You have flipped a standard quarter 10 times and had four head
and six tails come up. With that experience, what will be the
chances of you getting a heads on the next flip?
100%
60%
40%
50% - ANSWER-50%
If a student randomly guesses at five multiple-choice questions
during a BIO 340 exam, find the probability that the student
gets exactly three correct. Each question has five possible
choices.
0.1
0.05
1
10 - ANSWER-0.05
, 4|Page
What is the probability of having 4 girls in a row?
1 in 8
1 in 2
1 in 4
1 in 16 - ANSWER-1 in 16
In a cross between two heterozygous plants (Tt x Tt), what is
the probability of a plant being homozygous given that it is tall?
0.33
3
1
0.55 - ANSWER-0.33
What is the probability that the following pair of parents will
produce the indicated offspring? TTRrYy x TtRrYy -> TTrrYY
1/16
1/4
1/64
1/32 - ANSWER-1/32
BIO 340 FINAL EXAM VERSION B NEWEST 2026/2027
COMPLETE 100 VERIFIED QUESTIONS AND ANSWERS
(VERIFIED ANSWERS) |ALREADY GRADED A+||QUICK PASS!!!
Which of the following is the correct order of events in mitosis?
- Sister chromatids line up at the metaphase plate. The
kinetochore becomes attached to the mitotic spindle. The
nucleus reforms and the cell divides. Cohesin proteins break
down and the sister chromatids separate.
- The kinetochore becomes attached to the mitotic spindle.
Cohesin proteins break down and the sister chromatids
separate. Sister chromatids line up at the metaphase plate. The
nucleus reforms and the cell divides.
- The kinetochore becomes attached to the cohesin proteins.
Sister chromatids line up at the metaphase plate. The
kinetochore breaks down and the sister chromatids separate.
The nucleus reforms and the cell divides.
- The kinetochore becomes attached to the mitotic spindle.
Sister chromatids line up at the metaphase plate. Cohesin
proteins break down and the sister chromatids separate. The
nucleus reforms and the cell divides. - ANSWER-The
,2|Page
kinetochore becomes attached to the mitotic spindle. Sister
chromatids line up at the metaphase plate. Cohesin proteins
break down and the sister chromatids separate. The nucleus
reforms and the cell divides.
John has alkaptonuria; it "runs in the family". John and his
grandmother are both homozygous for alkaptonuria. John's
grandmother has two brothers and a sister. One of the brothers
had alkaptonuria and his daughter is John's mother. Based on
this information, John's parents are:
Not carrying the alkaptonuria gene.
Both heterozygous for the alkaptonuria gene.
Both homozygous for the alkaptonuria gene.
There isn't enough information. - ANSWER-Both heterozygous
for the alkaptonuria gene.
If John marries someone who is heterozygous for alkaptonuria,
then which of the following statements is true? Remember
alkaptonuria is a recessive disorder.
None of the children will have or be carriers of alkaptonuria.
All the children will have alkaptonuria.
,3|Page
All of the children will inherit at least one copy of the
alkaptonuria gene.
All of the children are heterozygous for alkaptonuria. -
ANSWER-All of the children will inherit at least one copy of the
alkaptonuria gene.
You have flipped a standard quarter 10 times and had four head
and six tails come up. With that experience, what will be the
chances of you getting a heads on the next flip?
100%
60%
40%
50% - ANSWER-50%
If a student randomly guesses at five multiple-choice questions
during a BIO 340 exam, find the probability that the student
gets exactly three correct. Each question has five possible
choices.
0.1
0.05
1
10 - ANSWER-0.05
, 4|Page
What is the probability of having 4 girls in a row?
1 in 8
1 in 2
1 in 4
1 in 16 - ANSWER-1 in 16
In a cross between two heterozygous plants (Tt x Tt), what is
the probability of a plant being homozygous given that it is tall?
0.33
3
1
0.55 - ANSWER-0.33
What is the probability that the following pair of parents will
produce the indicated offspring? TTRrYy x TtRrYy -> TTrrYY
1/16
1/4
1/64
1/32 - ANSWER-1/32
