, Student Solutions
Manual to
Accompany Atkins’
Physical Chemistry
ELEVENTH EDITION
Peter Bolgar
Haydn Lloyd
Aimee North
Vladimiras Oleinikovas
Stephanie Smith
and
James Keeler
Department of Chemistry
University of Cambridge
UK
Numerical solutions to the problems
compiled by Jack Entwistle
Selwyn College and the Department of Chemistry
University of Cambridge
,Preface
This document is a compilation of the numerical solutions to the (a) Exercises and the odd-
numbered Discussion questions and Problems from the th edition of Atkins’ Physical
Chemistry. Where a problem requests the derivation of a result or expression, and provided
that expression is not too complex, we have also included such results.
Errors and omissions
In such a complex undertaking some errors will no doubt have crept in, despite the authors’
best eorts. Readers who identify any errors or omissions are invited to pass them on to us by
email to .
Jack Entwistle
James Keeler
Cambridge, August
, 1
1 The properties of gases
1A The perfect gas
EA.(a) Torr . atm EA.(a) no . atm
EA.(a) . bar . atm EA.(a) 30 lb
in−2.
EA.(a) . bar 4.27 105 Pa
EA.(a) S8. ×
EA.(a) . kg
EA.(a) xO2 = 0.240 xN2 = 0.760 pO2 = 0.237 bar pN2 = 0.750 bar xN2 = 0.780
xO2 = 0.210 pN2 = 0.770 bar pO2 = 0.207 bar
EA.(a) . kg mol−1
EA.(a) θ = −273 ○C
EA.(a) xH2 = 2 3
xN2 = 31 pH2 = 2.0×105 Pa pN2 = 1.0×105 Pa ptot = 3.0×105 Pa
PA. 1.15 105×Pa . J K−1 mol−1 PA.
0.082062 atm dm3 mol−1 K−1 PA. p
= ρRT M . g mol−1 PA. 24.5
Pa 9.14 kPa 24.5 Pa
PA. between . km3 and . km3
PA. −2 Pa 0.25 atm
PA. cCCl F = 1.1 × 10−11 mol dm−3 cCCl F = 2.2 × 10−11 mol dm−3 cCCl F = 8.0 ×
3 2 2 3
−13 −3 −12
10 mol dm cCCl2 F2 = 1.6 × 10 mol dm−3
1B The kinetic model
EB.(a) .
−1
EB.(a) υrms,H2 = 1.90 km s υrms,O 2 = 478 m s−1
×
EB.(a) 6.87 10−3
EB.(a) 1832 m s−1
EB.(a) υmp = 333 m s−1 υmean = 376 m s−1 υrel = 531 m s−1
EB.(a) 1.7 10×10 s−1
EB.(a) 475 m s−1 . nm 8.10 × 109 s−1
EB.(a) . Pa
EB.(a) 1.4 × 10−6 m = . µm
PB. υmean, new ≈ 0.493 υmean
PB. 3.02 × 10−3 for n = 3 4.89 × 10−6 for n = 4
−1
4
PB. 1.12 × 10 m s 5.04 × 103 m s−1
Manual to
Accompany Atkins’
Physical Chemistry
ELEVENTH EDITION
Peter Bolgar
Haydn Lloyd
Aimee North
Vladimiras Oleinikovas
Stephanie Smith
and
James Keeler
Department of Chemistry
University of Cambridge
UK
Numerical solutions to the problems
compiled by Jack Entwistle
Selwyn College and the Department of Chemistry
University of Cambridge
,Preface
This document is a compilation of the numerical solutions to the (a) Exercises and the odd-
numbered Discussion questions and Problems from the th edition of Atkins’ Physical
Chemistry. Where a problem requests the derivation of a result or expression, and provided
that expression is not too complex, we have also included such results.
Errors and omissions
In such a complex undertaking some errors will no doubt have crept in, despite the authors’
best eorts. Readers who identify any errors or omissions are invited to pass them on to us by
email to .
Jack Entwistle
James Keeler
Cambridge, August
, 1
1 The properties of gases
1A The perfect gas
EA.(a) Torr . atm EA.(a) no . atm
EA.(a) . bar . atm EA.(a) 30 lb
in−2.
EA.(a) . bar 4.27 105 Pa
EA.(a) S8. ×
EA.(a) . kg
EA.(a) xO2 = 0.240 xN2 = 0.760 pO2 = 0.237 bar pN2 = 0.750 bar xN2 = 0.780
xO2 = 0.210 pN2 = 0.770 bar pO2 = 0.207 bar
EA.(a) . kg mol−1
EA.(a) θ = −273 ○C
EA.(a) xH2 = 2 3
xN2 = 31 pH2 = 2.0×105 Pa pN2 = 1.0×105 Pa ptot = 3.0×105 Pa
PA. 1.15 105×Pa . J K−1 mol−1 PA.
0.082062 atm dm3 mol−1 K−1 PA. p
= ρRT M . g mol−1 PA. 24.5
Pa 9.14 kPa 24.5 Pa
PA. between . km3 and . km3
PA. −2 Pa 0.25 atm
PA. cCCl F = 1.1 × 10−11 mol dm−3 cCCl F = 2.2 × 10−11 mol dm−3 cCCl F = 8.0 ×
3 2 2 3
−13 −3 −12
10 mol dm cCCl2 F2 = 1.6 × 10 mol dm−3
1B The kinetic model
EB.(a) .
−1
EB.(a) υrms,H2 = 1.90 km s υrms,O 2 = 478 m s−1
×
EB.(a) 6.87 10−3
EB.(a) 1832 m s−1
EB.(a) υmp = 333 m s−1 υmean = 376 m s−1 υrel = 531 m s−1
EB.(a) 1.7 10×10 s−1
EB.(a) 475 m s−1 . nm 8.10 × 109 s−1
EB.(a) . Pa
EB.(a) 1.4 × 10−6 m = . µm
PB. υmean, new ≈ 0.493 υmean
PB. 3.02 × 10−3 for n = 3 4.89 × 10−6 for n = 4
−1
4
PB. 1.12 × 10 m s 5.04 × 103 m s−1
