Summary Gauss's Law and Electric Flux Physics Notes and Practice Problems

Gauss's Laur * Area vector for surface is perpendicular to the surface
itself
.

·




Apply what we know about electric flux

Flux is the flow or something across an area

Field lines that 50
go into surface give
·




outside0

given any general distribution of charge ,
we surround it with an
imaginary
surface that encloses the charge.
↳ then to look at points on this surface order to find the total flux through the
going
in


surface

Gauss's law
gives us a relationship between the field at all points on the surface & the total

charge enclosed within the surface




Flux through a surface :




· 2



:E F .




The net electric flux is directly proportional to the net amount of
charge enclosed within the

surface & independent of the size of the closed surface.

if there is no in the surface flux
·




charge or the net charge = O , there will be no .




E-Cd
YTV2
Y

↳ alenc
200 = 1

E 19/v2
= Electric Flux
constant so ESdA can take E outside of the integral N .
m2/C


EA 191
=
CHE :
4/a inside E =

K
K
= EG
outside
#E) a : 9inside E

inside
=
E


charges create electric fields
Flux Flow of electric field lines
through an are a
=