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NURS 6501 ADVANCED PATHOPHYSIOLOGY MIDTERM EXAM 2026/2027 | All 100 Questions with Correct Answers | Latest Version | Pass Guaranteed - A+ Graded

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Pass the NURS 6501 Advanced Pathophysiology Midterm Exam on your first attempt with this complete 2026/2027 guide featuring all 100 questions with correct answers. This A+ Graded resource contains the latest version covering all key topics including cellular adaptation and injury, inflammation and immunity, genetics and genomics, fluid and electrolyte balance, acid-base disorders, and advanced pathophysiology across all body systems including cardiovascular, respiratory, renal, endocrine, gastrointestinal, neurological, and musculoskeletal systems. Each answer is accurate and aligned with current Walden University course objectives. With our Pass Guarantee, you can confidently ace your midterm exam. Download your complete NURS 6501 Advanced Pathophysiology Midterm Exam instantly!

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NURS 6501 ADVANCED PATHOPHYSIOLOGY MIDTERM
EXAM 2026/2027 | All 100 Questions with Correct Answers |
Latest Version | Pass Guaranteed - A+ Graded


Section 1: Cellular Adaptation, Injury & Death (Q1-12)

1. A 28-year-old bodybuilder has significantly enlarged skeletal muscle fibers. This
cellular adaptation is best classified as:
A. Hyperplasia
B. Hypertrophy [CORRECT]
C. Metaplasia
D. Dysplasia

Rationale: Hypertrophy is an increase in cell size causing tissue enlargement, as seen in
exercised muscle. Hyperplasia is increased cell number, metaplasia is a reversible
change from one differentiated cell type to another, and dysplasia is disordered,
pre-neoplastic growth.
Correct Answer: B

2. A patient with a fractured leg immobilized in a cast for 8 weeks demonstrates
decreased muscle mass. This is an example of:
A. Hypertrophy
B. Hyperplasia
C. Atrophy [CORRECT]
D. Metaplasia

Rationale: Atrophy is a decrease in cell size due to decreased workload, disuse, or
denervation. Hypertrophy and hyperplasia involve growth, and metaplasia involves cell
type transformation, not size reduction.
Correct Answer: C

3. A chronic smoker develops a transformation of normal pseudostratified ciliated
columnar epithelium to stratified squamous epithelium in the bronchi. This reversible
change is:

,A. Dysplasia
B. Anaplasia
C. Metaplasia [CORRECT]
D. Hyperplasia

Rationale: Metaplasia is the reversible replacement of one differentiated cell type with
another, often in response to chronic irritation. Dysplasia is disordered growth,
anaplasia is loss of differentiation (malignant), and hyperplasia is increased cell
number.
Correct Answer: C

4. A Pap smear reveals disordered epithelial growth with loss of normal maturation and
nuclear hyperchromasia. This is most consistent with:
A. Metaplasia
B. Dysplasia [CORRECT]
C. Hypertrophy
D. Hyperplasia

Rationale: Dysplasia is characterized by disordered, pre-neoplastic cellular development
with nuclear atypia. Metaplasia is a benign cell type switch, hypertrophy is increased
cell size, and hyperplasia is increased cell number without atypia.
Correct Answer: B

5. The most common mechanism of cellular injury resulting from myocardial infarction
is:
A. Free radical generation
B. Hypoxia leading to ATP depletion and cellular swelling [CORRECT]
C. Chemical toxicity
D. Apoptosis

Rationale: Myocardial infarction causes ischemic hypoxia, leading to ATP depletion,
Na⁺-K⁺ pump failure, cellular swelling, and necrosis. While free radicals and apoptosis
may occur, hypoxia is the primary mechanism.
Correct Answer: B

6. During reperfusion of ischemic tissue, oxygen-derived free radicals cause injury
primarily by:
A. Stimulating protein synthesis

,B. Damaging lipids, proteins, and DNA through oxidative stress [CORRECT]
C. Increasing ATP production
D. Promoting cell membrane repair

Rationale: Reperfusion generates free radicals that attack cellular components via
oxidative stress. Free radicals do not stimulate synthesis, increase ATP, or promote
repair—they cause destructive chain reactions.
Correct Answer: B

7. A pathologist observes cell shrinkage, chromatin condensation, and formation of
apoptotic bodies without inflammation. This pattern is characteristic of:
A. Coagulative necrosis
B. Liquefactive necrosis
C. Apoptosis [CORRECT]
D. Caseous necrosis

Rationale: Apoptosis is programmed cell death with cell shrinkage, chromatin
condensation, and apoptotic body formation without inflammation. Necrosis patterns
involve cell swelling, membrane rupture, and inflammatory responses.
Correct Answer: C

8. A patient who suffered a myocardial infarction 3 days ago has necrotic myocardial
tissue that preserves cellular outlines but has lost nuclei. This is:
A. Liquefactive necrosis
B. Coagulative necrosis [CORRECT]
C. Caseous necrosis
D. Fat necrosis

Rationale: Coagulative necrosis (typical of ischemia in solid organs except brain)
preserves tissue architecture temporarily while nuclei are lost. Liquefactive occurs in
brain/abscesses, caseous in TB, and fat necrosis in pancreatitis/trauma.
Correct Answer: B

9. A patient with a brain abscess shows necrotic tissue that has liquefied into pus. This
type of necrosis is:
A. Coagulative necrosis
B. Liquefactive necrosis [CORRECT]
C. Caseous necrosis

, D. Gangrenous necrosis

Rationale: Liquefactive necrosis occurs in the brain and abscesses due to enzymatic
digestion by leukocytes. Coagulative preserves architecture, caseous is cheese-like
(TB), and gangrene refers to tissue death with or without infection.
Correct Answer: B

10. A patient with tuberculosis has necrotic tissue that appears soft, white, and
cheese-like on gross examination. This is:
A. Coagulative necrosis
B. Liquefactive necrosis
C. Caseous necrosis [CORRECT]
D. Fat necrosis

Rationale: Caseous necrosis is characteristic of TB, with amorphous, granular,
cheese-like debris. Coagulative preserves architecture, liquefactive is
enzymatic/purulent, and fat necrosis involves adipose tissue saponification.
Correct Answer: C

11. A patient with acute pancreatitis develops chalky white deposits in peripancreatic
fat. This represents:
A. Coagulative necrosis
B. Fat necrosis [CORRECT]
C. Caseous necrosis
D. Apoptosis

Rationale: Pancreatic lipase release causes fat necrosis with fatty acid release and
calcium soap formation (saponification). Coagulative and caseous necrosis do not
involve adipose tissue specifically, and apoptosis is programmed cell death.
Correct Answer: B

12. A patient with peripheral vascular disease has dry, shrunken, blackened toes. This is
consistent with:
A. Wet gangrene
B. Dry gangrene [CORRECT]
C. Gas gangrene
D. Liquefactive necrosis

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Publié le
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